精华内容
下载资源
问答
  • Measure distance with a HC-SR04 ultrasonic sensor" and it's working. Thanks for that. <p>Nevertheless, i don't understand the syntax of this part of code: We declare an async anonymous ...
  • <p>In particular, I ran into an error with step_distance when I updated one of my printers a few weeks ago. I went from an old 8-bit control board using 8 microsteps to a newer board with tmc2208 ...
  • To allow negative distance values, you must explicitly pass in a `Distance` object with the the argument 'allow_negative=True'. </module></ipython-input-3-bc5d4ae3542b>...
  • * I have a space with only categorical variables (most of them containing integers admittedly) * ask and tell API is used with an gp optimizer <p>The first <code>n_initial_points</code>-many points ...
  • <p>Changed the dtw function from <code>sktime.distances.elastic_cython</code> to <code>from tslearn.metrics import cdist_dtw as dtw_distance Fixed the test for the KNeighborsTimeSeriesClassifier as ...
  • <div><p>Removed <code>.py</code> file. Added <code>.sg.in</code>...<p>Sorry for creating a new PR, had deleted the old branch by mistake.</p><p>该提问来源于开源项目:shogun-toolbox/shogun</p></div>
  • <div><p>I am using this wonderful library and it works very well but I am having a problem, the distance is broken when a query is made with listener event. It actually breaks when a new element is ...
  • However, it is difficult for existing lidars to achieve high speed, high precision, and long distance simultaneously. Here, we demonstrate a high-performance lidar based on a chip-scaled soliton ...
  • A graph distance based metric for data oriented workflow retrieval with variable time constraints
  • <p>Changed scan-distance in config to a few random values, watched scans happen at larger intervals. <h2>Types of changes <ul><li>[ ] Bug fix (non-breaking change which fixes an issue)</li><li>[ ] ...
  • <p>I went through the documentation but was not able to find any method that returns distance corresponding to the particular Navigation instruction. Can you please help me figure this out , if ...
  • A good default value for max comb distance with no retract or something that can warn the user about retraction (maybe in the tooltip of enable retraction?). It could make sense to make Max Comb ...
  • LABELING PLANAR GRAPHS WITHOUT 4,5-CYCLES WITH A CONDITION ON DISTANCE TWO
  • I tried first with the GeoDistance <pre><code>python from elasticsearch_dsl.query import GeoDistance from apps.residences.search_index import ResidenceFr geo = GeoDistance(distance='10km...
  • <div><p>Can I only provide a NxN matrix of pairwise distances, as in van der Maaten's <code>tsne_d</code> ? </p><p>该提问来源于开源项目:KlugerLab/FIt-SNE</p></div>
  • - Increase interaction distance with explosives from 1m to 1.5m. - Fix #3379 <p>It's a nice usability enhancement, that makes placing explosives quicker and more streamlined.</p><p>该提问来源于...
  • Loopholes with distance 0

    2020-11-28 11:03:17
    <p>Itineraries are given as a short transit leg (often only two stops long), combined with one to many walk legs which all have in common that they have distance 0.0 and legGeometry/length 2. ...
  • We propose a compact dual wavelength digital holographic Microscopy (DHM).based on a long working distance objective, which enabling quantitative phase imaging of.opaque samples with extended ...
  • <p>I am trying to simulate a point source in a 2D homogeneous media but I am getting some unexpected results for distances compared with the analytical solution. I am using skfmm version 2019.1.30, ...
  • 含大电极距离电容器的局部非对称电路产生的新动力,徐跃,王海滨,含有大极板距离电容器的局部非对称电路中,由于位移电流和传导电流的不同,电路中能够产生新的动力。通过选择电路结构和元件参数
  • - start <code>cm8jl65</code> distance sensor with an orientation set by a parameter - add failsafe if the range data are stale. Go first into loiter</p><p>该提问来源于开源项目:PX4/Firmware</p>...
  • ve tried to calculate a large distance matrix (~121 049 points) using following code <pre><code> js osrm.table({ coordinates: points }, function(error, table) { if (error) { callback(error) } else ...
  • <div><p>I have some short trips with a teltonika device which are reporting as 0 for distance. Where can I start troubleshooting this? <p>I have attached a route and trip report for the affected ...
  • Created a distance filter

    2020-11-25 16:53:25
    <p>I have created a distance filter which was requested in issue #2737. I am working on a software architecture project in TU Delft. My team created a number of architectural documents for c:geo ...
  • <div><p>Hi, I want to know how many distance calculations are needed to complete a query with fixed parameters. How can I get this value? Do I need to change the source code? Another question is how ...
  • A long-distance quantum key distribution scheme based on pre-detection of optical pulse with auxiliary state
  • <p>I am trying your firmware on a WeMos D1 mini but I can't get it to work. <p>I am connecting the sensor as: <p>D1 GPIO5 - 68 SNS_TRIG D5 GPIO14 - 69 SNS_TRIG <p>I am getting wrong distance .......
  • <p>I have done the calculation with postGIS in a query window and gotten: 9052.83580248723 meters (using SRID 4326 to 2163 ST_Transform() and ST_Distance()) <p>I've done the calculation by ...
  • Source: https://leetcode.com/contest/weekly-contest-173/problems/find-the-city-with-the-smallest-number-of-neighbors-at-a-threshold-distance/ There are n cities numbered from 0 to n-1. Given the array...

