
HELP with Measure distance with a HCSR04 ultrasonic sensor
20201227 11:52:27Measure distance with a HCSR04 ultrasonic sensor" and it's working. Thanks for that. <p>Nevertheless, i don't understand the syntax of this part of code: We declare an async anonymous ... 
Replace step_distance with rotation_distance
20210106 05:02:05<p>In particular, I ran into an error with step_distance when I updated one of my printers a few weeks ago. I went from an old 8bit control board using 8 microsteps to a newer board with tmc2208 ... 
Constructing a SphericalRepresentation object with a negative distance is impossible
20210106 19:59:50To allow negative distance values, you must explicitly pass in a `Distance` object with the the argument 'allow_negative=True'. </module></ipythoninput3bc5d4ae3542b>... 
Compute distance with one point normalized
20201130 07:37:17* I have a space with only categorical variables (most of them containing integers admittedly) * ask and tell API is used with an gp optimizer <p>The first <code>n_initial_points</code>many points ... 
Fixed the wrong KNNClassification with DTW as a distance
20210107 03:09:56<p>Changed the dtw function from <code>sktime.distances.elastic_cython</code> to <code>from tslearn.metrics import cdist_dtw as dtw_distance Fixed the test for the KNeighborsTimeSeriesClassifier as ... 
Replacing undocumented python example for Sparse Euclidian Distance with a metaexample
20210107 08:54:07<div><p>Removed <code>.py</code> file. Added <code>.sg.in</code>...<p>Sorry for creating a new PR, had deleted the old branch by mistake.</p><p>该提问来源于开源项目：shoguntoolbox/shogun</p></div> 
Distance is broken when it is a query with listener
20201228 08:14:00<div><p>I am using this wonderful library and it works very well but I am having a problem, the distance is broken when a query is made with listener event. It actually breaks when a new element is ... 
Longdistance ranging with high precision using a soliton microcomb
20210125 23:21:27However, it is difficult for existing lidars to achieve high speed, high precision, and long distance simultaneously. Here, we demonstrate a highperformance lidar based on a chipscaled soliton ... 
A graph distance based metric for data oriented workflow retrieval with variable time constraints
20210206 16:28:13A graph distance based metric for data oriented workflow retrieval with variable time constraints 
Override 70m step distance with new argument 'step_distance'
20210107 11:24:44<p>Changed scandistance in config to a few random values, watched scans happen at larger intervals. <h2>Types of changes <ul><li>[ ] Bug fix (nonbreaking change which fixes an issue)</li><li>[ ] ... 
Navigation directions missing distance, Any other method that returns distance with directions?
20201208 22:55:56<p>I went through the documentation but was not able to find any method that returns distance corresponding to the particular Navigation instruction. Can you please help me figure this out , if ... 
[4.7.1] Max Comb distance with no Retract disables retraction
20210106 14:16:51A good default value for max comb distance with no retract or something that can warn the user about retraction (maybe in the tooltip of enable retraction?). It could make sense to make Max Comb ... 
LABELING PLANAR GRAPHS WITHOUT 4,5CYCLES WITH A CONDITION ON DISTANCE TWO
20210209 01:15:05LABELING PLANAR GRAPHS WITHOUT 4,5CYCLES WITH A CONDITION ON DISTANCE TWO 
Duplicated results when using geo_distance with sorted results
20210108 09:23:04I tried first with the GeoDistance <pre><code>python from elasticsearch_dsl.query import GeoDistance from apps.residences.search_index import ResidenceFr geo = GeoDistance(distance='10km... 
is it possible to use this with a distance matrix input?
20201225 22:27:49<div><p>Can I only provide a NxN matrix of pairwise distances, as in van der Maaten's <code>tsne_d</code> ? </p><p>该提问来源于开源项目：KlugerLab/FItSNE</p></div> 
Increase interaction distance with explosives from 1m to 1.5m.
20201204 18:56:54 Increase interaction distance with explosives from 1m to 1.5m.  Fix #3379 <p>It's a nice usability enhancement, that makes placing explosives quicker and more streamlined.</p><p>该提问来源于... 
Loopholes with distance 0
20201128 11:03:17<p>Itineraries are given as a short transit leg (often only two stops long), combined with one to many walk legs which all have in common that they have distance 0.0 and legGeometry/length 2. ... 
time dualwavelength digital holographic microscopy with a longworking distance objective
20210208 17:25:54We propose a compact dual wavelength digital holographic Microscopy (DHM).based on a long working distance objective, which enabling quantitative phase imaging of.opaque samples with extended ... 
distance calculations with point source
20201208 21:15:53<p>I am trying to simulate a point source in a 2D homogeneous media but I am getting some unexpected results for distances compared with the analytical solution. I am using skfmm version 2019.1.30, ... 
New Force from Partially Asymmetric Circuit Including a Capacitor with Large Electrode Distance
20200228 01:50:32含大电极距离电容器的局部非对称电路产生的新动力，徐跃，王海滨，含有大极板距离电容器的局部非对称电路中，由于位移电流和传导电流的不同，电路中能够产生新的动力。通过选择电路结构和元件参数 
Collision Prevention with distance sensor
20210110 03:34:27 start <code>cm8jl65</code> distance sensor with an orientation set by a parameter  add failsafe if the range data are stale. Go first into loiter</p><p>该提问来源于开源项目：PX4/Firmware</p>... 
Distance matrix calculations with a lot of locations rans node out of memory
20201208 22:40:58ve tried to calculate a large distance matrix (~121 049 points) using following code <pre><code> js osrm.table({ coordinates: points }, function(error, table) { if (error) { callback(error) } else ... 
