前天帮同学做了一下面试题，题目要求如下：
读入一串字符，将该字符串中所有的“abc”字符串删除，并将处理后的字符串输出。
例如：
输入：asdfghjklabczxcv，输出：asdfghjklzxcv
程序如下：
int main()
{
	char str[100],*p,*q;
	cin>>str;
	for(p = str, q = str; *p !='\0'; p++)
	{
		if((*(p)=='a')&&(*(p+1)=='b')&&(*(p+2)=='c'))
		{
			p = p + 2;
		}
		else
		{
			*q++ = *p;
		}

	}
	*q = *p;	//this code get the '\0'
	cout << str << endl;
	return 0;
}

Given a string and an index, we have to remove the character from given index in the string using python program.
 给定一个字符串和一个索引，我们必须使用python程序从字符串中给定的索引中删除字符。 
Here, we would learn how we can remove a character from an index in a string easily?
 在这里，我们将学习如何轻松地从字符串的索引中删除字符？ 
Question:
 题： 
We are provided a non-empty string and an integer N, such that we have to return a string such that the character at the given index (N) has been removed. Where N belongs to the range from 0 to len(str)-1.
 我们提供了一个非空字符串和一个整数N ，以便我们必须返回一个字符串，以便删除给定索引(N)处的字符 。 其中N属于从0到len(str)-1的范围 。 
Example:
 例： 
    remove_char ('raman', 1) = 'rman'
    remove_char ('raman', 0) = 'aman'
    remove_char ('raman', 4) = 'rama'

Code:
 码： 
def remove_char(str, n):
    front = str[:n]  # up to but not including n
    back = str[n + 1:]  # n+1 till the end of string
    return front + back

print (remove_char('IncludeHelp', 3))
print (remove_char('Hello', 4))
print (remove_char('Website', 1))

Output
 输出量 
IncudeHelp
Hell
Wbsite


翻译自: https://www.includehelp.com/python/program-to-remove-a-character-from-a-specified-index-in-a-string.aspx

kotlin中判断字符串
Given a string and a character, we have to remove all occurrences of the character in given string.
 给定一个字符串和一个字符，我们必须删除给定字符串中所有出现的字符。 
Example:
 例： 
    Input:
    string = "includeHelp Delhi"

    Output:
    String after removing character : "includeelp Deli"

 在Kotlin中删除字符串中所有出现的字符的程序 (Program to remove all occurrences of a character in a string in Kotlin)
package com.includehelp.basic

import java.util.*

//Main Function, entry Point of Program
fun main(args: Array<String>) {
    // InputStream to get Input
    val scanner = Scanner(System.`in`)

    //Input String
    print("Enter String : ")
    var str = scanner.nextLine()

    //Input Character to Remove from String
    print("Enter Character : ")
    val c = scanner.next()[0]


    //Replace character with Empty String
    val newStr=str.replace(c.toString(),"",ignoreCase = true)


    //Print String after Replacement
    println("String after removing character : $newStr ")
}

Output
 输出量 
Run 1:
Enter String : includeHelp Delhi
Enter Character : h
String after removing character : includeelp Deli
---
Run 2:
Enter String : corona virus global death rate
Enter Character : o
String after removing character : crna virus glbal death rate


翻译自: https://www.includehelp.com/kotlin/remove-all-occurrences-of-a-character-in-a-string.aspx
kotlin中判断字符串

习题8-6 删除字符 (20 分)

本题要求实现一个删除字符串中的指定字符的简单函数。
函数接口定义：
void delchar( char *str, char c );

其中char *str是传入的字符串，c是待删除的字符。函数delchar的功能是将字符串str中出现的所有c字符删除。
裁判测试程序样例：
#include <stdio.h>
#define MAXN 20

void delchar( char *str, char c );
void ReadString( char s[] ); /* 由裁判实现，略去不表 */

int main()
{
    char str[MAXN], c;

    scanf("%c\n", &c);
    ReadString(str);
    delchar(str, c);
    printf("%s\n", str);

    return 0;
}

/* 你的代码将被嵌在这里 */

输入样例：
a
happy new year

输出样例：
hppy new yer

代码：
/*两种形式的解法，思路和网上常见的也是一样的原理，
每次遇到某一指定的字符就把后面的字符向前移动。
解题思路都相同，此处用的是指针，直接修改str参数本身*/
void delchar( char *str, char c ){
	//形式一
	char *p = str;
    while(*str!='\0'){
        if(*str==c){
        	str++;
        	continue;
		}
        *p = *str;
        p++;
        str++;
    }
    *p = '\0';
    /*
    //形式二：
	char *p = str;   
    int i;
    for(i=0;str[i]!='\0';i++){
    	if(str[i]==c)	continue;
		*p = str[i];
		p++;    	
	}
	*p = '\0';*/
	//str = &res;
	//printf("%s",str);
}

题目链接：习题8-6 删除字符