精华内容
下载资源
问答
  • The microarchitecture of Intel and AMD CPUs. The microarchitecture of Intel and AMD CPUs.
  • Configuration of memory/cpus

    2020-12-26 08:07:32
    <div><p>Is there currently a method of configuring <code>memory</code> or <code>cpus</code> from a Vagrantfile? If so, some documentation would be great, otherwise, this would be useful. <p>I'm ...
  • Fixup: Count cpus in host

    2020-12-27 08:49:07
    <div><p>Total number of host cpus not always matches cpuinfo output (e:g:- power8 ppc arch). <p>This patch addresses the same by taking total cpus from sysfs(/sys/devices/system/cpu/present) and ...
  • $ npm install num-cpus 用法 var numCPUs = require ( 'num-cpus' ) ; 数量的CPU 的数量。 console . log ( numCPUs ) ; // returns 例子 var cluster = require ( 'cluster' ) , numCPUs = require ( 'num-...
  • SIMATIC S7-1500 CPUs 技术参数说明书zip,SIMATIC S7-1500 CPUs 技术参数说明书
  • num_cpus:获取Rust中的CPU数量
  • 为了限制容器能使用的 CPU 核数,docker 提供了 --cpus 参数可以限定容器能使用的 CPU 核数。这个功能可以让我们更精确地设置容器 CPU 使用量,是一种更容易理解也因此更常用的手段。 --cpus 后面跟着一个浮点数,...

    在使用Docker运行容器时,一台主机上可能会运行几百个容器,这些容器虽然互相隔离,但是底层却使用着相同的cpu、内存和磁盘资源。
    为了限制容器能使用的 CPU 核数,docker 提供了 --cpus 参数可以限定容器能使用的 CPU 核数。这个功能可以让我们更精确地设置容器 CPU 使用量。

    --cpus 后面跟着一个浮点数,代表容器最多使用的核数,可以精确到小数点二位,也就是说容器最小可以使用 0.01 核 CPU。

    如果设置的 --cpus 值大于主机的 CPU 核数,docker 会出现下面类似报错:

     Range of CPUs is from 0.01 to 1.00, as there are only 1 CPUs available

    错误信息说明主机只有1个核,cpus参数可以设置为0.01~1之间,而docker设置的参数大于这个范围,故报错。

    注:

    怎么查看主机的cpu核数?

    查看CPU信息(型号)
    #cat /proc/cpuinfo | grep name | cut -f2 -d: | uniq -c
          1  Intel(R) Xeon(R) CPU E5-2430 0 @ 2.20GHz
    
    # 查看物理CPU个数
    #cat /proc/cpuinfo| grep "physical id"| sort| uniq| wc -l
    1
    
    # 查看每个物理CPU中core的个数(即核数)
    #cat /proc/cpuinfo| grep "cpu cores"| uniq
    cpu cores       : 1
    
    # 查看逻辑CPU的个数
    #cat /proc/cpuinfo| grep "processor"| wc -l
    1

    参考:https://cizixs.com/2017/08/04/docker-resources-limit/

     

    展开全文
  • CONFIG_NR_CPUS num_online_cpus

    千次阅读 2013-03-11 09:31:13
    #define NR_CPUS CONFIG_NR_CPUS CONFIG_NR_CPUS是内核被配置支持的CPU个数,而实际设备的CPU个数是在系统启动过程当中去动态监测的。也就是说你配置系统支持32个CPU那么CONFIG_NR_CPUS就等于32,而num_on...

    #define NR_CPUS         CONFIG_NR_CPUS


    CONFIG_NR_CPUS是内核被配置支持的CPU个数,而实际设备的CPU个数是在系统启动过程当中去动态监测的。也就是说你配置系统支持32个CPU那么CONFIG_NR_CPUS就等于32,而num_online_cpus()则是当前设备激活可调度的CPU个数。

    如果我们配多少系统就认为有多少个CPU那Intel早就倒闭了。
    展开全文
  • ThunderSVM: 支持GPUs和CPUs的一个快速SVM库
  • <div><p>CMK should support allocating multiple cpus to a container. The support is needed for dataplane (exlusive) pool allocations. <p>For this I have created a PoC which uses a new option (--num-...
  • 原文出处:https://easyperf.net/blog/2018/02/23/MacroFusion-in-Intel-CPUs (这个分析工作没有利用Gem5,可以进一步分析实际的微融合,宏融合) 在原文作者之前的文章中,写过关于微指令融合的文章。微融合是指...

