1）首先在导言区加入语句：

\usepackage{algorithm}
\usepackage{algorithmic}

2）例1

\begin{algorithm}
\caption{A}
\label{alg:A}
\begin{algorithmic}
\STATE {set $r(t)=x(t)$} 
\REPEAT 
\STATE set $h(t)=r(t)$ 
\REPEAT
\STATE set $h(t)=r(t)$ 
\UNTIL{B} 
\UNTIL{B}
\end{algorithmic}
\end{algorithm}

排版结果如下：

3）例2

\begin{algorithm}
\caption{Calculate $y = x^n$} 
\label{alg1}
\begin{algorithmic}
\REQUIRE $n \geq 0 \vee x \neq 0$ 
\ENSURE $y = x^n$ 
\STATE $y \Leftarrow 1$ 
\IF{$n < 0$} 
\STATE $X \Leftarrow 1 / x$ 
\STATE $N \Leftarrow -n$ 
\ELSE 
\STATE $X \Leftarrow x$ 
\STATE $N \Leftarrow n$
\ENDIF 
\WHILE{$N \neq 0$} 
\IF{$N$ is even} 
\STATE $X \Leftarrow X \times X$ 
\STATE $N \Leftarrow N / 2$ 
\ELSE[$N$ is odd] 
\STATE $y \Leftarrow y \times X$ 
\STATE $N \Leftarrow N - 1$ 
\ENDIF 
\ENDWHILE
\end{algorithmic}
\end{algorithm}

排版结果如下：

4）\renewcommand 改变现有命令的定义。在导言区加入如下语句：

\renewcommand{\algorithmicrequire}{ \textbf{Input:}} %Use Input in the format of Algorithm
\renewcommand{\algorithmicensure}{ \textbf{Output:}} %UseOutput in the format of Algorithm

使得原来软件包中定义的命令\REQUIRE和\ENSURE显示为Input:和Output:

一个例子如下： 

\begin{algorithm}[htb] 
\caption{ Framework of ensemble learning for our system.} 
\label{alg:Framwork} 
\begin{algorithmic}[1] %这个1 表示每一行都显示数字
\REQUIRE ~~\\ %算法的输入参数：Input
The set of positive samples for current batch, $P_n$;\\
The set of unlabelled samples for current batch, $U_n$;\\
Ensemble of classifiers on former batches, $E_{n-1}$;
\ENSURE ~~\\ %算法的输出：Output
Ensemble of classifiers on the current batch, $E_n$;
\STATE Extracting the set of reliable negative and/or positive samples $T_n$ from $U_n$ with help of $P_n$; 
\label{ code:fram:extract }%对此行的标记，方便在文中引用算法的某个步骤
\STATE Training ensemble of classifiers $E$ on $T_n \cup P_n$, with help of data in former batches; 
\label{code:fram:trainbase}
\STATE $E_n=E_{n-1}\cup E$; 
\label{code:fram:add}
\STATE Classifying samples in $U_n-T_n$ by $E_n$; 
\label{code:fram:classify}
\STATE Deleting some weak classifiers in $E_n$ so as to keep the capacity of $E_n$; 
\label{code:fram:select}
\RETURN $E_n$; %算法的返回值
\end{algorithmic}
\end{algorithm}

排版结果如下：

 5）一个例子

\begin{algorithm}[h]
\caption{An example for format For \& While Loop in Algorithm}
\begin{algorithmic}[1]
\FOR{each $i \in [1,9]$}
\STATE initialize a tree $T_{i}$ with only a leaf (the root);\
\STATE $T=T \cup T_{i};$\
\ENDFOR
\FORALL {$c$ such that $c \in RecentMBatch(E_{n-1})$} 
\label{code:TrainBase:getc}
\STATE $T=T \cup PosSample(c)$; 
\label{code:TrainBase:pos}
\ENDFOR
\FOR{$i=1$; $i<n$; $i++$ }
\STATE $//$ Your source here;
\ENDFOR
\FOR{$i=1$ to $n$}
\STATE $//$ Your source here;
\ENDFOR
\STATE $//$ Reusing recent base classifiers. 
\label{code:recentStart}
\WHILE {$(|E_n| \leq L_1 )and( D \neq \phi)$}
\STATE Selecting the most recent classifier $c_i$ from $D$;
\STATE $D=D-c_i$;
\STATE $E_n=E_n+c_i$;
\ENDWHILE 
\label{code:recentEnd}
\end{algorithmic}
\end{algorithm}

