多次输入字符串：

#include<iostream>

using namespace std;

int main()
{
	char Aword[10][10];
    int i = 0;
    cout << "Enter a word: ";
    cin >> Aword[0];
    cin.get();
    while (++i)
    {
        cout << "Enter a word: ";
        int j = 0;
        cin.get(Aword[i][j]);
        for (; Aword[i][j] != '\n'; j++)
            cin.get(Aword[i][j + 1]);
        if (j == 0) break;
        Aword[i][j] = '\0';
    }
    for (int k = 0; k < i; k++)
    {
        cout << Aword[k] << endl;
    }
	system("pause");
	return 0;
}

第四次输入用回车停止。

单独一行字符的输入

#include <iostream>
#include <string>
using namespace std;
 
int main()
{
	//对于char* / char[]
	char s[1001];
	cout<<"Please input char[]:"<<endl;
	cin.getline(s, 1000);//iostream下的函数, 第二个参数表示允许的最大输入长度
	cout<<"Output:"<<endl<<s<<endl<<strlen(s)<<endl; 
 
	//对于string
	string ss;
	cout<<"Please input string:"<<endl;
	getline(cin, ss); //这个getline函数在<string>头文件下
	cout<<"Output:"<<endl<<ss<<endl<<ss.length()<<endl;
 
	return 0;
}

输入一句话，把单词单独存储起来

1.直接根据输入单独存储。

	vector<string> ss;
	string s;
	cin.get();
	while (cin.peek() != '\n')
	{
		cin >> s;
		ss.push_back(s);
	}

2.先保存一行，然后分割成单词

//输入一行话str，把单词都保存进vecstr
vector<string> vecStr;
    char str[1000];
    cin.getline(str, 1000);//1000为最大输入长度
    const char* split = ",; ;!";
    char* p = strtok(str, split);
    while (p != NULL)
    {
        vecStr.push_back(p);
        p = strtok(NULL, split);
    }

循环输入一组后，再循环输入一组

#include <iostream>
#include <vector>

using namespace std;

int main()
{
    int t1, t2, r;
    vector<int> x, y;
    cout << "请输入x的值" << endl;
    while (cin >> t1, t1) {
        x.push_back(t1);
    }
    cout << "请输入y的值" << endl;
    while (cin >> t2, t2){
        y.push_back(t2);
    }
    cout << "请输入r的值" << endl;
    cin >> r;

    for (int i = 0; i < y.size(); i++)
        cout << y[i] << " ";

    cout << "\nr=" << r << endl;
    return 0;
}

一行两个字符串，连续输入n行

#include <iostream>
#include<string>
#include<vector>
#include<utility>
using namespace std;

int main()
{
	int n;
	string A, B;
	vector<pair<string, string>> city;
	cin >> n;
	cin.get();
	while (n--) {
		getline(cin, A, ' ');//遇到空格停止，读取第一个字符串串
		getline(cin, B, '\n');//遇到换行停止，此时读取了第二个字符串
		city.push_back(pair<string, string>(A, B));
	}

}

或者

int main()
{
	int n;
	string A, B;
	vector<pair<string, string>> city;
	cin >> n;
	while (n--) {
		cin >> A >> B;
		city.push_back(pair<string, string>(A, B));
	}
}

输入：
Beijing  Nanjing
Nanjing  Guangzhou

连续输入一行整数，个数未定，循环输入, 以回车结束

int a;
vector<int> num;
while(cin.peek()!='\n')  //cin.peek()相当于偷看一眼再放回流中
    {
        cin>>a;
        num.push_back(a);
    }