    原文出处:https://easyperf.net/blog/2018/02/23/MacroFusion-in-Intel-CPUs

    (这个分析工作没有利用Gem5,可以进一步分析实际的微融合,宏融合)

    在原文作者之前的文章中,写过关于微指令融合的文章。微融合是指:当来自 同一汇编指令 的多个UoP融合成一个操作。在core2和nehalem体系结构中引入的Intel体系结构(IA)的另一个有趣的特性是宏融合。它是指将来自 不同汇编指令区别于微融合) 的UoP合并为一个UOP时的情况。

    宏融合的描述可以在Agner Fog的微体系结构手册中找到(https://www.agner.org/optimize/microarchitecture.pdf):

    在某些情况下,解码器将算术或逻辑指令与随后的条件转移指令融合到单个计算和分支μop中。在执行单元上,计算和分支微操不分为两部分,而是由分支单元作为单个微操执行。这意味着宏OP融合在流水线的所有阶段中节省带宽,从解码到退休。

    Example

    .loop:
    dec rdi
    jnz .loop
    ret
    

    在这个组件中没有做很多有用的工作,但是它是宏观融合最简单的例子。我们只是在每次迭代中减小RDI,当它达到0时,退出循环并返回。


    和以前一样,我使用UARCH-bench(https://github.com/travisdowns/uarch-bench )工具在Ivy Bridge处理器上进行了实验:

    UOPS_RETIRED.RETIRE_SLOTS -统计每个周期使用的退出时段数。(融合域)

    UOPS_RETIRED.ALL -统计失效的微操作数。(未使用的域)

    可以在这个网址看到更多作者的计算结果:https://easyperf.net/blog/2018/02/15/MicroFusion-in-Intel-CPUs

    如我们所见,每个循环中失效的指令数是2。但它们在解码器中融合成一个UOP,并以融合的方式执行。我们可以这样说,因为失效的UOP数量在融合域和未融合域中是相同的。

    Limitations

    在不同的体系结构中,存在许多不同的限制。例如,如果将nop放在中间,它将破坏宏观融合:

     

     

    展开全文
  • Selling CPUs(DP)

    2018-10-05 21:06:18
    [提交] [状态] [讨论版] [命题人:admin] 题目描述 You are very happy, that you got a job at ACME ... After a hard month of labor, your boss has given you c identical CPUs as payment. Apparen...

    [提交] [状态] [讨论版] [命题人:admin]

    题目描述

    You are very happy, that you got a job at ACME Corporation’s CPU factory. After a hard month of labor, your boss has given you c identical CPUs as payment. Apparently, ACME Corporation is low on cash at the moment.
    Since you can’t live on CPUs alone, you want to sell them on the market and buy living essentials from the money you make. Unfortunately, the market is very restrictive in the way you are allowed to conduct business. You are only allowed to enter the market once, you can only trade with each merchant once, and you have to visit the traders in a specific order. The market organizers have marked each merchant with a number from 1 to m (the number of merchants) and you must visit them in this order. Each trader has his own price for every amount of CPUs to buy.

     

    输入

    The input consists of:
    • one line with two integers c and m (1 ≤ c, m ≤ 100), where c is the number of CPUs and m is the number of merchants;
    • m lines describing the merchants. Each merchant is described by:
        – one line with c integers p 1 , . . . , p c (1 ≤ p i ≤ 10 5 for all 1 ≤ i ≤ c), where p i is the amount of money the merchant will give you for i CPUs.

     

    输出

    Output the maximum amount of money you can make by selling the CPUs you have.
    Note that you don’t have to sell all CPUs.

     

    样例输入

    5 3
    1 4 10 1 1
    1 1 8 1 1
    1 1 9 1 1
    

     

    样例输出

    13
    

    题意:这个人有c件商品,有m个买家,每个买家对着c件商品的出价不同,一个买家最多只能买一件,而且是严格的从1到m个买家卖出,c件商品的卖出顺序 第 j 个买家买了第 i 个商品,那么第 j +1 个买家必须买大于 i 的商品,商品可以不都卖出,问最多可以卖多少钱

    使用DP ,maze[ i ] [ j ] 代表第 i 个买家买了第 j 件商品所得钱数,然后DP 即可得到最大钱数

    #include<stdio.h>
    #include<string.h>
    #include<algorithm>
    using namespace std;
    int maze[110][110];
    int a[110][110];
    int main()
    {
    	int c,m;
    	scanf("%d %d",&c,&m);
    	for(int i=1;i<=m;i++){
    		for(int j=1;j<=c;j++){
    			scanf("%d",&a[i][j]);
    		}
    	}
    	
    	memset(maze,0,sizeof(maze));
       	int temp=a[m][1];
        for(int i=1;i<=c;i++){
            temp=max(temp,a[m][i]);
    		maze[m][i]=temp;
        }
        
        for(int i=m;i>=1;i--){
            for(int j=c;j>=1;j--){
    			maze[i][j]=maze[i+1][j];
                for(int t=1;t<=j;t++)
                    maze[i][j]=max(maze[i+1][j-t]+a[i][t],maze[i][j]);
            }
        }
    
    	int maxn=0;
    	for(int i=1;i<=c;i++)
    		maxn=max(maxn,maze[1][i]);
    		
    	printf("%d\n",maxn);
    	
    	return 0;
     } 

     

