前天帮同学做了一下面试题，题目要求如下：
 
读入一串字符，将该字符串中所有的“abc”字符串删除，并将处理后的字符串输出。
 
例如：
 
输入：asdfghjklabczxcv，输出：asdfghjklzxcv
 
程序如下：
 

 
int main()
{
	char str[100],*p,*q;
	cin>>str;
	for(p = str, q = str; *p !='\0'; p++)
	{
		if((*(p)=='a')&&(*(p+1)=='b')&&(*(p+2)=='c'))
		{
			p = p + 2;
		}
		else
		{
			*q++ = *p;
		}

	}
	*q = *p;	//this code get the '\0'
	cout << str << endl;
	return 0;
}
 
 
 

 
 

 
 

 

 

 
kotlin中判断字符串
 
Given a string and a character, we have to remove all occurrences of the character in given string.
 
 
 给定一个字符串和一个字符，我们必须删除给定字符串中所有出现的字符。 
 
 
Example:
 
 
 例： 
 
 
    Input:
    string = "includeHelp Delhi"

    Output:
    String after removing character : "includeelp Deli"


 
 在Kotlin中删除字符串中所有出现的字符的程序 (Program to remove all occurrences of a character in a string in Kotlin)
 
 
package com.includehelp.basic

import java.util.*

//Main Function, entry Point of Program
fun main(args: Array<String>) {
    // InputStream to get Input
    val scanner = Scanner(System.`in`)

    //Input String
    print("Enter String : ")
    var str = scanner.nextLine()

    //Input Character to Remove from String
    print("Enter Character : ")
    val c = scanner.next()[0]


    //Replace character with Empty String
    val newStr=str.replace(c.toString(),"",ignoreCase = true)


    //Print String after Replacement
    println("String after removing character : $newStr ")
}


 
Output
 
 
 输出量 
 
 
Run 1:
Enter String : includeHelp Delhi
Enter Character : h
String after removing character : includeelp Deli
---
Run 2:
Enter String : corona virus global death rate
Enter Character : o
String after removing character : crna virus glbal death rate



 

  
翻译自: https://www.includehelp.com/kotlin/remove-all-occurrences-of-a-character-in-a-string.aspx
 
 
kotlin中判断字符串

 
Given a string and an index, we have to remove the character from given index in the string using python program.
 
 
 给定一个字符串和一个索引，我们必须使用python程序从字符串中给定的索引中删除字符。 
 
 
Here, we would learn how we can remove a character from an index in a string easily?
 
 
 在这里，我们将学习如何轻松地从字符串的索引中删除字符？ 
 
 
Question:
 
 
 题： 
 
 
We are provided a non-empty string and an integer N, such that we have to return a string such that the character at the given index (N) has been removed. Where N belongs to the range from 0 to len(str)-1.
 
 
 我们提供了一个非空字符串和一个整数N ，以便我们必须返回一个字符串，以便删除给定索引(N)处的字符 。 其中N属于从0到len(str)-1的范围 。 
 
 
Example:
 
 
 例： 
 
 
    remove_char ('raman', 1) = 'rman'
    remove_char ('raman', 0) = 'aman'
    remove_char ('raman', 4) = 'rama'


 
Code:
 
 
 码： 
 
 
def remove_char(str, n):
    front = str[:n]  # up to but not including n
    back = str[n + 1:]  # n+1 till the end of string
    return front + back

print (remove_char('IncludeHelp', 3))
print (remove_char('Hello', 4))
print (remove_char('Website', 1))


 
Output
 
 
 输出量 
 
 
IncudeHelp
Hell
Wbsite



 

  
翻译自: https://www.includehelp.com/python/program-to-remove-a-character-from-a-specified-index-in-a-string.aspx
 

【问题描述】编写一个程序，从键盘接收一个字符串，然后按照字符顺序从小到大进行排序，并删除重复的字符。
 【输入形式】从键盘输入一个字符串，以回车结束输入。要求程序可以处理含有空格的字符串。
 【输出形式】程序接收此字符串，然后将其按照字符ASCII码值从小到大的顺序进行排序，并删除重复的字符输出。如果字符串为空，输出也应该为空。
 【样例输入】badacgegfacb
 【样例输出】abcdefg
 【样例说明】输入badacgegfacb，然后排序、删除重复字符得到abcdefg。
 【评分标准】完全正确为20分，每个测试点4分。
 
import java.util.Arrays;
import java.util.Scanner;

public class _2Delete {

	public static void main(String[] args) {
		String str;
		Scanner sc = new Scanner(System.in);
		str = sc.nextLine();

		char[] cStr = str.toCharArray();//将字符串转换为字符数组，然后再排序
		Arrays.sort(cStr);//排序，手写排序是不可能的

		int i = 0;//下标
		while (i < cStr.length) {
			
			System.out.print(cStr[i]);//输出当前字符
			
			//忽略中间重复的字符：有趣的for实现
			for (++i; i < cStr.length && cStr[i] == cStr[i - 1]; ++i);
		}
	}
}

 
排序之后，输出一个字符，然后跳过紧跟着的重复字符。