语法

max(list)
min(list)

类型转换

如果列表内是字符串类型表示的浮点数，需要先转换成浮点数类型才能正确取最值。

'''
功能：求列表最值
作者：文雅兰
日期：2021年11月26日
'''
nums = [10,56,-38,22,18,-21]

max_value = nums[0]
for i in range(1,len(nums)):
    if max_value < nums[i]:
        max_value = nums[i]
print('max = {}'.format(max_value))

 输出后的结果就是列表中最大的数

def findMin(alist):

start = time.time()

findMin = alist[0];

for i in range(1,len(alist)):

if alist[i] < findMin:

findMin = alist[i]

end = time.time()

return findMin,end-start

结果如下：

for i in range(5):

print("the minimum is %d, the process required %10.7f seconds"%(findMin(list(random.randint(1,100) for i in range(1000000)))))

the minimum is 1, the process required 0.1043806 seconds

the minimum is 1, the process required 0.0833511 seconds

the minimum is 1, the process required 0.1031568 seconds

the minimum is 1, the process required 0.1031709 seconds

the minimum is 1, the process required 0.0906184 seconds

函数改进一下：

def findMin(alist):

start = time.time()

findMin = alist[0];

for i in alist:

if i < findMin:

findMin = i

end = time.time()

return findMin,end-start

因为python 中for循环可以对元素进行遍历，所以可以这样写。

结果如下：

for i in range(5):

print("the minimum is %d, the process required %10.7f seconds"%(findMin_1(list(random.randint(1,100) for i in range(1000000)))))

the minimum is 1, the process required 0.0530787 seconds

the minimum is 1, the process required 0.0150602 seconds

the minimum is 1, the process required 0.0606675 seconds

the minimum is 1, the process required 0.0580323 seconds

the minimum is 1, the process required 0.0625741 seconds

运行时间比上一种方法要短。