• <div><p>I am using two Raspberrys in my network with pi-hole installation. <em>No. 1</em> is for normal use and my DHCP-Server point to it <em>No. 2</em> for testing and development. <p>Now I get the ...
• <div><p>Given, wkt = new jsts.io.WKTReader(), A = wkt.read("POLYGON((0 0, 0 8, 8 8, 8 0, 0 0), (4 4, 2 4, 2 6, 6 6, 6 2, 4 2, 4 4))"); B = wkt.read("POLYGON((4 4, 4 6, 6 6, 6 4...
• The L-integral description for a brittle elastic plane with two holes before, during, and after coalescence，胡义峰，陈宜亨，This paper extends the L-integral concept [1-3] to study the degradation of...
• Cura can see the two holes but I cant print the unit with the 2 holes. The unit is constructed with Rhino5. Regards Hg <p><img alt="holes2" src=...
• [ RUN ] frag_list.two_holes_advanced /scrap/jenkins/workspace/hpc-ucx-pr-7/label/hpc-arm-cavium-jenkins/worker/3/contrib/../test/gtest/ucs/test_frag_list.cc:282: Failure Value of: i Actual: 5 ...
• <div><p>Now that we have or will soon have the ability to place orders using the orderbook an not only the top order another useful feature would be the ability for the bot to fill holes on the order...
• s two examples that bypass the <a href="https://github.com/inducer/relate/blob/master/course/page/code_feedback.py#L135">scalar value check, tested on CS357 quiz 17: <pre><code> # Type not being ...
• <p>I have gone over this several times and it seems that as soon as I move these two object around the block gets corrupted. The base file also gets screwed. <p>/tmp/guide-block-assy-OK-collection.gz...
• Cura puts correctly creates the top layers of the bottom of the cup, but then puts two solid layers on top of them, covering the holes. See the picture. <p><img alt="image" src=...
• <p>I think I could also get the code to work with only two peg holes, but have not tried yet. It might help people try out toonz (a pegbar can be easily created with a 3d-printer), but it would be ...
• <div><p>Implementation to milldrill holes with helixes as discussed in Issue #223. <p>Helix starts one step above Z0 for optimal work piece entry and makes a flat circle at the bottom. <p>This leads ...
• I have two of these T265 cameras and both holes only catch on the last thread, or not at all. I have tried a number of different M3(0.5 pitch) screws and they all act the same. I don't have an ...
• The coords now contain a nan separator and there are two separate lists of holes, one the same as above the second empty: <pre><code>python coords = [(1, 2), (2, 0), (3, 7), (np.nan, np.nan), (6,...
• <p>Additionally there is a consequence for proxies: because holes are checked via HasProperty before doing the GetProperty, a weird proxy could respond inconsistently between the two (e.g. <code>proxy...
• m here to report two issues with vase mode. <strong>1. "Dots"</strong> When I turn vase on for this model, it generates some <strong>"dots"</strong> over the inner part of the model,...
• B - HolesTime limit : 2sec / Memory limit : 256MBScore : 600 pointsProblem StatementThere are N holes in a two-dimensional plane. The coordinates of the i-th hole are (xi,yi).Let R=10101010....
B - HolesTime limit : 2sec / Memory limit : 256MBScore : 600 pointsProblem StatementThere are N holes in a two-dimensional plane. The coordinates of the i-th hole are (xi,yi).Let R=10101010. Ringo performs the following operation:Randomly choose a point from the interior of a circle of radius R centered at the origin, and put Snuke there. Snuke will move to the hole with the smallest Euclidean distance from the point, and fall into that hole. If there are multiple such holes, the hole with the smallest index will be chosen.For every i (1≤i≤N), find the probability that Snuke falls into the i-th hole.Here, the operation of randomly choosing a point from the interior of a circle of radius R is defined as follows:Pick two real numbers x and y independently according to uniform distribution on [−R,R].If x2+y2≤R2, the point (x,y) is chosen. Otherwise, repeat picking the real numbers x,y until the condition is met.Constraints2≤N≤100|xi|,|yi|≤106(1≤i≤N)All given points are pairwise distinct.All input values are integers.InputInput is given from Standard Input in the following format:N
x1 y1
:
xN yN
OutputPrint N real numbers. The i-th real number must represent the probability that Snuke falls into the i-th hole.The output will be judged correct when, for all output values, the absolute or relative error is at most 10−5.Sample Input 1Copy2
0 0
1 1
Sample Output 1Copy0.5
0.5
If Ringo put Snuke in the region x+y≤1, Snuke will fall into the first hole. The probability of this happening is very close to 0.5. Otherwise, Snuke will fall into the second hole, the probability of which happening is also very close to 0.5.Sample Input 2Copy5
0 0
2 8
4 5
2 6
3 10
Sample Output 2Copy0.43160120892732328768
0.03480224363653196956
0.13880483535586193855
0.00000000000000000000
0.39479171208028279727【思路】由于给定范围可以视作无穷大，在所选的点的凸包的范围外的面积远大于凸包内，我们只需要考虑落在凸包上的点就好，因为在无穷大的区域里随机选点最近点是凸包内部点的概率无限趋近于0。因此先用Graham扫描法求凸包，注意保留落在边上的点，再求凸包各边指向外外部的法向量的夹角占2π的比例，最后按顺序输出即可。【代码】//************************************************************************
// File Name: F.cpp
// Author: Shili_Xu
// E-Mail: shili_xu@qq.com
// Created Time: 2018年03月24日 星期六 22时32分59秒
//************************************************************************

