• 1374. Generate a String With Characters That Have Odd Counts* https://leetcode.com/problems/generate-a-string-with-characters-that-have-odd-counts/ 题目描述 Given an integer n, return a string with n ...
1374. Generate a String With Characters That Have Odd Counts*
https://leetcode.com/problems/generate-a-string-with-characters-that-have-odd-counts/
题目描述
Given an integer n, return a string with n characters such that each character in such string occurs an odd number of times.
The returned string must contain only lowercase English letters. If there are multiples valid strings, return any of them.
Example 1:
Input: n = 4
Output: "pppz"
Explanation: "pppz" is a valid string since the character 'p' occurs three times and the character 'z' occurs once. Note that there are many other valid strings such as "ohhh" and "love".

Example 2:
Input: n = 2
Output: "xy"
Explanation: "xy" is a valid string since the characters 'x' and 'y' occur once. Note that there are many other valid strings such as "ag" and "ur".

Example 3:
Input: n = 7
Output: "holasss"

Constraints:
1 <= n <= 500
C++ 实现 1
class Solution {
public:
string generateTheString(int n) {
if (n % 2 == 1) return string(n, 'a');
else return string(n - 1, 'a') + 'b';
}
};

展开全文
• https://www.yahoo.com/tech/the-apple-watch-face-that-counts-down-to-your-113889037339.html
https://www.yahoo.com/tech/the-apple-watch-face-that-counts-down-to-your-113889037339.html
展开全文
• Generate a String With Characters That Have Odd Counts (E) Given an integer n, return a string with n characters such that each character in such string occurs an odd number of times. The returned str...
Generate a String With Characters That Have Odd Counts (E)
Given an integer n, return a string with n characters such that each character in such string occurs an odd number of times.
The returned string must contain only lowercase English letters. If there are multiples valid strings, return any of them.
Example 1:
Input: n = 4
Output: "pppz"
Explanation: "pppz" is a valid string since the character 'p' occurs three times and the character 'z' occurs once. Note that there are many other valid strings such as "ohhh" and "love".

Example 2:
Input: n = 2
Output: "xy"
Explanation: "xy" is a valid string since the characters 'x' and 'y' occur once. Note that there are many other valid strings such as "ag" and "ur".

Example 3:
Input: n = 7
Output: "holasss"

Constraints:
1 <= n <= 500

题意
给定整数n，要求返回长度为n的字符串，该字符串只由小写字母组成，且每一个字母出现的次数都为奇数。
思路
直接ab就完事了。

代码实现
class Solution {
public String generateTheString(int n) {
StringBuilder sb = new StringBuilder();
for (int i = 0; i < n - 1; i++) {
sb.append('a');
}
if (n % 2 == 0) {
sb.append('b');
} else {
sb.append('a');
}
return sb.toString();
}
}

展开全文
• COZ: Finding Code that Counts with Causal ProfilingCharlie Curtsinger ∗Department of Computer ScienceGrinnell Collegecurtsinger@cs.grinnell.eduEmery D. BergerCollege of Information and Computer ...
• https://leetcode.com/problems/generate-a-string-with-characters-that-have-odd-counts/ class Solution { public String generateTheString(int n) { char[] chars = new char[n]; if (...
https://leetcode.com/problems/generate-a-string-with-characters-that-have-odd-counts/

class Solution {
public String generateTheString(int n) {
char[] chars = new char[n];
if (n == 0) return "";
boolean isOdd = n % 2 != 0;
for (int i = 0; i < n; i++) {
if (isOdd) chars[i] = 'k';
else if (i == 0) {
chars[0] = 's';
} else {
chars[i] = 'k';
}
}
return new String(chars);
}
}


展开全文
• https://leetcode.com/problems/generate-a-string-with-characters-that-have-odd-counts/ 给定一个正整数nnn，返回一个长nnn的任一字符串，使得每个字母都出现奇数次。 代码如下： public class Solution { ...
• 1、Write a method that counts the number of occurrences of a given character in a string 2、Write a method that counts the number of occurrences of a particular string in another string
• COZ: Finding Code that Counts with Causal ProfilingCharlie Curtsinger Emery D. Berger School of Computer ScienceUniversity of Massachusetts Amherst {charlie,emery}@cs.umass.eduAbstract Improving ...
• Write a function that counts the occurences of each digit in a string using the following header: int* count(const string& s) 返回字符串里各个数字出现的次数。 #include<iostream> #include<...
• Given an integer n, return a string with n characters such that each character in such string occurs an odd number of times. The returned string must contain only lowercase English letters. If there ...
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• Given an integer n, return a string with n characters such that each character in such string occurs an odd number of times. The returned string must contain only lowercase English letters. If there ...
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• Generate a String With Characters That Have Odd Counts生成每种字符都是奇数个的字符串【Easy】【Python】【字符串】 Problem LeetCode Given an integer n, return a string with n characters such that each...
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• 输入：n = 7 输出："holasss
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