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  • Excel从日期中提取年份

    千次阅读 2014-06-24 15:59:30
    日出生日期中提取年份 B1=

    从出生日期中提取年份

    B1=TEXT(A1,"yyyy")

    B2=YEAR(A2)

     

    从出生日期中提取出生年月和具体时间

    B3=TEXT(A3,"e-m-d")

    B4==TEXT(A4,"h:m")

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  • I need a mysql query to extract the year from the following date format from a table in my database.For eg :subdateshow----------------01/17/200901/17/200901/17/200901/17/200901/17/2009the following q...

    I need a mysql query to extract the year from the following date format from a table in my database.

    For eg :

    subdateshow

    ----------------

    01/17/2009

    01/17/2009

    01/17/2009

    01/17/2009

    01/17/2009

    the following query didn't working

    select YEAR ( subdateshow ) from table

    The column type is varchar. Is there any way to solve this?

    解决方案

    Since your subdateshow is a VARCHAR column instead of the proper DATE, TIMESTAMP or DATETIME column you have to convert the string to date before you can use YEAR on it:

    SELECT YEAR(STR_TO_DATE(subdateshow, "%m/%d/%Y")) from table

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  • I'm using spark 2.1.2.I'm working with datetime data, and would like to get the year from a dt string using spark sql functions.The code I use is as follows:import org.apache.spark.sql.functions._impo...

    I'm using spark 2.1.2.

    I'm working with datetime data, and would like to get the year from a dt string using spark sql functions.

    The code I use is as follows:

    import org.apache.spark.sql.functions._

    import org.apache.spark.sql._

    import org.apache.spark.sql.types._

    val spark: SparkSession = SparkSession.builder().

    appName("myapp").master("local").getOrCreate()

    case class Person(id: Int, date: String)

    import spark.implicits._

    val mydf: DataFrame = Seq(Person(1,"9/16/13")).toDF()

    val select_df: DataFrame = mydf.select(unix_timestamp(mydf("date"),"MM/dd/yy").cast(TimestampType))

    select_df.select(year($"date")).show()

    I expect the year of the date as 13 in the example above.

    Actual: org.apache.spark.sql.AnalysisException: cannot resolve 'date' given input columns: [CAST(unix_timestamp(date, MM/dd/yy) AS TIMESTAMP)];;

    'Project [year('date) AS year(date)#11]

    解决方案

    case class Person(id: Int, date: String)

    val mydf = Seq(Person(1,"9/16/13")).toDF

    val solution = mydf.withColumn("year", year(to_timestamp($"date", "MM/dd/yy")))

    scala> solution.show

    +---+-------+----+

    | id| date|year|

    +---+-------+----+

    | 1|9/16/13|2013|

    +---+-------+----+

    It looks like year does not give you two digits but four for years. I'm leaving the string truncation as a home exercise for you :)

    Actual: org.apache.spark.sql.AnalysisException: cannot resolve 'date' given input columns: [CAST(unix_timestamp(date, MM/dd/yy) AS TIMESTAMP)];; 'Project [year('date) AS year(date)#11]

    The reason of the exception is that you want to access the "old" date column (in select(year($"date"))) that's no longer available after select (select(unix_timestamp(mydf("date"),"MM/dd/yy").cast(TimestampType)).

    You could use alias or as to change the weird-looking auto-generated name into something else like date again, and that would work.

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  • I would like to extract the year from the current date using Python.In C#, this looks like:DateTime a = DateTime.Now()a.YearWhat is required in Python?解决方案It's in fact almost the same in Python.....

    I would like to extract the year from the current date using Python.

    In C#, this looks like:

    DateTime a = DateTime.Now()

    a.Year

    What is required in Python?

    解决方案

    It's in fact almost the same in Python.. :-)

    import datetime

    year = datetime.date.today().year

    Of course, date doesn't have a time associated, so if you care about that too, you can do the same with a complete datetime object:

    import datetime

    year = datetime.datetime.today().year

    (Obviously no different, but you can store datetime.datetime.today() in a variable before you grab the year, of course).

    One key thing to note is that the time components can differ between 32-bit and 64-bit pythons in some python versions (2.5.x tree I think). So you will find things like hour/min/sec on some 64-bit platforms, while you get hour/minute/second on 32-bit.