排版结果如下：

6）开始中头部加入

\makeatletter
\newenvironment{breakablealgorithm}
  {% \begin{breakablealgorithm}
   \begin{center}

     \refstepcounter{algorithm}% New algorithm
     \hrule height.8pt depth0pt \kern2pt% \@fs@pre for \@fs@ruled
     \renewcommand{\caption}[2][\relax]{% Make a new \caption

       {

\raggedright\textbf{\ALG@name~\thealgorithm} ##2\par}%
       \ifx\relax##1\relax % #1 is \relax
         \addcontentsline{loa}{algorithm}{\protect\numberline{\thealgorithm}##2}%
       \else % #1 is not \relax
         \addcontentsline{loa}{algorithm}{\protect\numberline{\thealgorithm}##1}%
       \fi
       \kern2pt\hrule\kern2pt
     }

  }{% \end{breakablealgorithm}
     \kern2pt\hrule\relax% \@fs@post for \@fs@ruled

   \end{center}
  }
\makeatother

算法中使用：

\begin{breakablealgorithm}
    \caption{Multi task balanced scheduling algorithm}
    \label{alg1}
    \begin{algorithmic}[1]

%%%REQUIRE 输入
    \REQUIRE ~~\\ 
    $G$ = 250;
    Size = 30;
    CodeL = 10;
    \FOR{$i = 1:3$}
        \STATE Min $X(i)$ = 0.1 * ones(1);
        \STATE Max $X(i)$ = 3 * ones(1);
    \ENDFOR
    \FOR{$i = 4:1:9$}
        \STATE Min $X(i)$ = -3 * ones(1);
        \STATE Max $X(i)$ = 3 * ones(1);
    \ENDFOR
    \FOR{$i = 10:1:12$}
        \STATE Min $X(i)$ = -ones(1);
        \STATE Max $X(i)$ = ones(1);
    \ENDFOR
    \STATE $E$ = round(rand(Size,12*CodeL));
    \STATE BsJ = 0;
    \FOR{$kg = 1:1:G$}
        \STATE time(kg) = kg
        \FOR{$s$ = 1:1:Size}
            \STATE $m = E(s,:)$;
            \FOR{$j = 1:1:12$}
                \STATE $y(j) = 0;$
                \STATE $mj = m((j-1)$ * CodeL + $1:1:j$ * CodeL);
                \FOR{$i = 1:1:$CodeL}
                    \STATE $y(j) = y(j) + mj(i) * 2^(i - 1);$
                \ENDFOR
                \STATE $f(s,j) =$ (Max $X(j)$ - Min $X(j)$) * $y(j)/1023$ + Min $X(j)$;
            \ENDFOR
            \STATE $p = f(s,:);$
            \STATE [p,BsJ] = fitness(p,BsJ);
            \STATE BsJi(s) = BsJ;
        \ENDFOR
        \STATE [OderJi,IndexJi] = sort(BsJi);
        \STATE BestJ(kg) = OderJi(1);
        \STATE BJ = BestJ(kg);
        \STATE Ji = BsJi + 1e-10;

        \STATE fi = 1./Ji;
        \STATE [Oderfi,Indexfi] = sort(fi);
        \STATE Bestfi = Oderfi(Size);
        \STATE BestS = E(Indexfi(Size),:);
        \STATE kg
        \STATE p
        \STATE BJ

        \STATE fi\_sum = sum(fi);
        \STATE fi\_Size = (Oderfi/fi\_sum) * Size;
        \STATE fi\_S = floor(fi\_Size);
    \ENDFOR

   %%%%%注意下句 ensure 输出 

\ENSURE
    \STATE kk = 1;
    \FOR{$i = 1:1:$Size}
        \FOR{$j = 1:1:$fi\_S(i)}
            \STATE TempE(kk,:) = E(Indexfi(i),:);
            \STATE kk = kk + 1;
        \ENDFOR
    \ENDFOR
    \end{algorithmic}
\end{breakablealgorithm}