Trip distance issue with teltonika device
20210107 02:58:47<div><p>I have some short trips with a teltonika device which are reporting as 0 for distance. Where can I start troubleshooting this? <p>I have attached a route and trip report for the affected ... 
Created a distance filter
20201125 16:53:25<p>I have created a distance filter which was requested in issue #2737. I am working on a software architecture project in TU Delft. My team created a number of architectural documents for c:geo ... 
I want to know how many distance calculations are needed to complete a query with fixed parameters
20201127 02:29:34<div><p>Hi, I want to know how many distance calculations are needed to complete a query with fixed parameters. How can I get this value? Do I need to change the source code? Another question is how ... 
A longdistance quantum key distribution scheme based on predetection of optical pulse with ...
20210222 02:19:50A longdistance quantum key distribution scheme based on predetection of optical pulse with auxiliary state 
Problem with distance measurement
20201209 10:14:36<p>I am trying your firmware on a WeMos D1 mini but I can't get it to work. <p>I am connecting the sensor as: <p>D1 GPIO5  68 SNS_TRIG D5 GPIO14  69 SNS_TRIG <p>I am getting wrong distance ....... 
Distance between points with transform
20201209 14:14:08<p>I have done the calculation with postGIS in a query window and gotten: 9052.83580248723 meters (using SRID 4326 to 2163 ST_Transform() and ST_Distance()) <p>I've done the calculation by ... 
1334. Find the City With the Smallest Number of Neighbors at a Threshold Distance
20200130 09:51:06Source: https://leetcode.com/contest/weeklycontest173/problems/findthecitywiththesmallestnumberofneighborsatathresholddistance/ There are n cities numbered from 0 to n1. Given the array...Source: https://leetcode.com/contest/weeklycontest173/problems/findthecitywiththesmallestnumberofneighborsatathresholddistance/
There are n cities numbered from 0 to n1. Given the array edges where edges[i] = [fromi, toi, weighti] represents a bidirectional and weighted edge between cities fromi and toi, and given the integer distanceThreshold.
Return the city with the smallest number of cities that are reachable through some path and whose distance is at most distanceThreshold, If there are multiple such cities, return the city with the greatest number.
Notice that the distance of a path connecting cities i and j is equal to the sum of the edges’ weights along that path.
Example 1:
Input: n = 4, edges = [[0,1,3],[1,2,1],[1,3,4],[2,3,1]], distanceThreshold = 4
Output: 3
Explanation: The figure above describes the graph.
The neighboring cities at a distanceThreshold = 4 for each city are:
City 0 > [City 1, City 2]
City 1 > [City 0, City 2, City 3]
City 2 > [City 0, City 1, City 3]
City 3 > [City 1, City 2]
Cities 0 and 3 have 2 neighboring cities at a distanceThreshold = 4, but we have to return city 3 since it has the greatest number.Example 2:
Input: n = 5, edges = [[0,1,2],[0,4,8],[1,2,3],[1,4,2],[2,3,1],[3,4,1]], distanceThreshold = 2
Output: 0
Explanation: The figure above describes the graph.
The neighboring cities at a distanceThreshold = 2 for each city are:
City 0 > [City 1]
City 1 > [City 0, City 4]
City 2 > [City 3, City 4]
City 3 > [City 2, City 4]
City 4 > [City 1, City 2, City 3]
The city 0 has 1 neighboring city at a distanceThreshold = 2.Constraints:
2 <= n <= 100
1 <= edges.length <= n * (n  1) / 2
edges[i].length == 3
0 <= fromi < toi < n
1 <= weighti, distanceThreshold <= 10^4
All pairs (fromi, toi) are distinct.思路：求出所有点之间最短路径长度，从而计算从各顶点出发可到达的distanceThreshold以内的点的数量，找出最大的即可，一样大的也更新，因为要下标大的。
class Solution { public: int adjmat[100][100]; int dist[100][100]; int mark[100]; int num[100]; void computedist(int n, int s){ memset(mark,0,sizeof(mark)); mark[s]=1; for(int i=0;i<n;i++){ dist[s][i]=adjmat[s][i]; } dist[s][s]=0; for(int k=0;k<n;k++){ int mindist=0x3f3f3f3f; int minidx; for(int i=0;i<n;i++){ if(dist[s][i]!=0x3f3f3f3f && mark[i]==0 && dist[s][i]<mindist){ mindist=dist[s][i]; minidx=i; } } mark[minidx]=1; for(int i=0;i<n;i++){ if(adjmat[minidx][i]!=0x3f3f3f3f && mark[i]==0 && adjmat[minidx][i]+dist[s][minidx]<dist[s][i]){ dist[s][i]=adjmat[minidx][i]+dist[s][minidx]; } } } } int findTheCity(int n, vector<vector<int>>& edges, int distanceThreshold) { int numedge=edges.size(); for(int i=0;i<n;i++){ for(int j=0;j<n;j++){ adjmat[i][j]=0x3f3f3f3f; } } for(int i=0;i<numedge;i++){ adjmat[edges[i][0]][edges[i][1]]=edges[i][2]; adjmat[edges[i][1]][edges[i][0]]=edges[i][2]; } memset(num,0,sizeof(num)); int minnum=105; int ans; for(int i=0;i<n;i++){ computedist(n,i); for(int j=0;j<n;j++){ if(dist[i][j]<=distanceThreshold){ num[i]++; } } if(num[i]<=minnum){ minnum=num[i]; ans=i; } } return ans; } };