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  • 用于从和获取最新的和老式的数据。 这个软件包的目的是要足够简单,以便快速,交互地导入数据,同时又有足够的能力来下载许多年份的许多系列。 目录 得到一个。 由于这是一个Matlab程序包,因此带有fred.调用函数...
  • Excel从日期中提取年、、日

    千次阅读 2019-06-05 15:43:03
    提取年:=text(a2,"YYYY") 提取月:=TEXT(A2,"M") 提取日:=TEXT(A2,"D日")
  • 我有一个充满数据的数据库,包括日期和时间字符串,例如2010年921日,星期二14:16:17 0000我想做的是根据日期字符串Tue,21 Sep 2010 14:16:17 0000包含的时间数据库中提取各种文档(记录).上面的日期字符串,我...
  • I have the following DF45 2018-01-0173 2018-02-0874 2018-02-0875 2018-02-0876 2018-02-08I want to extract the month name and year in a simple way in the following format:45 Jan-20187...
  • 年份和月份合并的一种方法是对它们进行整数编码,如2014年8的201408。 df['YearMonth'] = df['ArrivalDate'].map(lambda x: 1000*x.year + x.month)
  • .年),类型显示为object 目标:转换成日期, 类型显示为datetime 一种方式: import pandas as pd sales['date']= pd.to_datetime(sales['date'], format='%d.%m.%Y') 一种方式: from datetime import d...
  • 在数据处理常会遇到要对数据框的时间做聚类处理,如"%m/%d/%Y"中提取年份。 对应操作为:拆分成列表——列表转矩阵——利用索引矩阵提取第一列—— year<-strsplit(case_data2$Date,split = "-")...
  • excel提取日期中的年月日
  •  从日期中提取年份  例子 : =LEFT(TEXT(I155,"yyyy-mm-dd"),4)  解释 : 单元格I155为要操作的日期,TEXT函数把日期转换为格式为yyyy-mm-dd的文本.然后用LEFT函数提取转换后的文本的左边四位,即年份.  ...
  • SQL时间字段值获取年份使用DATENAME()函数。 DATENAME()函数语法:DATENAME(param,date) date是时间字段名 或一个时间值 param是指定要返回日期部分的参数,包括下面几种: 获取年份就可以这样写 datename...
  • scala提取字符串数字The "calendar" class handles working with date and time in Scala, the class generates the ... “ calendar”类处理Scala日期和时间 ,该类以以下格式生成当前时间, Thu Apr 23...
  • 文章目录1、pandas.Series.dt.year() pandas.Series.dt.month() 方法提取月份年份2、strftime() 方法提取年份和月份3、pandas.DatetimeIndex.month pandas.DatetimeIndex.year 提取年份和月份4、参考资料 ...
  • import pandas as pd df = pd.read_excel('{}-{}.xlsx'.format(name, today), parse_dates=['净值日期']) df['年'] = df.净值日期.dt.year print(df)
  • Oracle获得日期中年份

    万次阅读 2011-09-01 15:10:38
    在Oracle,要获得日期中年份,例如把sysdate年份取出来。 一种常用的方法是:to_number(to_char(sysdate,'yyyy')) 还有一种更好的方法,那就是使用oracle提供的Extract函数,使用方法是: extract(year
  • 在了解如何实现自动身份证号码中提取出生年月、性别信息之前,首先需要了解身份证号码所代表的含义。我们知道,当今的身份证号码有15/18位之分。早期签发的身份证号码是15位的,现在签发的身份证由于年份的扩展...
  • Oracle获得日期中年份

    千次阅读 2015-05-22 22:31:28
    select to_number(to_char(sysdate,'yyyy')) from dual; 或者可以直接使用Oracle提供的 Extract 函数 ... --获得系统当前 select extract(day from sysdate) from dual; --获得系统当前日  作者: itmyhome
  • #region 10_不规则日期中提取年月日。 string xdate = "August 17 , 2016 "; Match xMatch = Regex.Match(xdate, @"^([a-zA-Z]+)\s*(\d{1,2})\s*,\s*(\d{4})\s*$"); Console.Write...
  • oracle如何获得日期中年份

    千次阅读 2015-06-08 16:57:47
    在Oracle,要获得日期中年份,例如把sysdate年份取出来,并不是一件难事。常用的方法是:Select to_number(to_char(sysdate,'yyyy')) from dual,而实际上,oracle本身有更好的方法,那就是使用Extract函数...
  • 1.身份证号第7-10是年份,11-12位是月份,13-14是日期 2.身份证号第17位对应性别 3.偶数—女 奇数----男 name = input("请输入你的名字:") id = input("请输入你的身份证号码:") year = id[6:10] month = id[10:12] ...
  • In [18]: df['date'] = pd.to_datetime(df['date']) df['year'], df['month'] = df['date'].apply(lambda x: x.year), df['date'].apply(lambda x: x.month) df Out[18]: date Count year month ...
  • 需求需要文本文件中提取中时间及日期代码“`java /** * 文本内容中提取日期时间 * @param text 包含日期时间的文本(格式:yyyy年MMdd日HH:mm) * @return 日期时间字符串(yyyy-MM-dd HH:mm) */ ...

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从日期中提取年份和月