    Source: https://leetcode.com/contest/weekly-contest-173/problems/find-the-city-with-the-smallest-number-of-neighbors-at-a-threshold-distance/

    There are n cities numbered from 0 to n-1. Given the array edges where edges[i] = [fromi, toi, weighti] represents a bidirectional and weighted edge between cities fromi and toi, and given the integer distanceThreshold.

    Return the city with the smallest number of cities that are reachable through some path and whose distance is at most distanceThreshold, If there are multiple such cities, return the city with the greatest number.

    Notice that the distance of a path connecting cities i and j is equal to the sum of the edges’ weights along that path.

    Example 1:

    在这里插入图片描述

    Input: n = 4, edges = [[0,1,3],[1,2,1],[1,3,4],[2,3,1]], distanceThreshold = 4
    Output: 3
    Explanation: The figure above describes the graph.
    The neighboring cities at a distanceThreshold = 4 for each city are:
    City 0 -> [City 1, City 2]
    City 1 -> [City 0, City 2, City 3]
    City 2 -> [City 0, City 1, City 3]
    City 3 -> [City 1, City 2]
    Cities 0 and 3 have 2 neighboring cities at a distanceThreshold = 4, but we have to return city 3 since it has the greatest number.

    Example 2:

    在这里插入图片描述

    Input: n = 5, edges = [[0,1,2],[0,4,8],[1,2,3],[1,4,2],[2,3,1],[3,4,1]], distanceThreshold = 2
    Output: 0
    Explanation: The figure above describes the graph.
    The neighboring cities at a distanceThreshold = 2 for each city are:
    City 0 -> [City 1]
    City 1 -> [City 0, City 4]
    City 2 -> [City 3, City 4]
    City 3 -> [City 2, City 4]
    City 4 -> [City 1, City 2, City 3]
    The city 0 has 1 neighboring city at a distanceThreshold = 2.

    Constraints:

    2 <= n <= 100
    1 <= edges.length <= n * (n - 1) / 2
    edges[i].length == 3
    0 <= fromi < toi < n
    1 <= weighti, distanceThreshold <= 10^4
    All pairs (fromi, toi) are distinct.

    思路:求出所有点之间最短路径长度,从而计算从各顶点出发可到达的distanceThreshold以内的点的数量,找出最大的即可,一样大的也更新,因为要下标大的。

    class Solution {
    public:
        int adjmat[100][100];
        int dist[100][100];
        int mark[100];
        int num[100];
        void computedist(int n, int s){
            memset(mark,0,sizeof(mark));
            mark[s]=1;
            for(int i=0;i<n;i++){
                dist[s][i]=adjmat[s][i];
            }
            dist[s][s]=0;
            
            for(int k=0;k<n;k++){
                int mindist=0x3f3f3f3f;
                int minidx;
                for(int i=0;i<n;i++){
                    if(dist[s][i]!=0x3f3f3f3f && mark[i]==0 && dist[s][i]<mindist){
                        mindist=dist[s][i];
                        minidx=i;
                    }
                }
                mark[minidx]=1;
                for(int i=0;i<n;i++){
                    if(adjmat[minidx][i]!=0x3f3f3f3f && mark[i]==0 && adjmat[minidx][i]+dist[s][minidx]<dist[s][i]){
                        dist[s][i]=adjmat[minidx][i]+dist[s][minidx];
                    }
                }
                
            }
        }
        int findTheCity(int n, vector<vector<int>>& edges, int distanceThreshold) {
            int numedge=edges.size();
            for(int i=0;i<n;i++){
                for(int j=0;j<n;j++){
                    adjmat[i][j]=0x3f3f3f3f;
                }
            }
            for(int i=0;i<numedge;i++){
                adjmat[edges[i][0]][edges[i][1]]=edges[i][2];
                adjmat[edges[i][1]][edges[i][0]]=edges[i][2];
            }
            memset(num,0,sizeof(num));
            int minnum=105;
            int ans;
            for(int i=0;i<n;i++){
                computedist(n,i);
                for(int j=0;j<n;j++){
                    if(dist[i][j]<=distanceThreshold){
                        num[i]++;
                    }
                }
                if(num[i]<=minnum){
                    minnum=num[i];
                    ans=i;
                }
            }
            
            return ans;
        }
    };
    
    展开全文

空空如也

空空如也

1 2 3 4 5 ... 20
收藏数 10,332
精华内容 4,132
关键字:

adistancewith