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  • 一,问题描述 在使用tensorflow-gpu时,出现下面的错误: ... This is probably because cuDNN failed to initialize, so try looking to see if a warning log message was printed above. [[node sequ

    一,问题描述

    在使用tensorflow-gpu时,出现下面的错误:

    tensorflow.python.framework.errors_impl.UnknownError: Failed to get convolution algorithm. This is probably because cuDNN failed to initialize, so try looking to see if a warning log message was printed above.
    [[node sequential/conv2d/Conv2D (defined at tf_keras_classification_model-cnn.py:107) ]] [Op:__inference_distributed_function_930]
    Function call stack:
    distributed_function

    二、解决办法:

    方法一:
    import tensorflow as tf
    gpu_options=tf.compat.v1.GPUOptions(per_process_gpu_memory_fraction=0.85)
    config=tf.compat.v1.ConfigProto(gpu_options=gpu_options)
    session = tf.compat.v1.Session(config=config)
    方法二:
    import tensorflow as tf
    config = tf.compat.v1.ConfigProto()
    config.gpu_options.per_process_gpu_memory_fraction = 0.85 # 占用85%显存
    session = tf.compat.v1.Session(config=config)
    将以上两种方法用到的任意一种代码放在程序开头。

    展开全文
  • The project may be inconsistent, if so try refresh,并且SVN报错Previous operation has not finished; run 'cleanup' if it was interrupted,出现问题的原因是上一次更新或者提交代码操作未完成,此时需要根据...

    eclipse启动后在代码文件package xxx处报错A class file was not written. The project may be inconsistent, if so try refresh,并且SVN报错Previous operation has not finished; run 'cleanup' if it was interrupted,出现问题的原因是上一次更新或者提交代码操作未完成,此时需要根据提示进行cleanup操作。可解决这类问题

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  • This is probably because cuDNN failed to initialize, so try looking to see if a warning log message was printed above. [Op:Conv2D]”错误解决 Failed to get convolution algorithm. This is probably ...

    “Failed to get convolution algorithm. This is probably because cuDNN failed to initialize, so try looking to see if a warning log message was printed above. [Op:Conv2D]”错误解决

    Failed to get convolution algorithm. This is probably because cuDNN failed to initialize, so try looking to see if a warning log message was printed above. [Op:Conv2D]
    

    在导入tf后加入如下代码:

    import os
    os.environ['CUDA_VISIBLE_DEVICES'] = '/gpu:0'
    

    或者

    physical_devices = tf.config.experimental.list_physical_devices(‘GPU’)
    tf.config.experimental.set_memory_growth(physical_devices[0], True)
    
    
    展开全文
  • cracklib.so try_first_pass retry=6 password sufficient pam_unix.so md5 shadow nullok try_first_pass use_authtok remember=3 password required pam_deny.so session optional pam_keyinit.so revoke session ...

    -------------------------------------------------

    每次修改密码时设置的新密码不能是前n次使用过的密码。配置如下:

    Debian / Ubuntu:修改文件  # vi /etc/pam.d/common-password

    CentOS / RHEL / RedHat / Fedora 修改文件 #  vi /etc/pam.d/system-auth

    在 password sufficient pam_unix.so use_authtok md5 shadow remember=10

    在相应行的后面添加 remember=10,而不是添加一行!

    SUSE比较恶心,找了半天才找到。man pw_check

    在 /etc/security/pam_pwcheck 文件中添加 remember=5

    passwd:     nullok use_cracklib remember=5

    -------------------------------------------------------

    /etc/pam.d/system-auth

    pam_cracklib.so 的 options

    6.2.2.OPTIONS

    debug

    This option makes the module write information to syslog(3) indicating the behavior of the module

    (this option does not write password information to the log file).

    authtok_type=XXX

    The default action is for the module to use the following prompts when requesting passwords:

    "New UNIX password: " and "Retype UNIX password: ".

    The example word UNIX can be replaced with this option, by default it is empty.

    retry=N

    Prompt user at most N times before returning with error. The default is 1.

    difok=N

    This argument will change the default of 5 for the number of characters in the new password

    that must not be present in the old password. In addition, if 1/2 of the characters in the new password are different

    then the new password will be accepted anyway.

    difignore=N

    How many characters should the password have before difok will be ignored. The default is 23.

    minlen=N

    The minimum acceptable size for the new password (plus one if credits are not disabled which is the default).

