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  • The unstable-resonator spatially enhanced detection (USED) coherent anti-stokes Raman spectroscopy (CARS) measurements of temperature and N_(2) concentration in the combustion of solid propellant at ...
  • 建立的宽带CARS实验系统采用非稳腔空间增强探测(USED)相位匹配构造,其横向空间分辨率约0.1 mm,纵向空间分辨率约3 mm,该系统能实现10 Hz重复频率测量火焰瞬时温度。采用宽带非稳腔空间增强探测CARS在甲烷-空气预混...
  • Anti Lock Brakes for cars

    2020-11-30 15:21:20
    <div><p>Hi <p>I useOpen TX with ...<p>Is there a way of doing this easily ordo you need to add a feature to Open TX so it can be used? <p>Thanks</p><p>该提问来源于开源项目:opentx/opentx</p></div>
  • <div><p>This technique is used in #2542 and in SpringMassSystem. Maybe it's useful for the migration to System 2.0?</p><p>该提问来源于开源项目:RobotLocomotion/drake</p></div>
  • I think cars will prefer to use the shortest distance without taking into account the cars that could block their path (taking more time) resulting in vehicles all choosing the same lane. <p>I mean, ...
  • <div><p>The cars are glitched in Daytona USA. What used to run perfectly now looks like this ...
  • <p>My bmw.py from https://github.com/ipv6freely/bmw2018 and modify for my used. I want to use bimmer_connected <p>Thanks thanks Havrla</p><p>该提问来源于开源项目:bimmerconnected/bimmer_...
  • ⠀⠀⠀[x] <strong>Allow bus lanes near junctions to be used as turning lanes</strong></li><li>The new option would auto-remove the vehicle restrictions from bus lanes on segments at junctions (user ...
  • Whether you're casually browsing and researching or shopping for your next car, Edmunds is here to help. We make car buying ... Tap into a huge selection of new and used vehicles near you. Unlock in...

    Whether you're casually browsing and researching or shopping for your next car, Edmunds is here to help. We make car buying easy. Tap into a huge selection of new and used vehicles near you. Unlock instant savings and find available incentives. Let our experts guide you. Read reviews and see what others nearby paid for your perfect car. Buy with confidence. Estimate monthly payments and know what dealers will offer for your trade-in.

    Named one of the top 10 car-buying apps by Nerdwallet and Marketwatch!

    We draw on decades of automotive experience to leverage our extensive network of new car and used car dealers to help save you thousands. Browse our used cars for sale and new cars for sale today and let us know what you think.

    With this app you can:

    BROWSE THE LARGEST SELECTION OF NEW & USED CARS LISTINGS

    Search our network of nationwide inventory. Narrow down your search with our extensive filters including: price range, new/used/cpo, exterior and interior colors, years, model type, body type, trim, options & packages, features, Edmunds deal ratings, Edmunds special offers, engine, transmission, drive train, fuel type, and vehicle history. We show you the best matches first!

    VIEW PRICING, VEHICLE HISTORY, & INSTALLED FEATURES/OPTIONS ON INVENTORY LISTINGS

    See a detailed price analysis including whether we think it's a great, good, or fair deal as well as the average price paid for new cars. We strengthen your negotiating power by letting you know how long a car has been on the lot and history of any price changes. For used and cpo cars, we let you know owner, accident and usage history as well as if buyback protection is provided (where available). View all installed options and corresponding prices on the listing details page.

    GET SPECIAL OFFERS AND PRICE QUOTES

    Text, call or connect with dealers to check availability or obtain an Edmunds special offer to save up to thousands off MSRP.

    SAVE YOUR FAVORITES

    Save your searches as well as your favorite cars for sale to quickly get back to them at any time.

    CALCULATE PAYMENTS

    Use our extensive loan and lease payment calculators to quickly determine your monthly payment before heading to the dealer.

    RESEARCH

    Read Edmunds' expert reviews on thousands of cars and check out our latest videos all in the app. See the latest incentives, consumer reviews, safety ratings, features and specs, True Cost to Own® and photo galleries all on the research tab. You can also write a review for a car right in the app!

    APPRAISE YOUR CAR

    Find out the trade-in, private party, and dealer retail prices for your car.

    FIND A DEALER

    Browse our massive dealer network to find the best dealer near you. Check out sales and service reviews. Call, text, or get directions to the dealership. Check out hours of operation as well as various amenities the dealer has to offer.

    CAN IT FIT?

    Before heading to the dealer, see if a car will fit in your space! Our AR garage experience lets you visualize most cars in your space and will let you know if it fits!

    ON THE LOT

    Get notified of unlocked special offers when you enter a dealer lot. Search vins, stock numbers, colors, models or years to locate your car on a dealer lot.

