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  • wander

    2019-09-19 03:47:35
    05-26 to do: 1. person too high, (is there problem with the size of model?) 2. go to floor 2. 3. fly mode, do not descend 4. door open animatio...

    05-26 to do:

    1. person too high, (is there problem with the size of model?)

    2. go to floor 2.

    3. fly mode, do not descend

    4. door open animation

    5. move too slow


    05-26-20:21

    发现胶囊的高度高于8.08才可以进门。进入后,加入重力也掉不小来,

    看来肯定是模型的尺寸有问题!!! 

    今天终于做了一点有用的实验,摆放另一个同样高度和尺寸的胶囊形影相随,

    其实这个小伎俩我早应该想出来的。


    05-27-11:48

    发现用unity集成环境,情况不大一样,

    现在不敢断定模型尺寸有问题了,

    但还是发现好像有看不见的实物作怪。


    先把fly mode搞定再说吧!


    05-28-06:30

    todo:

    1. combine First Person and the old UI elements

    2. master First Person Law


    The “GetAxisRaw” method is used instead of the “GetAxis” because the latter applies smoothing which will make our rotations less responsive. 


    our horizontalInput and verticalInput variables will return values between -1 and 1. They are the magnitudes of the direction. The right and forward variables return directions as vectors.


    ApplyGravityAndJumping可以用一个flag控制一下,flymode不用调用。


    The “movement” variable takes the direction and multiplies it by Time.deltaTime * 2. This will slow down the movement to rotate by seconds instead of by frames. 

    转载于:https://my.oschina.net/u/1771959/blog/268876

    展开全文
  • Wander

    2011-07-12 08:46:27
    In this project, everything i do is depend what my mind will think about what...Next to do:1. KLinkList, reverse, 2. recognise "1+2*3"3. c++

    In this project, everything i do is depend what my mind will think about what...

    Next to do:

    1. KLinkList, reverse, 

    2. recognise "1+2*3"

    3. c++ factory

    展开全文
  • Wander是用于编写非确定性幻想“故事”的工具。 该产品是一个故事,其展开受到“读者”所做决定的影响。 作者是( ,当被问及这是否确实是1974年时,他说: “我记得当我还在华盛顿州奥林匹亚州Evergreen State ...
  • 语言:English (United States) 每次打开Goog​​le地图时,请享受一个新的位置。 每次打开Goog​​le Maps时探索新位置。 一种获得崭新视角的好方法...请注意,地球上有很多水:)可用资源:github.com/ghchinoy/wander
  • Wander Chrome扩展程序可让您:-直接从正在查看的内容共享到Wander-在帖子中添加标签-评论文章以存储最佳见解要了解有关Wander的更多信息,请访问[ThinkWander.com](https ://www.thinkwander.com)--------------...
  • Beam wander of partially coherent array beams through non-Kolmogorov turbulence
  • Wander是一个全栈应用程序,可以保存您在世界各地最喜欢的地方 :magnifying_glass_tilted_left: 搜索功能以及在您的帐户上保存位置的可能性 :pencil: 可以编辑地点并根据其类别添加评论,注释或颜色标签 :blue_...
  • wander程序是一个很好的学习程序,将这个程序弄明白对于先锋三机器人的学习有着很大的帮助,这个wander注释版尽我的能力做了注释,希望对大家有所帮助
  • Wander-源码

    2021-03-05 05:03:20
    2021年Spring 2D中世纪小屋平台游戏
  • Relative clock wander between data signal and sampling source is a typical occurrence in such systems. A method for the quantitative monitoring of the relative clock wander in asynchronous optical ...
  • Lunar New Year and a Wander

    2019-03-05 08:22:00
    Lunar New Year and a Wander time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output Lunar New Year is approach...
    D. Lunar New Year and a Wander
    time limit per test
    3 seconds
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    Lunar New Year is approaching, and Bob decides to take a wander in a nearby park.

    The park can be represented as a connected graph with n nodes and m bidirectional edges. Initially Bob is at the node 1 and he records 1 on his notebook. He can wander from one node to another through those bidirectional edges. Whenever he visits a node not recorded on his notebook, he records it. After he visits all nodes at least once, he stops wandering, thus finally a permutation of nodes a1,a2,,an is recorded.

    Wandering is a boring thing, but solving problems is fascinating. Bob wants to know the lexicographically smallest sequence of nodes he can record while wandering. Bob thinks this problem is trivial, and he wants you to solve it.

