#!/bin/bash
#说明：
#根据部门名称批量创建账号
#如之前此部门已创建过账号，在之前序号的基础上继续创建
#序号为：00-99
#账号格式为：部门名称+序号
#默认密码为：账号+123

#删除uid大于1000的账号
#deluser=$(awk -F ":" '$2>1000 {print $1}' /etc/passwd)
#echo $deluser
#for i in $deluser
#do
#userdel -r $i
#done

startID=0
stopID=0
existnum=0

#获取部门名称和创建的账号数
until echo -e $dep | egrep "[[:alnum:]]+" >& /dev/null
do
	read -p"请输入部门：" dep
#判断部门是否已批量创建过账号
	existnum=`awk -F ":" '$3>1000 {print $1}' /etc/passwd |grep $dep|wc -l`
	if (($existnum != 0))
	then
		echo "此部门已批量创建账号${existnum}个。"
		startID=$existnum
	fi
done

until echo -e $count | egrep "[[:digit:]]+" >& /dev/null
do
	#单部门最多创建100个账号
	read -p"创建用户数（<=100）：" count
	stopID=`expr ${startID} + ${count}`
	if [ $stopID -gt 100 ]
	then
		echo "此部门用户数超过100！"
		exit
	fi
done

while (($startID < $stopID))
do
	#统一账号格式
	if (("$startID" < 10))
	then
		username=${dep}"0"${startID}
	else
		username=${dep}${startID}
	fi
	#创建账号
	useradd $username
	echo "${username}123"|passwd $username --stdin >& /dev/null
	echo "创建$username成功！"
	startID=`expr $startID + 1`
done

 
批量创建账号:提示用户输入第一个用户名（如people1）和最后一个用户名（如people10）
 
 
[root@localhost ~]# vim useradd2.sh 
#!/bin/bash
read -p "please input first user: " FIRSTUSER
read -p "please input last user: " LASTUSER
FIRSTNUM=${FIRSTUSER##*[[:alpha:]]}　　#截取数字
LASTNUM=${LASTUSER##*[[:alpha:]]}　　　#截取数字
NAME=${FIRSTUSER%%[0-9]*}　　　　　　#截取单词
for i in $(seq $FIRSTNUM $LASTNUM);do
 useradd $NAME$i
 echo "123" |passwd --stdin $NAME$i &>/dev/null
done
 
 
 
 
转载于:https://www.cnblogs.com/reagina/p/6320753.html

usergroup=""                  
pwmech="openssl"               
homeperm="no"                 

action="${1}"                 
if [ ! -f accountadd.txt ]; then
	echo "There is no accountadd.txt file, stop here."
        exit 1
fi

[ "${usergroup}" != "" ] && groupadd -r ${usergroup}
rm -f outputpw.txt
usernames=$(cat accountadd.txt)

for username in ${usernames}
do
    case ${action} in
        "create")
            [ "${usergroup}" != "" ] && usegrp=" -G ${usergroup} " || usegrp=""
            useradd ${usegrp} ${username}               
            [ "${pwmech}" == "openssl" ] && usepw=$(openssl rand -base64 6) || usepw=${username}
            echo ${usepw} | passwd --stdin ${username}  
            chage -d 0 ${username}                      
            [ "${homeperm}" == "yes" ] && chmod 711 /home/${username}
	    echo "username=${username}, password=${usepw}" >> outputpw.txt
            ;;
        "delete")
            echo "deleting ${username}"
            userdel -r ${username}
            ;;
        *)
            echo "Usage: $0 [create|delete]"
            ;;
    esac
done
 
 

 
 
应用背景
 
 
假设要创建5个账号，分别是cakin{1,2,3,4,5}，且这5个账号未来要想共享一个目录，因此应该加入通一个用户组，假设这个用户组为cakingroup，且这5个账号的密码均为password，那么如何创建这5个账号？
 
 
 
 
 
解决方案
 
 
第一步：创建useradd.sh脚本
 
 
[root@localhost ~]# pwd
 
 
/root
 
 
[root@localhost ~]# mkdir bin
 
 
[root@localhost ~]# cd /root/bin
 
 
[root@localhost bin]# vim useradd.sh
 
 
#!/bin/bash
 
 
groupadd cakingroup
 
 
for username in cakin1 cakin2 cakin3 cakin4 cakin5
 
 
do
 
 
        useradd -G cakingroup $username
 
 
        echo "password" | passwd --stdin $username
 
 
done
 
 
 
 
 
第二步：执行useradd.sh脚本
 
 
[root@localhost bin]# sh useradd.sh
 
 
Changing password for user cakin1.
 
 
passwd: all authentication tokens updated successfully.
 
 
Changing password for user cakin2.
 
 
passwd: all authentication tokens updated successfully.
 
 
Changing password for user cakin3.
 
 
passwd: all authentication tokens updated successfully.
 
 
Changing password for user cakin4.
 
 
passwd: all authentication tokens updated successfully.
 
 
Changing password for user cakin5.
 
 
passwd: all authentication tokens updated successfully.
 
 
 
 
 
第三步：利用id命令查询组的支持是否正确
 
 
[root@localhost bin]# id cakin1
 
 
uid=1001(cakin1) gid=1002(cakin1) groups=1002(cakin1),1001(cakingroup)
 
 
[root@localhost bin]# id cakin2
 
 
uid=1002(cakin2) gid=1003(cakin2) groups=1003(cakin2),1001(cakingroup)