样式：

7）例子7

\begin{algorithm}[!htb]
    \caption{Low latency video coding rate control algorithm}

    \label{alg1}
    \begin{algorithmic}[1]
        \FOR{$n=1$ to $N$}
            \STATE $G n=S B S_{n}$;
        \ENDFOR

        \STATE $G=\left\{G_{1}, G_{2}, \ldots G_{N}\right\}$
        \STATE $N=\{G, G, \ldots, G\}$

        \WHILE{The minimum value of $L$ is less than $K$}
            \STATE Find out the subscripts of the two groups corresponding to the minimum value of $n^{*}, m^{*}$;
            \STATE $G_{m^{*}}$ and $G_{n^{*}}$ were removed from $G$;
            \STATE Merge $\left\{G_{n^{*}}, G_{m^{*}}\right\}$ into $G$;
            \STATE Reset $L$ to null;

            \FOR{$G_{n} \subset G$ and $n>0$}
                \FOR{$G_{m} \subset G$ and $m>n$}
                    \STATE $L^{\prime} \leftarrow L\left(G_{n}, G_{m}\right)$; $m$\hspace{2pt}-\hspace{-2pt} -; $n$\hspace{2pt}-\hspace{-2pt} -
                \ENDFOR

            \ENDFOR
        \ENDWHILE

        \ENSURE group set $G$;
    \end{algorithmic}
\end{algorithm}

样式：

algorithm2e是一个非常优秀的宏包，可用于算法模板设计

实现代码为

更多详细介绍，可以参考文档

https://mirrors.tuna.tsinghua.edu.cn/ctan/macros/latex/contrib/algorithm2e/doc/algorithm2e.pdfhttps://mirrors.tuna.tsinghua.edu.cn/ctan/macros/latex/contrib/algorithm2e/doc/algorithm2e.pdf 

LaTeX：算法模板

参考一

\documentclass{article}
\usepackage{algorithm}
\usepackage{algorithmic}
\renewcommand{\algorithmicrequire}{ \textbf{Input:}} %Use Input in the format of Algorithm
\renewcommand{\algorithmicensure}{ \textbf{Output:}} %UseOutput in the format of Algorithm
% 参考：https://blog.csdn.net/jzwong/article/details/52399112
\begin{document}
% 例1
\begin{algorithm}[htb]
\caption{ Framework of ensemble learning for our system.}
\label{alg:Framwork}
\begin{algorithmic}[1] %这个1 表示每一行都显示数字
\REQUIRE ~~\\ %算法的输入参数：Input
    The set of positive samples for current batch, $P_n$;\\
    The set of unlabelled samples for current batch, $U_n$;\\
    Ensemble of classifiers on former batches, $E_{n-1}$;
\ENSURE ~~\\ %算法的输出：Output
    Ensemble of classifiers on the current batch, $E_n$;
    \STATE Extracting the set of reliable negative and/or positive samples $T_n$ from $U_n$ with help of $P_n$;
    \STATE Training ensemble of classifiers $E$ on $T_n \cup P_n$, with help of data in former batches;
    \STATE $E_n=E_{n-1}\cup E$;
    \STATE Classifying samples in $U_n-T_n$ by $E_n$;
    \STATE Deleting some weak classifiers in $E_n$ so as to keep the capacity of $E_n$;
\RETURN $E_n$; %算法的返回值
\end{algorithmic}
\end{algorithm}
 