#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
using namespace std;

const double EPS = 1e-8, PI = acos(-1);
const int MAXN = 105;

struct point {
double x, y;
int id;

point() {}
point(double _x, double _y, int _id = -1) : x(_x), y(_y), id(_id) {}
bool operator<(const point &another) const;
};

struct ans {
double val;
int id;

ans() {}
bool operator<(const ans &another) const
{
return id < another.id;
}
};

int tot, n;
point p[MAXN], s[MAXN], normal[MAXN];
ans an[MAXN];
bool visited[MAXN];

int sgn(double x)
{
if (fabs(x) < EPS) return 0;
return (x > 0 ? 1 : -1);
}

double det(const point &a1, const point &a2, const point &b1, const point &b2)
{
return ((a2.x - a1.x) * (b2.y - b1.y) - (a2.y - a1.y) * (b2.x - b1.x));
}

double dot(const point &a1, const point &a2, const point &b1, const point &b2)
{
return ((a2.x - a1.x) * (b2.x - b1.x) + (a2.y - a1.y) * (b2.y - b1.y));
}

double dist(const point &p1, const point &p2)
{
return sqrt((p2.x - p1.x) * (p2.x - p1.x) + (p2.y - p1.y) * (p2.y - p1.y));
}

bool point::operator<(const point &another) const
{
if (sgn(det(p[0], *this, p[0], another)) == 0)
return dist(p[0], *this) < dist(p[0], another);
else
return det(p[0], *this, p[0], another) > 0;
}

void graham()
{
double min_y = p[0].y, min_x = p[0].x;
int index = 0;
for (int i = 1; i <= n - 1; i++) {
if (p[i].y < min_y || (sgn(p[i].y - min_y) == 0 && p[i].x < min_x)) {
min_y = p[i].y;
min_x = p[i].x;
index = i;
}
}
swap(p[0], p[index]);
sort(p + 1, p + n);
s[0] = p[0]; s[1] = p[1];
tot = 2;
for (int i = 2; i <= n - 1; i++) {
while (tot >= 2 && sgn(det(s[tot - 1], p[i], s[tot - 1], s[tot - 2]) < 0)) tot--;
s[tot++] = p[i];
}
}

int main()
{
scanf("%d", &n);
for (int i = 0; i < n; i++) {
scanf("%lf %lf", &p[i].x, &p[i].y);
p[i].id = i;
}
graham();
for (int i = 0; i < tot; i++) {
if (i == 0) {
normal[i].y = -(s[i].x - s[tot - 1].x);
normal[i].x = s[i].y - s[tot - 1].y;
normal[i].id = s[i].id;
}
else {
normal[i].y = -(s[i].x - s[i - 1].x);
normal[i].x = s[i].y - s[i - 1].y;
normal[i].id = s[i].id;
}
}
point zero(0, 0);
for (int i = 0; i < tot; i++) {
if (i == tot - 1) {
an[i].val = acos(dot(zero, normal[i], zero, normal[0]) / dist(zero, normal[i]) / dist(zero, normal[0])) / PI / 2;
an[i].id = normal[i].id;
}
else {
an[i].val = acos(dot(zero, normal[i], zero, normal[i + 1]) / dist(zero, normal[i]) / dist(zero, normal[i + 1])) / PI / 2;
an[i].id = normal[i].id;
}
}
memset(visited, false, sizeof(visited));
for (int i = 0; i < tot; i++) visited[s[i].id] = true;
for (int i = 0; i < n; i++)
if (!visited[i]) {
an[tot].val = 0.0000000;
an[tot++].id = i;
}
sort(an, an + n);
for (int i = 0; i < n; i++) printf("%.8f\n", an[i].val);
return 0;
}

展开全文
• If the two triangles abutting a segment are eaten, the segment itself is also eaten. Do not place a hole directly on a segment; if you do, Triangle will choose one side of the segment arbitrarily. ...
• seems to end up in osmnx as two individual building polygons on top of each other. This leads to holes in buildings actually being double counted as building area sometimes generating Site Coverages ...
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• <div><p>As recommended by , using <code>point_on_border</code> to check whether two polygons which don't have intersecting linework are disjoint. The previous PR didn't cover all the possible ...
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• The subject holes are clearance holes for a 4-40 screw. <p><a href="https://github.com/slic3r/Slic3r/files/1995635/Arrick_Slic3r_Issue.zip">Arrick_Slic3r_Issue.zip</a></p> <p>Below is a screen shot ...
• Instead, the latter produces a hole in the overlap, regardless of the direction of the exterior of the two polygons. <h2>Steps to reproduce the problem. <pre><code> shp1 = Polygon.from_bounds(0, ...
• <div><p>While working on the M&M color segmentation gallery example, we noticed ... I added two tests to cover the new behavior.</p><p>该提问来源于开源项目：scikit-image/scikit-image</p></div>
• like i said tho this has been a issue for a month or two now so version listed dont mean much. also including my config in case its due to something i changed. <p>...

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