精华内容
下载资源
问答
  • Thought Police

    2019-10-25 00:30:02
    Thought Police
  • Byte Police

    2019-10-24 21:08:22
    Byte Police
  • BN Police

    2019-10-24 20:56:55
    BN Police
  • Police Recruits

    2021-06-14 21:16:13
    文章目录一、Police Recruits总结 一、Police Recruits 本题链接:Police Recruits 题目: A. Police Recruits time limit per test1 second memory limit per test256 megabytes inputstandard input ...


    一、Police Recruits

    本题链接Police Recruits

    题目
    A. Police Recruits
    time limit per test1 second
    memory limit per test256 megabytes
    inputstandard input
    outputstandard output
    The police department of your city has just started its journey. Initially, they don’t have any manpower. So, they started hiring new recruits in groups.

    Meanwhile, crimes keeps occurring within the city. One member of the police force can investigate only one crime during his/her lifetime.

    If there is no police officer free (isn’t busy with crime) during the occurrence of a crime, it will go untreated.

    Given the chronological order of crime occurrences and recruit hirings, find the number of crimes which will go untreated.

    Input
    The first line of input will contain an integer n (1 ≤ n ≤ 1e5), the number of events. The next line will contain n space-separated integers.

    If the integer is -1 then it means a crime has occurred. Otherwise, the integer will be positive, the number of officers recruited together at that time. No more than 10 officers will be recruited at a time.

    Output
    Print a single integer, the number of crimes which will go untreated.

    Examples
    input
    3
    -1 -1 1
    output
    2

    input
    8
    1 -1 1 -1 -1 1 1 1
    output
    1

    input
    11
    -1 -1 2 -1 -1 -1 -1 -1 -1 -1 -1
    output
    8

    Note
    Lets consider the second example:

    1.Firstly one person is hired.
    2.Then crime appears, the last hired person will investigate this crime.
    3.One more person is hired.
    4.One more crime appears, the last hired person will investigate this crime.
    5.Crime appears. There is no free policeman at the time, so this crime will go untreated.
    6.One more person is hired.
    7.One more person is hired.
    8.One more person is hired.

    The answer is one, as one crime (on step 5) will go untreated.

    本博客给出本题截图
    在这里插入图片描述
    在这里插入图片描述

    题意:输入-1证明产生了一个犯罪,输入其他正整数(小于10)代表招募警察的数量,每个警察在处理完一个犯罪后就会退休,且初始警察数为0,问有多少起犯罪是没有警察出来的

    AC代码

    #include <iostream>
    
    using namespace std;
    
    int main()
    {
        int n;
        cin >> n;
        
        int res = 0, cnt = 0;
        for (int i = 0; i < n; i ++ )
        {
            int a;
            cin >> a;
            if (a == -1) 
            {
                if (cnt == 0) res ++;
                else cnt --;
            }
            else cnt += a;
        } 
        
        cout << res << endl;
        
        return 0;
    }
    

    总结

    水题,不解释

    展开全文
  • UNT-Police-源码

    2021-03-14 01:51:31
    UNT-Police
  • Police Patrol

    2019-04-03 20:42:20
    Police Patrol 题目描述: 题目大概讲述的是,现在要在x轴上建一座警察局,x轴上有n个罪犯,现在警局有一辆最多能够装载m个人的巡逻车,然后题目让我们求这辆巡逻车把所有罪犯运回警察局需要行驶的最短距离是多少...