    In addition to the number of characters in the new password, credit (of +1 in length) is given for each different

    kind of character (other, upper, lower and digit). The default for this parameter is 9 which is good for a old style

    UNIX password all of the same type of character but may be too low to exploit the added security of a md5 system.

    Note that there is a pair of length limits in Cracklib itself, a "way too short" limit of 4 which is hard coded in and

    a defined limit (6) that will be checked without reference to minlen. If you want to allow passwords as short as 5 characters

    you should not use this module.

    dcredit=N

    (N >= 0) This is the maximum credit for having digits in the new password. If you have less than or N digits,

    each digit will count +1 towards meeting the current minlen value. The default for dcredit is 1 which is the

    recommended value for minlen less than 10.

    (N < 0) This is the minimum number of digits that must be met for a new password.

    ucredit=N

    (N >= 0) This is the maximum credit for having upper case letters in the new password.

    If you have less than or N upper case letters each letter will count +1 towards meeting the current minlen value.

    The default for ucredit is 1 which is the recommended value for minlen less than 10.

    (N < 0) This is the minimum number of upper case letters that must be met for a new password.

    lcredit=N

    (N >= 0) This is the maximum credit for having lower case letters in the new password.

    If you have less than or N lower case letters, each letter will count +1 towards meeting the current minlen value.

    The default for lcredit is 1 which is the recommended value for minlen less than 10.

    (N < 0) This is the minimum number of lower case letters that must be met for a new password.

    ocredit=N

    (N >= 0) This is the maximum credit for having other characters in the new password.

    If you have less than or N other characters, each character will count +1 towards meeting the current minlen value.

    The default for ocredit is 1 which is the recommended value for minlen less than 10.

    (N < 0) This is the minimum number of other characters that must be met for a new password.

    minclass=N

    The minimum number of required classes of characters for the new password. The default number is zero.

    The four classes are digits, upper and lower letters and other characters. The difference to the credit check is that

    a specific class if of characters is not required. Instead N out of four of the classes are required.

    maxrepeat=N

    Reject passwords which contain more than N same consecutive characters.

    The default is 0 which means that this check is disabled.

    reject_username

    Check whether the name of the user in straight or reversed form is contained in the new password.

    If it is found the new password is rejected.

    use_authtok

    This argument is used to force the module to not prompt the user for a new password

    but use the one provided by the previously stacked password module.

    dictpath=/path/to/dict

    Path to the cracklib dictionaries.

    #----------------------------------------------------------------------------------------------------------------------#

    cat > /etc/pam.d/system-auth <

    #%PAM-1.0

    # This file is auto-generated.

    # User changes will be destroyed the next time authconfig is run.

    auth        required      pam_env.so

    auth        sufficient    pam_unix.so nullok try_first_pass

    auth        requisite     pam_succeed_if.so uid >= 500 quiet

    auth        required      pam_deny.so

    account     required      pam_unix.so

    account     sufficient    pam_succeed_if.so uid < 500 quiet

    account     required      pam_permit.so

    password    requisite     pam_cracklib.so try_first_pass retry=6

    password    sufficient    pam_unix.so md5 shadow nullok try_first_pass use_authtok remember=3

    password    required      pam_deny.so

    session     optional      pam_keyinit.so revoke

    session     required      pam_limits.so

    session     [success=1 default=ignore] pam_succeed_if.so service in crond quiet use_uid

    session     required      pam_unix.so

    auth        required      pam_tally2.so deny=6 onerr=fail unlock_time=300

    account     required      pam_tally2.so

    password    required      pam_cracklib.so try_first_pass retry=6 minlen=8 lcredit=-1 ucredit=-1 ocredit=-1 dcredit=-1

    !