    COMPARE

    Quickly compare cars side-by-side on data points such as price, consumer reviews, Edmunds rating, engine, horsepower, torque, transmission, drive train, EPA mileage, range, fuel capacity, included features, warranty, cargo capacity, seating capacity, and vehicle dimensions.

    Let us know what you think! If you need help or just have a suggestion or feedback, tap the help button on the settings screen.

    展开全文
  • This network combines residual learning with Inception-style layers and is used to count cars in one look. This is a new way to count objects rather than by localization or density estima

    这篇文章值得关注的点:

    1. This network combines residual learning with Inception-style layers and is used to count cars in one look. This is a new way to count objects rather than by localization or density estimation.

    2. The counting method is not car or scene specific. It would be easy to train this method to count other kinds of objects and counting over new scenes requires no extra set up or assumptions about object locations.

    3.COWC数据集:
    3.1 The image set is annotated by single pixel points, 不用处理车辆大小不变性,因为地图的空间分辨率作为先验信息。
    3.2 Large trucks are completely omitted since it can be unclear when something stops being a light vehicle and starts to become a truck. Vans and pickups are included as cars even
    if they are large. All boats, trailers and construction vehicles are always added as negatives.
    3.3 生成红色部分是测试集,蓝色部分是训练集。不觉得这样的选取很奇怪吗!!!
    这里写图片描述
    3.4 验证集的图片来自犹他州,图片内容与训练集的差别很大
    3.5 训练集大小256X256, 每15度旋转扩充训练集,This yielded a set of 308,988 training
    patches and 79,447 testing patches.Patch中间区域48 × 48 有车辆才认为有车,所以负样本里面也有车。此外,边缘处的32个像素灰色处理,因为这样实验对比出来,模型性能最好(An edge margin of 32 pixels was grayed out in each patch)。
    4.The ResCeption network: We created a third network to synthesize Residual Learning [26] with Inception. We called this one ResCeption network.与标准的残差网络不一样的地方是增加了projection shortcut.
    这里写图片描述
    5. 对比试验与本文的方法在caffe上完成,AlexNet、GoogLeNet/Inception、ResCeption network。
    6.
    这里写图片描述
    patch边缘灰化对性能的影响1%左右,作者认为上下文场景太多对车辆有不好的提示。
    (That we can have too much context might be a result of too much irrelevant information or
    bad hints from objects that are too far from a car.)
    7. 测试用10张图片,滑动窗口的方式,窗口大小224X224,32像素的灰化区域, 步长8个像素。极大值抑制阈值0.75。Verification测试标准下,split和merge都没有计入(TP - x)/(TP+FP - 2x),所以值较大相比正常的统计TP/(TP+FP)

    这里写图片描述

    这里写图片描述

    Q:发现没有correct = (TP+TN)/(TP+TN+FP+FN);F = 2*P*R/(P+R),可table2竟然拿这两个指标对比(Ideally the verification score should …)。

    8. 计数,每个patch,车辆中心至少八个像素才算,整个网络变成一个回归问题,64个输出,表示一个patch可以输出最多64辆车。试验在GoogleNet(22层),
    这里写图片描述

    展开全文
  • <div><p>Column attribute is not used in case of join <p>var user = await _db.Users.FindByIdAsync(1, x => x.Cars); <pre><code> [Table("Cars")] public class Car : BaseEntity<int...
  • GSdx OGL HW (no graphical bugs, so default settings are used), SPU2-X, LilyPad, Gigaherz CDVD, the rest are null plugins. <p><strong><em>Description of the issue:</em></strong> During gameplay, player...
  • <p>I am trying to get the total count for new and used cars from the column "type" in a csv file. I output the data fine but cant seem to figure out out to split up the new and used count.. <p>Here ...
  • other: %{count} cars es: car: one: other: </code></pre> <p>If I run <pre><code> I18n.locale = :es I18n.t 'car', count: 2 </code></pre> <p>I get this exception <pre><code> Runtime...
  • Linked to a charger I am playing project cars2. On 30 mbps and HEVC codec I can play for a while longer but eventually it will still crash. Increasing the speed increases the quality of the video ...
  • in which one (1) statically allocated array of pointers to base class, with the capacity of 15, is used to keep / store all the cars. In the car container class, you shall also implement copy ...
  • These days, many carmakers are developing cars that run on electricity instead of ... The batteries used in these cars are generally very heavy and expensive, so designers must make an important...

    These days, many carmakers are developing cars that run on electricity instead of gasoline. The batteries used in these cars are generally very heavy and expensive, so designers must make an important tradeoffs when determining the battery capacity, and therefore the range, of these vehicles. Your task is to help determine the minimum range necessary so that it is possible for the car to travel between any two cities on the continent.