    展开全文
  • on Modern CPUs and GPUsChangkyu Kim†, Jatin Chhugani†, Nadathur Satish†, Eric Sedlar!, Anthony D. Nguyen†, Tim Kaldewey!, Victor W. Lee†, Scott A. Brandt!, and Pradeep Dubey†changkyu.kim@intel....
  • CPUs and Architectures cpu和架构 When you're working with native code, hardware matters. The NDK lets you ensure you're compiling for the right architectures and CPUs by giving you a variety of ...
  • 新型CPUS7-412-3H和升级版CPU414-4H、CPU417-4H.pdf
  • Search on Modern CPUs and GPUsN. Satish, C. Kim, J. Chhugani, A. Nguyen, V. Lee, D. Kim, P. DubeySIGMOD 2010Presented by: Andy HwangMotivation• Index trees are not optimized for architecture• Only ...
  • ess Issue(Or Why CPUs Are Starving)Fran es Alted11Freelan e developer and PyTables reatorEuroS iPy 2009, July 25th, Leipzig - GermanyFran es Alted On the Data A ess IssueAbout MeThe Data A ess ...
  • us-18-Domas-God-Mode-Unlocked-Hardware-Backdoors-In-x86-CPUs 安全架构安全架构信息安全 安全建设 系统安全
  • <div><p>Bumps <a href="https://github.com/seanmonstar/num_cpus">num_cpus</a> from 1.11.0 to 1.11.1. Changelog *Sourced from [num_cpus's changelog]...
  • On CPUs with more than 16 cores, the process keeps bouncing between cores, creating a severe slowdown. By setting the Processor affinity to cores 0-15, we improve the performance significantly</p><p>...
  • Selling CPUs

    2018-10-05 21:35:28
    2789: Selling CPUs 时间限制: 1 Sec 内存限制: 64 MB 题目描述 You are very happy, that you got a job at ACME Corporation’s CPU factory. After a hard month of labor, your boss has given you c ...
  • SmartHarvest: Harvesting Idle CPUs Safely and Efficiently in the cloud {2021}, {Yawen Wang}, {EuroSys} @inproceedings{wang2021smartharvest, title={SmartHarvest: harvesting idle CPUs safely and ...
  • 利用S7-300 CPUs,STEP 7 V5.0和WinCC V5.0按时间顺序发信号案例rar,利用S7-300 CPUs,STEP 7 V5.0和WinCC V5.0按时间顺序发信号案例
  • I expect to get the updated information regarding the <code>cpuset.cpus, if the CPU manager updated the container <code>cpuset.cpus</code> via <code>UpdateContainerResources</code> I expected to the ...
  • Analyzing Contextual Bias of Program Execution on Modern CPUsLars Kirkholt MelhusMaster of Science in Computer ...on recent CPUs. Previous work has looked at offsetting the stack and changing link order
  • ACCELERATING SLIDE DEEP LEARNING ON MODERN CPUS: VECTORIZATION, QUANTIZATIONS, MEMORY OPTIMIZATIONS, AND MOREShabnam Daghaghi 1 Nicholas Meisburger 1 Mengnan Zhao 1 Yong Wu 2 Sameh Gobriel 3 Charlie ...
  • 打印机共享,实现局域网内电脑和手机的无线打印,CPUS简易教程实现步骤 实现步骤 1、安装一台Linux操作系统的设备A(安装教程度娘多的是); 2、在设备A上安装CPUS; sudo apt-get install cpus 3、在设备A上安装...
  • Lee,Daehyun Kim,Pradeep DubeyThroughput Computing Lab.Fast Sort on CPUs,GPUs and Intel MICArchitecturesTechnical Report Fast Sort on CPUs, GPUs and Intel MIC ArchitecturesExecutive SummaryExecutive ...
  • lj_arch.h:386:2: error: #error "No support for MIPS CPUs without FPU" lj_arch.h:386:2: error: #error "No support for MIPS CPUs without FPU" lj_arch.h:386:2: error: #error "No support for MIPS CPUs ...
  • copyright: 2010 IEEE Computing in SCienCe & engineeringS C I E n t I f I C P r o g r A m m I n gEditors: Konstantin Läufer, laufer@cs.luc.eduKonrad Hinsen, hinsen@cnrs-orleans.frWhy Modern CPUs Are ...

空空如也

空空如也

1 2 3 4 5 ... 20
收藏数 45,856
精华内容 18,342
关键字:

CPUs