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  • error adding symbols: DSO missing from command line Ubuntu Raring:我收到了更多信息的错误消息 /usr/bin/ld: note: 'uncompress' is defined in DSO /lib/x86_64-linux-gnu/libz.so.1 so try adding it to the ...
  • 例如修改配置/etc/pam.d/system-auth-ac文件,在password模块接口行修改或添加配置参数如下: password requisite pam_cracklib.so try_first_pass retry=3 type= reject_username minlen=12 lcredit=-1 ucredit=-1 ...
  • 在java中的try-catch中重试try块问题描述 投票:0回答:3我是java的新手,有以下问题。我已经找到了几个答案,但仍然不清楚如何实现while块来解决问题:在下面的代码中,我试图从用户输入接收有关“产品名称”和...
  • 今天突然有个使用宝塔linux面板客户的线上mysql服务停止并无法启动,检查后发现根目录占用已经达到100%,清理日志腾出空间后执行启动命令:service mysqld restart ... Failed to stop running server, so refusing...
  • Look for the following two lines: password requisite pam_cracklib.so try_first_pass retry=3 password sufficient pam_unix.so md5 shadow nullok try_first_pass use_authtok 3. Comment out the first ...
  • 1 dcredit=-1 ocredit=-1 enforce_for_root password requisite pam_pwquality.so try_first_pass local_users_only retry=3 authtok_type= password sufficient pam_unix.so sha512 shadow nullok try_first_pass ...
  • anoconda在使用虚拟... This is probably because cuDNN failed to initialize, so try looking to see if a warning log message was printed above. [Op:Conv2D] 可能很多帖子会给出是tensorflow和对应的cuda和cud
  • 【问题】折腾:出错:/home/CLi/develop/crosstool-ng/x-tools/arm-xscale-linux-gnueabi/lib/gcc/arm-xscale-linux-gnueabi/4.6.0/../../../../arm-xscale-linux-gnueabi/bin/ld: warning: libexpat.so.1, needed ...
  • password requisite pam_pwquality.so try_first_pass local_users_only retry=3 authtok_type= minlen=6 ucredit=1 lcredit=1 ocredit=1 dcredit=1 (2)修改用户xiao的密码 注:输入一次密码:123456,提示“无效...
  • #password requisite pam_cracklib.so try_first_pass retry=3 type= password requisite pam_cracklib.so try_first_pass retry=5 dcredit=-1 lcredit=-1 ucredit=-1 ocredit=-1 minlen=8 remember=5 #修改后 字段...
  • # 写在前面,下面的方法是针对centos7版本的,centos6pam认证模块用的是pam_cracklib.so设置密码中至少包含一个小写字符,执行命令:# authconfig --enablereqlower --update查看设置:# grep "^lcredit" /etc/...
  • 可以直接忽略,修改成功就可以了 #password requisite pam_pwquality.so try_first_pass local_users_only retry=3 authtok_type= enforce_for_root password required pam_pwquality.so password sufficient pam_...
  • 它工作得很好,我想提供一些自动防故障方法,以确保缓存功能始终正常(例如,使用基于文件的缓存),即使redis服务器出现...try {$redis->connect('127.0.0.1', 6379);} catch (Exception $e) {// tried changing...
  • 3.禁止使用旧密码找到同时有“password”和“pam_unix.so”字段并且附加有“remember=5”的那行,它表示禁止使用最近用过的5个密码(己使用过的密码会被保存在/etc/security/opasswd下面)。Debian、Ubuntu或LinuxMint...
  • TRY NOT TO SAY SO MUCH!

    2021-10-10 05:35:13
    THE BEST APPROACH IS TO LISTEN AND OBSERVE FIRST!!!
  • You've gone through so much trouble. - _________ A.It's no trouble at all. B.That's good. C.I don't think so. D.That's very kind of you. 答案:A 3.- I believe we've met somewhere before. - No, ______...
  • try_files 指令的官方介绍比较让人摸不着头脑,经网上一番总结查看,try_files最核心的功能是可以替代rewrite。try_files语法: try_files file ... uri 或 try_files file ... = code默认值: 无作用域: server ...
  • 0、目标so为a 被引用so为b a引用b1、被引用的so b需要有头文件,包含extern "C" 定义函数2、生成待使用的目标so acmakelist.txt 中要指定 .h头文件位置 参考:include_directories( libs/jni/include/ )cmakelist....
  • Is it possible to use try catch block inside of a lambda function. I need the lambda function to convert a certain variable into an integer, but not all of the values will be able to be converted int....
  • 密码设置生效后,重新编辑sshd_configtimed文件,将注释’#'去掉 将两行注释去掉 password requisite pam_pwquality.so try_first_pass local_users_only retry=3 authtok_type= enforce_for_root password ...
  • I am writing python code to install all the library packages required by my program in the linux environment.So the linux may contain python 2.7 or 2.6 or both so I have developed a try and except blo...
  • 正如SpoonMeiser已经提到的,您的代码有很多问题:The only division takes place before entering the try block, so your except ZeroDivisionError will never get triggered.except user_input_1 != int ...

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