        The road network on the continent consists of cities connected by bidirectional roads of different lengths. Each city contains a charging station. Along a route between two cities, the car may pass through any number of cities, but the distance between each pair of consecutive cities along the route must be no longer than the range of the car. What is the minimum range of the car so that there is a route satisfying this constraint between every pair of cities on the continent?
    Input
    The input consists of a sequence of road networks. The first line of each road network contains two positive integers n and m, the number of cities and roads. Each of these integers is no larger than one million. The cities are numbered from 0 to n − 1. The first line is followed by m more lines, each describing a road. Each such line contains three non-negative integers. The first two integers are the numbers of the two cities connected by the road. The third integer is the length of the road. The last road network is followed by a line containing two zeros, indicating the end of the input.
    Output
    For each road network, output a line containing one integer, the minimum range of the car that enables it to drive from every city to every other city. If it is not possible to drive from some city to some other city regardless of the range of the car, instead output a line containing the word ‘IMPOSSIBLE’.
    Sample Input
    3 3
    0 1 3
    1 2 4
    2 1 5
    2 0
    0 0
    Sample Output
    4
    IMPOSSIBLE

    问题链接UVA11857 HDU3742 Driving Range
    问题简述:(略)
    问题分析:简单题,不解释看代码,用Kruskal算法解决。
    程序说明:(略)
    参考链接:(略)
    题记:(略)

    AC的C++语言程序如下:

    /* UVA11857 HDU3742 Driving Range */
    
    #include <bits/stdc++.h>
    
    using namespace std;
    
    const int N = 1000000;
    struct Edge { int u, v, w;} e[N];
    bool cmp ( Edge a, Edge b ) {  return a.w < b.w; }
    int f[N + 1], fcnt;
    void UFInit(int n) {for(int i = 0; i <= n; i++) f[i] = i; fcnt = n;}
    int Find(int a) {return a == f[a] ? a : f[a] = Find(f[a]);}
    
    int main()
    {
        int n, m;
        while(~scanf("%d%d", &n, &m) && (n || m)) {
            for(int i = 0; i < m; i++)
                scanf("%d%d%d", &e[i].u, &e[i].v, &e[i].w);
    
            UFInit(n);
    
            // Kruskal算法
            sort(e, e + m, cmp);
            int ans;
            for(int i = 0; i < m; i++) {
                int u = Find(e[i].u);
                int v = Find(e[i].v);
                if ( u != v ) {
                    f[u] = v;
                    ans = e[i].w;
                    if(--fcnt == 1) break;
                }
            }
    
            if(fcnt == 1) printf("%d\n", ans);
            else printf("IMPOSSIBLE\n");
        }
    
        return 0;
    }
    
    展开全文
  • These days, many carmakers are developing cars that run on electricityinstead of gasoline. The batteries used in these cars are generallyvery heavy and expensive, so designers must make an important t

    These days, many carmakers are developing cars that run on electricityinstead of gasoline. The batteries used in these cars are generallyvery heavy and expensive, so designers must make an important tradeoffswhen determining the battery capacity, and therefore the range, of thesevehicles. Your task is to help determine the minimum range necessaryso that it is possible for the car to travel between any two cities onthe continent.

    The road network on the continent consists of cities connected bybidirectional roads of different lengths. Each city contains a charging station.Along a route between two cities, the car may pass through anynumber of cities, but the distance between each pair of consecutivecities along the route must be no longer than the range of the car.What is the minimum range of the car so that there is a routesatisfying this constraint between every pair of cities on the continent?

    Input Specification

    The input consists of a sequence of road networks.The first line of each road network contains two positive integersn and m, the number of cities and roads.Each of these integers is no larger than one million.The cities are numbered from 0 to n-1.The first line is followed by m more lines,each describing a road. Each such line contains three non-negativeintegers. The first two integers are the numbers of the two citiesconnected by the road. The third integer is the length of the road.The last road network is followed by a line containing two zeros,indicating the end of the input.

    Sample Input

    3 3
    0 1 3
    1 2 4
    2 1 5
    2 0
    0 0
    

    Output Specification

    For each road network, output a line containing one integer,the minimum range of the car that enables it to drive from everycity to every other city. If it is not possible to drive fromsome city to some other city regardless of the range of thecar, instead output a line containing the word IMPOSSIBLE.

