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  • 编译环境:Python3.8.1 注:压缩包内自带虚拟环境,可通过虚拟环境运行,避免版本冲突 代码功能:Python判断代码文件所在文件夹一级目录下是否存在目标文件
  • 以下文章是对C/C++中判断某一文件目录是否存在的实现代码进行了详细的分析介绍,需要的朋友可以参考
  • shell判断某一目录下是否有文件存在

    千次阅读 2021-05-10 04:20:24
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    展开全文
  • 主要介绍了Lua判断一个目录文件是否存在的方法,Lua中可以使用io.open判断文件或目录是否存在,本文总结了判断方法,并给出了一个自定义函数,需要的朋友可以参考
  • 下面小编就为大家带来一篇linux下判断文件目录是否存在的方法(总结)。小编觉得挺不错的,现在就分享给大家,也给大家做个参考。一起跟随小编过来看看吧
  • 主要介绍了linux shell 中判断文件目录是否存在的方法,文中通过示例代码介绍的非常详细,对大家的学习或者工作具有一定的参考学习价值,需要的朋友们下面随着小编来一起学习学习吧
  • 写法如下: if [ "`ls -A ${dir}`" != "" ]; then echo has files fi

    写法如下:

    dir=${HOME}/test
    if [ -d ${dir} -a "`ls -A ${dir}`" != "" ]; then
        echo "${dir} has files!"
    fi

    展开全文
  • Linux如何统计当前目录下文件有多少个,目录多少个呢? 下面用shell写一个脚本,放置在当前目录下,执行即可。 代码如下:  #!/bin/bash   #脚本名称 dir #定义一个函数fun_directory   fun_directory() {...
  • 一、关于删除指定文件夹文件,这里写了一个工具类,但是删除的是全部文件,包括图片,如果需要删除各别类型,再额外定义文件类型(根据后缀)。 文件删除工具类: public class delUtil { public static boolean ...

    一、关于删除指定文件夹下的文件,这里写了一个工具类,但是删除的是全部文件,包括图片,如果需要删除各别类型,再额外定义文件类型(根据后缀)。
    文件删除工具类:

    public class delUtil {
    	public static  boolean delAllFile(String path) {  
            boolean flag = false;  
            File file = new File(path);  
            if (!file.exists()) {  
                return flag;  
            }  
            if (!file.isDirectory()) {  
                return flag;  
            }  
            String[] tempList = file.list();  
            File temp = null;  
            for (int i = 0; i < tempList.length; i++) {  
                if (path.endsWith(File.separator)) {  
                    temp = new File(path + tempList[i]);  
                } else {  
                    temp = new File(path + File.separator + tempList[i]);  
                }  
                if (temp.isFile()) {  
                    temp.delete();  
                }  
                if (temp.isDirectory()) {  
                    delAllFile(path + "/" + tempList[i]);// 删除文件夹里面的文件  
                    flag = true;  
                }  
            }  
            return flag;  
        } 
    }
    

    测试类代码:

    public class test {
    
    	public static void main(String[] args) {
    		try {
    			String path = "E:/file/file";
    			delUtil.delAllFile(path);
    			System.out.println("文件删除成功!");
    			
    		} catch (Exception e) {
    			System.out.println(e);
    		}
    
    	}
    
    }
    

    输出结果如下:
    在这里插入图片描述
    在这里插入图片描述
    二、查询文件夹下有多少文件:

    //查询方法:
    public static long picCount() {
    		File file = new File("E:/file/file");// 图片存放路径
    		File list[] = file.listFiles();
    		/**
    		* 获取文件夹下所有的文件 不是图片的文件也会被读取的, 如果你是专门用来存放图片的文件,这种方法可行 否则的话就要判断文件的类型了
    		*/
    		return list.length;
    		}
    

    测试类:

    public class test1 {
    	public static void main(String[] args) {
    		System.out.println("文件个数为:"+SelectFile.picCount());
    	}
    }
    

    输出结果为:
    在这里插入图片描述
    在这里插入图片描述
    三、还有一种直接判断文件夹下是否有文件(即文件夹是否为空)

    String path = "E:/file/file";
    		File file = new File(path);
    		File[] list = file.listFiles();
    		if (list.length>0) {
    			System.out.println("该文件夹下有文件");
    		}else{
    			System.out.println("该文件夹下没有文件");
    		}
    

    在这里插入图片描述
    在这里插入图片描述

    展开全文
  • 一、判断有无文件且删除 import os if os.path.exists(r'session_name.session-journal'): os.remove(r'session_name.session-journal') print('当前数据库已解除锁定') else: print('当前数据库未被锁定'...