                                             Police Patrol

    题目描述:

                题目大概讲述的是,现在要在x轴上建一座警察局,x轴上有n个罪犯,现在警局有一辆最多能够装载m个人的巡逻车,然后题目让我们求这辆巡逻车把所有罪犯运回警察局需要行驶的最短距离是多少。

    题目分析:

                这个题目警察局的位置不同会影响到答案的不一样,因此我们要尽量把警察局建在一个合适的位置,使得巡逻车所行驶的无用距离最短(所谓的无用距离是指巡逻车从警察局到达第一个罪犯的距离),如果警察局在所有罪犯的左边或者右边的话,我们会发现无用距离是很大的,而如果警察局在罪犯的中间的话,那么无用距离就会大大减小。

                其实警察局的位置不用枚举出来,我们假设警察局在罪犯中间的某个位置,最左边的罪犯到最右边的罪犯的距离是无论警察局位置在哪里都不会改变的,这个距离的两倍就是巡逻车从警察局到左边搭载u个罪犯(u<=m)以及右边搭载v个罪犯(v<=m)需要行驶的距离,根据贪心策略,巡逻车每次从警察局出发无论向左边还是右边,尽可能运输多一些的罪犯,模拟这个过程,直到所有罪犯都被运输完后,以上每次运输罪犯需要行驶的距离的总和便是答案。

    代码:

    #include <iostream>
    #include <cstdio>
    #include <stdio.h>
    #include <cstdlib>
    #include <stdlib.h>
    #include <cmath>
    #include <math.h>
    #include <algorithm>
    #include <cstring>
    #include <string>
    #include <string.h>
    #include <vector>
    #include <queue>
    #include <stack>
    #include <set>
    #include <map>
    #include <bitset>
    #include <deque>
    #define reg register
    #define ll long long
    #define ull unsigned long long
    #define INF 0x3f3f3f3f
    #define min(a,b) (a<b?a:b)
    #define max(a,b) (a>b?a:b)
    #define lowbit(x) (x&(-x))
    using namespace std;
    const int Maxn=1e6+5;
    ll x[Maxn];
    int main()
    {
    	int n,m;
    	scanf("%d%d",&n,&m);
    	for (reg int i=1;i<=n;i++) scanf("%lld",&x[i]);
    	int l=1,r=n;
    	ll ans=0;
    	while (l<r)
    	{
    		ans+=(x[r]-x[l])<<1;
    		l+=m;
    		r-=m;
    	}
    	printf("%lld\n",ans);
    	return 0;
    }

     

    展开全文
  • Danish police records

    2020-12-08 18:41:22
    It was decided by law, that citizens of Copenhagen should report personal informations such as way of living, place of birth and family informations to the police. The 1.4 million registrations has ...
  • pi-police-scanner-源码

    2021-04-03 10:37:51
    pi-police-scanner
  • mastodon-police:Mastodon警察机器人
  • police-reform-源码

    2021-03-21 22:55:58
    警察改革 数据源: 1. Connor Brooks and Kevin M. Scott (2015), ``Number of arrest-related deaths, percent confirmed by survey respondents, and death-identification source, by state, June-August 2015,'...
  • G - Police Recruits

    2021-02-24 21:22:23
    G - Police Recruits The police department of your city has just started its journey. Initially, they don’t have any manpower. So, they started hiring new recruits in groups. Meanwhile, crimes keeps ...

    G - Police Recruits
    The police department of your city has just started its journey. Initially, they don’t have any manpower. So, they started hiring new recruits in groups.

    Meanwhile, crimes keeps occurring within the city. One member of the police force can investigate only one crime during his/her lifetime.

    If there is no police officer free (isn’t busy with crime) during the occurrence of a crime, it will go untreated.

    Given the chronological order of crime occurrences and recruit hirings, find the number of crimes which will go untreated.

    Input
    The first line of input will contain an integer n (1 ≤ n ≤ 105), the number of events. The next line will contain n space-separated integers.

    If the integer is -1 then it means a crime has occurred. Otherwise, the integer will be positive, the number of officers recruited together at that time. No more than 10 officers will be recruited at a time.

    Output
    Print a single integer, the number of crimes which will go untreated.