    A sequence x is lexicographically smaller than a sequence y if and only if one of the following holds:

    • x is a prefix of y, but xy (this is impossible in this problem as all considered sequences have the same length);
    • in the first position where x and y differ, the sequence x has a smaller element than the corresponding element in y.
    Input

    The first line contains two positive integers n and m (1n,m105), denoting the number of nodes and edges, respectively.

    The following m lines describe the bidirectional edges in the graph. The i-th of these lines contains two integers ui and vi (1ui,vin), representing the nodes the i-th edge connects.

    Note that the graph can have multiple edges connecting the same two nodes and self-loops. It is guaranteed that the graph is connected.

    Output

    Output a line containing the lexicographically smallest sequence a1,a2,,an Bob can record.

    Examples
    input
    Copy
    3 2
    1 2
    1 3
    
    output
    Copy
    1 2 3 
    
    input
    Copy
    5 5
    1 4
    3 4
    5 4
    3 2
    1 5
    
    output
    Copy
    1 4 3 2 5 
    
    input
    Copy
    10 10
    1 4
    6 8
    2 5
    3 7
    9 4
    5 6
    3 4
    8 10
    8 9
    1 10
    
    output
    Copy
    1 4 3 7 9 8 6 5 2 10 
    
    Note

    In the first sample, Bob's optimal wandering path could be 1213. Therefore, Bob will obtain the sequence {1,2,3}, which is the lexicographically smallest one.

    In the second sample, Bob's optimal wandering path could be 14323415. Therefore, Bob will obtain the sequence {1,4,3,2,5}, which is the lexicographically smallest one.

     

     

    #include<bits/stdc++.h>
    #define REP(i, a, b) for(int i = (a); i <= (b); ++ i)
    #define REP(j, a, b) for(int j = (a); j <= (b); ++ j)
    #define PER(i, a, b) for(int i = (a); i >= (b); -- i)
    using namespace std;
    const int maxn=2e5+5;
    template <class T>
    inline void rd(T &ret){
        char c;
        ret = 0;
        while ((c = getchar()) < '0' || c > '9');
        while (c >= '0' && c <= '9'){
            ret = ret * 10 + (c - '0'), c = getchar();
        }
    }
    priority_queue<int,vector<int>,greater<int> >q;
    vector<int>ans;
    bool vis[maxn];
    int head[maxn],n,m,tot;
    struct node{
        int to,nx;
    }p[maxn];
    void addedge(int s,int t){
         p[++tot].to=t,p[tot].nx=head[s],head[s]=tot;
    }
    int main()
    {
        rd(n),rd(m);
        REP(i,1,m){
            int u,v;
            rd(u),rd(v);
            addedge(u,v),addedge(v,u);
        }
        q.push(1);
        while(!q.empty()){
             int cur=q.top();
             q.pop();
             if(vis[cur])continue;
             vis[cur]=true;
             ans.push_back(cur);
             for(int i=head[cur];i;i=p[i].nx){
                  int to=p[i].to;
                  if(vis[to])continue;
                 // vis[to]=1;
                  q.push(to);
             }
        }
        for(int i=0;i<ans.size();i++)cout<<ans[i]<<' ';
        return 0;
    }

     

    转载于:https://www.cnblogs.com/czy-power/p/10474488.html

    展开全文
  • 每次打开Goog​​le地图时都可以享受新的地理位置。 每次打开Goog​​le Maps时探索新位置。...请注意,地球上有很多水:)可用资源:github.com/ghchinoy/wander 支持语言:English (United States)
  • FTP Wander

    2012-06-13 21:28:10
    这个是一个ftp客户端的源代码 网上也是比较少 很难得的
  • 精品的高级的音乐与视频手机应用Wander UI Kit.sketch素材下载 App Ui Kit、sketch、UI Kit、主题包、音乐手机APP界面设计
  • Wander通过精心策划的一系列沉浸式故事来重新发明城市旅行,这些故事涵盖了最佳的城市景点。 在下载应用程序 您可以找到。 安装 由于安全原因,免责声明项目缺少Info.plist中的GoogleService-Info.plist和...
  • 题目链接:Codeforces - Lunar New Year and a Wander 每次肯定选择当前能走的最小的节点走。 因为可以回退。所以直接每次把能到的点全部放到堆里面,每次取最小的即可。 AC代码: #pragma GCC optimize("-Ofast",...

