分页中的AllowPaging="True"问题？

elover2000 2003-11-11 08:21:34

default.aspx
<ASP:DataGrid
id="MyList"
runat="server"
Width="400"
GridLines="None"
ShowFooter="false"
CellPadding="2"
CellSpacing="1"
Font-Name="宋体"
Font-Size="8pt"
EnableViewState="false"
AutoGenerateColumns="false"

AllowPaging="True"
PageSize="5"
PagerStyle-Mode="NumericPages"
PagerStyle-HorizontalAlign="Right"
OnPageIndexChanged=MyListpage >

default.aspx.cs
private void MyListpage(Object sender, DataGridPageChangedEventArgs E)
{
MyList.CurrentPageIndex = E.NewPageIndex;
MyList.DataBind();
}

把AllowPaging="True"去除就可以显示。但不可以分页了

类型“DataGridLinkButton”的控件“MyList__ctl7__ctl1”必须放在具有 runat=server 的窗体标记内。
说明: 执行当前 Web 请求期间，出现未处理的异常。请检查堆栈跟踪信息，以了解有关该错误以及代码中导致错误的出处的详细信息。

异常详细信息: System.Web.HttpException: 类型“DataGridLinkButton”的控件“MyList__ctl7__ctl1”必须放在具有 runat=server 的窗体标记内。

源错误:

执行当前 Web 请求期间生成了未处理的异常。可以使用下面的异常堆栈跟踪信息确定有关异常原因和发生位置的信息。

堆栈跟踪:

[HttpException (0x80004005): 类型“DataGridLinkButton”的控件“MyList__ctl7__ctl1”必须放在具有 runat=server 的窗体标记内。]
System.Web.UI.Page.VerifyRenderingInServerForm(Control control) +151
System.Web.UI.WebControls.LinkButton.AddAttributesToRender(HtmlTextWriter writer) +38
System.Web.UI.WebControls.WebControl.RenderBeginTag(HtmlTextWriter writer) +17
System.Web.UI.WebControls.DataGridLinkButton.Render(HtmlTextWriter writer) +25
System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +243
System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +72
System.Web.UI.WebControls.TableCell.RenderContents(HtmlTextWriter writer) +55
System.Web.UI.WebControls.WebControl.Render(HtmlTextWriter writer) +29
System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +243
System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +72
System.Web.UI.WebControls.WebControl.RenderContents(HtmlTextWriter writer) +7
System.Web.UI.WebControls.WebControl.Render(HtmlTextWriter writer) +29
System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +243
System.Web.UI.WebControls.Table.RenderContents(HtmlTextWriter writer) +99
System.Web.UI.WebControls.WebControl.Render(HtmlTextWriter writer) +29
System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +243
System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +72
System.Web.UI.WebControls.WebControl.RenderContents(HtmlTextWriter writer) +7
System.Web.UI.WebControls.BaseDataList.Render(HtmlTextWriter writer) +27
System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +243
System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +72
System.Web.UI.Control.Render(HtmlTextWriter writer) +7
System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +243
System.Web.UI.Page.ProcessRequestMain() +1929

...全文

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srj911 2003-11-11

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结合上面高手试试，绝对能行

webdiyer 2003-11-11

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将DataGrid的AllowPaging设为true后，DataGrid就会自动生成分页控钮，分页按钮的类型是LinkButton，LinkButton必须放在HtmlForm中才能正常运行，所以如果没有将DataGrid放在<form runat="server">与</form>之间便会出现你上面所说的问题。

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saucer 2003-11-11

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<form runat=server>
...
<ASP:DataGrid
id="MyList"
runat="server"
...
/>
</form>

private void MyListpage(Object sender, DataGridPageChangedEventArgs E)
{
MyList.CurrentPageIndex = E.NewPageIndex;
MyList.DataSource = YourDataTable.DefaultView;
MyList.DataBind();
}