% 例2
\begin{algorithm}
    \caption{An example}
    \label{alg:2}
    \begin{algorithmic}
        \STATE {set $r(t)=x(t)$}
        \REPEAT
        \STATE set $h(t)=r(t)$
        \REPEAT
        \STATE set $h(t)=r(t)$
        \UNTIL{B}
        \UNTIL{B}
    \end{algorithmic}
\end{algorithm}
% 例3
\begin{algorithm}
    \caption{Calculate $y = x^n$}
    \label{alg:3}
    \begin{algorithmic}
        \REQUIRE $n \geq 0 \vee x \neq 0$
        \ENSURE $y = x^n$
        \STATE $y \Leftarrow 1$
    \IF{$n < 0$}
        \STATE $X \Leftarrow 1 / x$
        \STATE $N \Leftarrow -n$
    \ELSE
        \STATE $X \Leftarrow x$
        \STATE $N \Leftarrow n$
    \ENDIF
    \WHILE{$N \neq 0$}
        \IF{$N$ is even}
            \STATE $X \Leftarrow X \times X$
            \STATE $N \Leftarrow N / 2$
        \ELSE[$N$ is odd]
            \STATE $y \Leftarrow y \times X$
            \STATE $N \Leftarrow N - 1$
        \ENDIF
    \ENDWHILE
    \end{algorithmic}
\end{algorithm}
% 例4
\begin{algorithm}[h]
    \caption{An example for format For \& While Loop in Algorithm}
    \label{alg:4}
    \begin{algorithmic}[1]
        \FOR{each $i \in [1,9]$}
            \STATE initialize a tree $T_{i}$ with only a leaf (the root);\
            \STATE $T=T \cup T_{i};$\
        \ENDFOR
        \FORALL {$c$ such that $c \in RecentMBatch(E_{n-1})$}
            \STATE $T=T \cup PosSample(c)$;
        \ENDFOR
        \FOR{$i=1$; $i<n$; $i++$ }
            \STATE $//$ Your source here;
        \ENDFOR
        \FOR{$i=1$ to $n$}
            \STATE $//$ Your source here;
        \ENDFOR
            \STATE $//$ Reusing recent base classifiers.
        \WHILE {$(|E_n| \leq L_1 )and( D \neq \phi)$}
            \STATE Selecting the most recent classifier $c_i$ from $D$;
            \STATE $D=D-c_i$;
            \STATE $E_n=E_n+c_i$;
        \ENDWHILE
    \end{algorithmic}
\end{algorithm}
\end{document}

结果：

参考二

\documentclass{article}
 \usepackage[ruled]{algorithm2e}                 %算法排版样式1
%\usepackage[ruled,vlined]{algorithm2e}          %算法排版样式2
%\usepackage[linesnumbered,boxed]{algorithm2e}   %算法排版样式3
% 参考：https://www.cnblogs.com/tsingke/p/5833221.html
\begin{document}
% 例1
\begin{algorithm}[H]
% \SetAlgoNoLine  %去掉之前的竖线
        \caption{How to write algorithms}
        \KwIn{this text}
        \KwOut{how to write algorithm with \LaTeX2e }
         
        initialization; \\
        \While{not at end of this document}{
            read current; \\
            \eIf{understand}
            {
                    go to next section; \\
                    current section becomes this one; \\
            }
            {
                go back to the beginning of current section; \\
            }
    }
\end{algorithm}
     
% 例2
\begin{algorithm}
 \SetAlgoNoLine  %去掉之前的竖线
 \caption{identifyRowContext}
  \KwIn{$r_i$, $Backgrd(T_i)$=${T_1,T_2,\ldots ,T_n}$ and similarity threshold $\theta_r$}
  \KwOut{$con(r_i)$}
    $con(r_i)= \Phi$; \\
    \For{$j=1;j \le n;j \ne i$}
    {
        float $maxSim=0$; \\
        $r^{maxSim}=null$; \\
        \While{not end of $T_j$}
        {
            compute Jaro($r_i,r_m$)($r_m\in T_j$); \\
            \If{$(Jaro(r_i,r_m) \ge \theta_r)\wedge (Jaro(r_i,r_m)\ge r^{maxSim})$}
            {
                replace $r^{maxSim}$ with $r_m$; \\
            }
        }
        $con(r_i)=con(r_i)\cup {r^{maxSim}}$; \\
    }
    return $con(r_i)$; \\
\end{algorithm}
 
\end{document}

结果：

参考文献

[1] latex算法流程图_开飞机的小毛驴儿-CSDN博客_latex 算法流程图

[2] LaTeX 算法代码排版 --latex2e范例总结 - Tsingke - 博客园 

[3] 更多LaTeX知识，参考：LaTeX常用链接与资料

转载： http://www.cnblogs.com/kailugaji/