    题目链接:Codeforces - Lunar New Year and a Wander


    每次肯定选择当前能走的最小的节点走。

    因为可以回退。所以直接每次把能到的点全部放到堆里面,每次取最小的即可。


    AC代码:

    #pragma GCC optimize("-Ofast","-funroll-all-loops")
    #include<bits/stdc++.h>
    //#define int long long
    using namespace std;
    const int N=1e5+10;
    int n,m,vis[N];	priority_queue<int,vector<int>,greater<int> > q;
    vector<int> g[N];
    inline void add(int a,int b){g[a].push_back(b),g[b].push_back(a);}
    signed main(){
    	cin>>n>>m;	q.push(1);	vis[1]=1;
    	for(int i=1,a,b;i<=m;i++)	scanf("%d %d",&a,&b),add(a,b);
    	while(q.size()){
    		int u=q.top();	q.pop();	printf("%d ",u);
    		for(auto to:g[u])	if(!vis[to])	vis[to]=1,q.push(to);
    	}
    	return 0;
    }
    
    展开全文
  • Lunar New Year and a Wander ( DFS ) Lunar New Year is approaching, and Bob decides to take a wander in a nearby park. The park can be represented as a connected graph withnnnodes andmmbidir...
  • 有一个收藏夹(书签)编辑器,因为在虚拟现实中编辑书签很困难,而且您无法更改顺序。 使用此编辑器,您可以在 VR 中策划一系列地点,并将它们组织成与其他人一起游览。 还有一些其他实用程序可以管理您的收藏夹文件...
  • 徘徊(Wander)行为 许多时候,人们需要让游戏中的角色在游戏环境中随机移动(如巡逻的士兵、惬意吃草的牛羊等),就像这些角色是在等待某些事情发生,或者是在寻找什么东西,当角色出现在玩家视线中,人们通常希望...
  • Lunar New Year and a Wander题目链接分析代码 题目链接 传送门 分析 直接用优先队列维护字典序就好。 代码 感觉写的好像dijkstra #include <iostream> #include <cstdio> #include <algorithm> #...
  • 0.前提 由AS准备的使用Google Maps Activity模板的示例 google_maps_api.xml 设置文件 这也用于调试和发布 activity_maps.xml MapsActivity.java 谷歌地图术语 类型 普通的 杂交种 卫星 ...在google_
  • Lunar New Year is approaching, and Bob decides to take a wander in a nearby park. The park can be represented as a connected graph with n nodes and m bidirectional edges. Initially Bob is at the n...
  • iwander_-源码

    2021-02-18 11:31:45
    安装说明 请按照以下步骤安装应用程序: 在phpMyAdmin上创建数据库 在根文件夹中创建一个新文件。 将其命名为“ .env ” 复制“ .env.example ”中的所有内容并将代码粘贴到“ .env ”中 打开“ .env ”,然后将DB...
  • 题目摘自WC模拟试题(by Philipsweng),原题目名Wander,“山村游历”是自己搞出来的中文名。 数据自测,如有问题欢迎反馈 对耐心的人来说,这道题是个裸题(当我什么也没说) 题面 题目描述 在一个偏远的小镇上,有...
  • Lunar New Year and a Wander bfs+优先队列 题意 给出一个图,从1点开始走,每个点至少要经过一次(可以很多次),每次经过一个没有走过的点就把他加到走过点序列中,问最小字典序的序列是多少 思路 起始就是从每次...
  • Lunar New Year is approaching, and Bob decides to take a wander in a nearby park. The park can be represented as a connected graph with nn nodes and mm bidirectional edges. Initially Bob is at ...
  • Lunar New Year is approaching, and Bob decides to take a wander in a nearby park. The park can be represented as a connected graph with n nodes and m bidirectional edges. Initially Bob is at...
  • Wander&Aspire-crx插件

    2021-04-03 05:37:25
    语言:English 要小心! 以下扩展可能会增加或减少您的渴望,以达到令人敬畏的新旅行目的地。 使用... 要小心! 以下扩展可能会增加或减少您的渴望,以达到令人敬畏的新旅行目的地。 小心使用。
  • Lunar New Year is approaching, and Bob decides to take a wander in a nearby park. The park can be represented as a connected graph with nn nodes and mm bidirectional edges. Initially Bob is at ...

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