    Output for Sample Input

    4
    IMPOSSIBLE
    
    题意:给出n个点及m个路径,求构成的图连通的最大的边的值

    思路:Kruskal算法,先将边排序,然后用并查集。如果并查集的集合的个数与n相等,说明是可行的

    #include <cstdio>
    #include <vector>
    #include <utility>
    #include <queue>
    
    using namespace std;
    
    class UnionFindSet
    {
    public:
        UnionFindSet(int size = 0);
        int find(int a);
        bool isSameSet(int a, int b);
        void unionSet(int a, int b);
        int numDisjointSets();
        int sizeOfSet(int a);
        void setSize(int n);
        void init(int size);
    private:
        int size;
        vector<int> pset;
        vector<int> set_size;
    };
    
    void UnionFindSet::init(int size)
    {
        this->size = size;
        pset.assign(size, 0);
        set_size.assign(size, 1);
        
        for (int i = 0; i < size; i++) {
            pset[i] = i;
        }
    }
    
    UnionFindSet::UnionFindSet(int size)
    {
        init(size);
    }
    
    int UnionFindSet::find(int a)
    {
        return pset[a] == a ? a : (pset[a] = find(pset[a]));
    }
    
    bool UnionFindSet::isSameSet(int a, int b)
    {
        return find(a) == find(b);
    }
    
    void UnionFindSet::unionSet(int a, int b)
    {
        if (isSameSet(a, b)) return;
        
        size--;
        set_size[find(a)] += set_size[find(b)];
        pset[find(b)] = pset[find(a)];
    }
    
    int UnionFindSet::numDisjointSets()
    {
        return size;
    }
    int UnionFindSet::sizeOfSet(int a)
    {
        return set_size[find(a)];
    }
    
    void UnionFindSet::setSize(int n)
    {
        init(n);
    }
    
    int n, m;
    UnionFindSet unionSet;
    
    bool input()
    {
        scanf("%d%d", &n, &m);
        if (n == 0 && m == 0) return false;
        
        unionSet.setSize(n);
        return true;
    }
    
    void solve()
    {
        int a, b, c;
        priority_queue< pair<int, pair<int, int> > > edgeList;
        
        for (int i = 0; i < m; i++) {
            scanf("%d%d%d", &a, &b, &c);
            edgeList.push(make_pair(-c, make_pair(a, b)));
        }
      
        int ans = 0;
        while (!edgeList.empty()) {
            pair<int, pair<int, int> > edge = edgeList.top(); edgeList.pop();
            if (!unionSet.isSameSet(edge.second.first, edge.second.second)) {
                if (-edge.first > ans) {
                    ans = -edge.first;
                }
                unionSet.unionSet(edge.second.first, edge.second.second);
            } 
        }
       
        if (unionSet.sizeOfSet(0) != n) {
            printf("IMPOSSIBLE\n");
        } else {
            printf("%d\n", ans);
        }
    }
    
    int main() 
    {
    #ifndef ONLINE_JUDGE
        freopen("d:\\OJ\\uva_in.txt", "r", stdin);
    #endif
       
        while (input()) {
            solve();
        }
        return 0;
    }
    
    


    展开全文
  • Before bridges were common, ferries were used to transport cars across rivers. River ferries, unlike their larger cousins, run on a guide line and are powered by the river’s current. Cars drive onto ...
  • 快排递归非递归pythonRecurrent neural networks are deep learning models that are typically used to solve time series... They are used in self-driving cars, high-frequency trading algorithms, and other ...
  • 贪心 1014

    2016-03-21 08:58:07
    Before bridges were common, ferries were used to transport cars across rivers. River ferries, unlike their larger cousins, run on a guide line and are powered by the river's current. Cars drive onto t
  • curl-7.69.1.zip

    2020-03-26 22:54:39
    It is also used in cars, television sets, routers, printers, audio equipment, mobile phones, tablets, settop boxes, media players and is the internet transfer backbone for thousands of software ...
  • Before bridges were common, ferries were used to transport cars across rivers. River ferries, unlike their larger cousins, run on a guide line and are powered by the river’s current. Cars drive onto ...
  • Before bridges were common, ferries were used to transport cars across rivers. River ferries, unlike their larger cousins, run on a guide line and are powered by the river’s current. Cars drive onto ...
  • Before bridges were common, ferries were used to transport cars across rivers. River ferries, unlike their larger cousins, run on a guide line and are powered by the river's current. Cars drive onto ...
  • Before bridges were common, ferries were used to transport cars across rivers. River ferries, unlike their larger cousins, run on a guide line and are powered by the river’s current. Cars driv...
  • curl-7.59.0

    2018-04-26 20:38:35
    It is also used in cars, television sets, routers, printers, audio equipment, mobile phones, tablets, settop boxes, media players and is the internet transfer backbone for thousands of software ...
  • Before bridges were common, ferries were used to transport cars across rivers. River ferries, unlike their larger cousins, run on a guide line and are powered by the river’s current. Cars drive onto ...

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