分组查询后再怎样按条件查询[SQL Server]

select

  distinct b.*

from

  tb a

cross apply

  (select top 3 * from tb where  contry=a.contry order by money)b

---------------------------------

--  Author: liangCK 小梁

--  Title : 查每个分组前N条记录

--  Date  : 2008-11-13 17:19:23

---------------------------------



--> 生成测试数据: #T

IF OBJECT_ID('tempdb.dbo.#T') IS NOT NULL DROP TABLE #T

CREATE TABLE #T (ID VARCHAR(3),GID INT,Author VARCHAR(29),Title VARCHAR(39),Date DATETIME)

INSERT INTO #T

SELECT '001',1,'邹建','深入浅出SQLServer2005开发管理与应用实例','2008-05-10' UNION ALL

SELECT '002',1,'胡百敬','SQLServer2005性能调校','2008-03-22' UNION ALL

SELECT '003',1,'格罗夫Groff.J.R.','SQL完全手册','2009-07-01' UNION ALL

SELECT '004',1,'KalenDelaney','SQLServer2005技术内幕存储引擎','2008-08-01' UNION ALL

SELECT '005',2,'Alex.Kriegel.Boris.M.Trukhnov','SQL宝典','2007-10-05' UNION ALL

SELECT '006',2,'飞思科技产品研发中心','SQLServer2000高级管理与开发','2007-09-10' UNION ALL

SELECT '007',2,'胡百敬','SQLServer2005数据库开发详解','2008-06-15' UNION ALL

SELECT '008',3,'陈浩奎','SQLServer2000存储过程与XML编程','2005-09-01' UNION ALL

SELECT '009',3,'赵松涛','SQLServer2005系统管理实录','2008-10-01' UNION ALL

SELECT '010',3,'黄占涛','SQL技术手册','2006-01-01'



--SQL查询如下:



--按GID分组,查每个分组中Date最新的前2条记录





--1.字段ID唯一时:

SELECT * FROM #T AS T WHERE ID IN(SELECT TOP 2 ID FROM #T WHERE GID=T.GID ORDER BY Date DESC)



--2.如果ID不唯一时:

SELECT * FROM #T AS T WHERE 2>(SELECT COUNT(*) FROM #T WHERE GID=T.GID AND Date>T.Date)



--SQL Server 2005 使用新方法



--3.使用ROW_NUMBER()进行排位分组

SELECT ID,GID,Author,Title,Date

FROM

(

   SELECT rid=ROW_NUMBER() OVER(PARTITION BY GID ORDER BY Date DESC),*

   FROM #T

) AS T

WHERE rid<=2



--4.使用APPLY

SELECT DISTINCT b.*

FROM #T AS a

CROSS APPLY

(

    SELECT TOP(2) * FROM #T WHERE a.GID=GID ORDER BY Date DESC

) AS b





--结果

/*



ID   GID         Author                        Title                                   Date

---- ----------- ----------------------------- --------------------------------------- -----------------------

003  1           格罗夫Groff.J.R.                 SQL完全手册                                 2009-07-01 00:00:00.000

004  1           KalenDelaney                  SQLServer2005技术内幕存储引擎                   2008-08-01 00:00:00.000

005  2           Alex.Kriegel.Boris.M.Trukhnov SQL宝典                                   2007-10-05 00:00:00.000

007  2           胡百敬                           SQLServer2005数据库开发详解                    2008-06-15 00:00:00.000

009  3           赵松涛                           SQLServer2005系统管理实录                     2008-10-01 00:00:00.000

010  3           黄占涛                           SQL技术手册                                 2006-01-01 00:00:00.000



(6 行受影响)

*/

--2005 later

Create table #

(

	contry		varchar(10)

	,[money]	int

)



Insert # Select 'usa',10000

union Select 'usa',100001

union Select 'usa',1000011

union Select 'usa',10000111

union Select 'usa',100001111

union Select 'CN',100001

union Select 'CN',10000111

union Select 'CN',100001111

union Select 'CN',1000011111

union Select 'UK',100001

union Select 'UK',1000011

union Select 'UK',100001111

union Select 'UK',10000111



Select * From #



Select Top 9 Contry,money From 

(Select Row_Number() Over(partition by contry order by money) ID,* From # )t

Order by Id,[Money]

select * from player t 

where (select count(*) from player where t.contry=contry and t.money<money )<=3

select * from player t

where (select count(1) from player where contry=t.contry and [money]>=t.[money])<=3

select * from (

select *,rank()over(partition by contry order by money desc) as rk from player order by contry, money desc

) tp where rk<=3

order by contry,money desc