    一、判断有无文件,有且删除

            import os
            if os.path.exists(r'session_name.session-journal'):
                os.remove(r'session_name.session-journal')
                print('当前数据库已解除锁定')
            else:
                print('当前数据库未被锁定')
    

    新增:
    1、新建文件

    import os
    
    current_path = os.getcwd()  #获取当前路径
    print(current_path)
    path = current_path+'\\test.txt' #在当前路径创建名为test的文本文件
    
    if os.path.exists(path):
    	print('exist')
    else:
    	os.mkdir(path)
    
    

    2、新建文件夹

    import os
    current_path = os.getcwd()  #获取当前路径
    path = current_path+'\\test' #在当前路径创建名为test的文件夹
    
    if os.path.exists(path):
    	print('exist')
    else:
    	os.mkdir(path)  #创建
    
    
    展开全文
  • Android:判断手机内部储存目录下是否有指定的文件1、 关于手机内部储存目录和外部储存目录的关系2、判断手机内部储存目录/data/user/0/com.example.xuanfuchuang/files/下是否有名称为“switch_configure.txt”的...
  • 因shell还不是很熟练,所以做此笔记,方便查看,学习shell的朋友可以参考
  • 批处理判断指定目录是否存在文件

    千次阅读 2020-10-14 22:49:28
    @echo off set fnum=0 for %%a in (*.*) do ( set fnum=1 ) echo %fnum%
  • liunx判断多层目录下是否有压缩文件 liunx判断多层目录下是否有压缩文件
  • PHP判断指定目录下是否存在文件

    千次阅读 2018-04-28 16:33:52
    功能:判断某个目录下是否存在文件; 参数:$path —— 要进行判断目录,使用绝对路径 返回值:存在 - true 不存在 - false */ function dir_exist_file($path) { if (!is_dir($path)) { return f...
  • java 判断文件夹是否存在文件

    千次阅读 2021-02-26 10:19:11
    2、然后判断是否目录,不是目录就返回3、之后使用file.list()方法获取目录下文件并存入数组4、最后判断数组长度大于0则存在文件。代码如下:/*** 读取某个文件夹的所有文件*/public static boolean hasfile...
  • 本篇文章给大家分享了Java IO判断目录文件是否存在的代码,对此需要的读者们可以跟着小编一起学习
  • 时候我们需要判断是否目录有读写权限就需要下面的代码,需要的朋友的可以参考
  • 第二步,检测文件目录是否存在: hdfs dfs -test -e 文件目录名 第三步,查看检测结果: echo $? 若输出结果为0,则说明文件目录存在,若为1,则说明文件目录不存在。 二、Java代码实现 import org.apache...
  • Android 判断目录下文件是否存在

    千次阅读 2019-09-06 16:23:58
    //strFile 为文件名称 返回true为存在 public boolean fileIsExists(String strFile) { try { File f=new File(strFile); if(f.exists()) { return true; }else{ return ...
  • 今天小编大家分享一篇C#获得程序的根目录以及判断文件是否存在的实例讲解,具有很好的参考价值,希望对大家有所帮助。一起跟随小编过来看看吧
  • linux下判断文件目录是否存在[总结]1、前言 工作中涉及到文件系统,时候需要判断文件目录是否存在。我结合APUE第四章文件目录,总结一下如何正确判断文件目录是否存在,方便以后查询。2、stat系列函数 ...
  • 判断文件是否可做读写操作 2.使用Try语句 3. 使用pathlib模块 正文 通常在读写文件之前,需要判断文件或目录是否存在,不然某些处理方法可能会使程序出错。所以最好在做任何操作之前,先判断文件是否存在。 ...
  • 主要为大家详细介绍了java判断ftp目录是否存在的方法,具有一定的参考价值,感兴趣的小伙伴们可以参考一下
  • 所以最好在做任何操作之前,先判断文件是否存在。这里将介绍三种判断文件或文件夹是否存在的方法,分别使用os模块、Try语句、pathlib模块。1.使用os模块os模块中的os.path.exists()方法用于检验文件是否存在。判断...
  • shell 判断文件夹或文件是否存在

    千次阅读 2021-05-09 04:22:34
    shell 判断文件夹或文件是否存在2018-12-05文件夹不存在则创建12345if [ ! -d "/data/" ];thenmkdir /dataelseecho "文件夹已经存在"fi文件存在则删除12345if [ ! -f "/data/filename" ];thenecho "文件不存在...
  • 第一种:判断服务器上的文件是否存在,里面需要使用服务器路径(../ACD.word),而不是具体路径(D:\ACD.word),使用MapPath属性,此属性是“返回与 Web 服务器上的指定虚拟路径相对应的物理文件路径。” string ...
  • linux下判断文件目录是否存在

    千次阅读 2021-02-13 02:04:28
    1、前言工作中涉及到文件系统,时候需要判断文件目录是否存在。我结合APUE第四章文件目录,总结一下如何正确判断文件目录是否存在,方便以后查询。2、stat系列函数stat函数用来返回与文件有关的结构信息。...

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