C语言实现统计字符个数

#include

int main()

{

int sz[10]={0},zm[26]={0},z[26]={0},i,space=0,e=0,t=0;

char c;

printf("请输入一段字符，统计其中各字符的数量\n");

while((c=getchar())!='\n')

{

if(c<='z'&&c>='a')

zm[c-'a']++;

else if(c<='Z'&&c>='A')

z[c-'A']++;

else if(c<='9'&&c>='0')

sz[c-'0']++;

else if(c==' ')

space++;

else

e++;

}

printf("\n\n");

for(i=0;i<=9;i++)

{

t++;

printf(" %d的个数为%d ",i,sz[i]);

if(t%3==0)

printf("\n");

}

t=0;

printf("\n\n\n");

for(i=0;i<=25;i++)

{

t++;

printf(" %c的个数为%d ",i+97,zm[i]);

if(t%3==0)

printf("\n");

}

t=0;

printf("\n\n\n");

for(i=0;i<=25;i++)

{

t++;

printf(" %c的个数为%d ",i+65,z[i]);

if(t%3==0)

printf("\n");

}

t=0;

printf("\n\n\n");

printf(" 空格的个数为%d\n\n",space);

printf(" 其他字符的个数为%d\n",e);

return 0;

}

再来一则C语言统计输入字符个数的代码

#include

#define MAXWORD 30 //单词的最大长度

#define IN 1 //在单词内，即没有遇到空格

#define OUT 0 //在单词外，即遇到了空格

/*word length ==> wl单词长度简称*/

int wl()

{

char c;

int i;

int nc;

int state; //state为单词的状态：IN或OUT;

int overflow; //操过MAXWORD的单词个数

int wl[MAXWORD]; //长度为1~30的的字符长度统计

state = OUT;

nc = 0;

overflow = 0;

for(i = 1; i < MAXWORD; ++i)

wl[i] = 0;

while((c = getchar()) != EOF)

if(c == ' ' || c == '\n' || c == '\t')

{

state = OUT;

if(nc > 0)

if(nc < MAXWORD)

++wl[nc];

else

++overflow;

nc = 0;

}

else if(state == OUT)

{

state = IN;

nc = 1;

}

else

++nc;

for(i = 1; i < MAXWORD; ++i)

printf("长度为：%d的单词个数为：%d : \n\n", i, wl[i]);

return 0;

}

main()

{

wl();

}

以上所述就是本文的全部内容了，希望大家能够喜欢

import feedparser # package to parse rss

import re # package to match regular expression

def getwordscount(url):

d = feedparser.parse(url)

sum = 0 # sum for all the words

sum_en = 0

sum_zh = 0

sum_punc = 0

wordcount_zh = {} # dict to store chinese and its frequency

wordcount_en = {}

wordcount_punc = {}

for e in d[‘entries‘]:

if ‘summary‘ in e:# every entry should have a ‘summary‘ or a ‘description‘

summary = e.summary

else:

summary = e.description

words_zh, words_en, words_punc = getwords(e.title + ‘ ‘ + summary)

for word in words_zh:

wordcount_zh.setdefault(word, 0)#to set a dict[item] to default 0 if it doesn‘t exist

wordcount_zh[word] += 1

sum_zh += 1

for word in words_en:

wordcount_en.setdefault(word, 0)

wordcount_en[word] += 1

sum_en += 1

for word in words_punc:

wordcount_punc.setdefault(word, 0)

wordcount_punc[word] += 1

sum_punc += 1

sum = sum_zh + sum_en + sum_punc

wordcount_zh = sorted(wordcount_zh.items(), key = lambda d:d[1], reverse = True)# sort the dict with the value, and from the largest to smallest

wordcount_en = sorted(wordcount_en.items(), key = lambda d:d[1], reverse = True)

wordcount_punc = sorted(wordcount_punc.items(), key = lambda d:d[1], reverse = True)

print (d[‘feed‘][‘title‘])

print (‘Chinese: %d

%s‘%(sum_zh, wordcount_zh))

print (‘English: %d

%s‘%(sum_en, wordcount_en))

print (‘Punctuation: %d

%s‘%(sum_punc, wordcount_punc))

print (‘There are %d words in total‘%(sum))

def getwords(html):

txt = re.compile(r‘]+>‘).sub(‘ ‘, html)# re to replace ‘

words_zh = re.compile(r‘[u4E00-u9FFA]‘).findall(txt)# chinese character is between u4E00-u9FFA

words_en = re.compile(r‘[A-Za-z]+‘).findall(txt)

words_punc = re.compile(r‘[s+.!/_,$%^*(+"‘]+|[+——！，。？、[email protected]#￥%……&*()]+‘).findall(txt)

return words_zh, words_en, words_punc

(getwordscount(‘http://feed.cnblogs.com/blog/u/426928/rss‘))