    Examples
    Input

    3
    -1 -1 1
    Output
    2
    Input
    8
    1 -1 1 -1 -1 1 1 1
    Output
    1
    Input
    11
    -1 -1 2 -1 -1 -1 -1 -1 -1 -1 -1
    Output
    8
    Note
    Lets consider the second example:

    1.Firstly one person is hired.
    2.Then crime appears, the last hired person will investigate this crime.
    3.One more person is hired.
    4.One more crime appears, the last hired person will investigate this crime.
    5.Crime appears. There is no free policeman at the time, so this crime will go untreated.
    6.One more person is hired.
    7.One more person is hired.
    8.One more person is hired.
    The answer is one, as one crime (on step 5) will go untreated.

    #include <iostream>
    
    using namespace std;
    int a[22222222];
    int main()
    {
        int n,i;
        cin>>n;
        for(i=1;i<=n;i++)
        cin>>a[i];
        int x=0,y=0;
        for(i=1;i<=n;i++)
        {
            if(a[i]>0)
            {
            x+=a[i];
            }
           else
            {
               if(x>0)
              {
                x--;
               }
               else
                y++;
            }
        }
         cout<<y;
        return 0;
    }
    
    展开全文
  • EG Police vs Thief-crx插件

    2021-04-06 05:10:58
    EG Police vs Thief是一款休闲游戏,其中有一辆警车和一辆红色车,红色车必须从警察车中逃脱 EG Police vs Thief是一款休闲游戏,其中在开始屏幕中,有一辆警车和一辆红色车,红色车必须从该警车中脱身,只需单击...
  • 警察 模块依赖项版本管理工具。 它会遍历您在github上具有package.json的所有存储库。 然后,它分析依赖性并向您报告所有过时的软件包。 在某些情况下,它也可以建议对package.json文件进行更正。 安装 通过键入...
  • Police Forces是适用于Linux和Windows的开源第一人称射击游戏。 其目的是非常接近商业FPS反恐精英。
  • 风帆生成警察 使用快速启动您的开发的生成器 注意:这需要 Sails v0.11.0+。 如果 v0.11.0+ 还没有发布到 NPM,你需要通过 Github 安装它。 警告!:在新帆项目中使用此生成器,否则请考虑使用 安装 $ npm install...
  • Police World V1.4

    2013-11-02 19:11:58
    Police World V1.4是唐胜555的作品 这是1.3的改进bAN
  • A. Police Recruits

    2019-05-08 19:55:38
    Police Recruits time limit per test1 second memory limit per test256 megabytes input standard input output standard output The police department of your city has just started its journey. Initially.....

    A. Police Recruits
    time limit per test1 second
    memory limit per test256 megabytes
    input standard input
    output standard output
    The police department of your city has just started its journey. Initially, they don’t have any manpower. So, they started hiring new recruits in groups.
    Meanwhile, crimes keeps occurring within the city. One member of the police force can investigate only one crime during his/her lifetime.
    If there is no police officer free (isn’t busy with crime) during the occurrence of a crime, it will go untreated.
    Given the chronological order of crime occurrences and recruit hirings, find the number of crimes which will go untreated.
    Input
    The first line of input will contain an integer n (1 ≤ n ≤ 105), the number of events. The next line will contain n space-separated integers.
    If the integer is -1 then it means a crime has occurred. Otherwise, the integer will be positive, the number of officers recruited together at that time. No more than 10 officers will be recruited at a time.
    Output
    Print a single integer, the number of crimes which will go untreated
    Examples
    Input
    3
    -1 -1 1
    Output
    2
    Input
    8
    1 -1 1 -1 -1 1 1 1
    Output
    1
    Input
    11
    -1 -1 2 -1 -1 -1 -1 -1 -1 -1 -1
    Output
    8
    Note
    Lets consider the second example: Firstly one person is hired.
    Then crime appears, the last hired person will investigate this crime.
    One more person is hired.
    One more crime appears, the last hired person will investigate this crime.
    Crime appears. There is no free policeman at the time, so this crime will go untreated. One more person is hired.
    One more person is hired.
    One more person is hired. The answer is one, as one crime (on step 5) will go untreated.

    #include<iostream>
    using namespace std;
    int main()
    {
    int n,i,k=0,sum=0;
    int a;
    cin>>n;
    for(i=0;i<n;i++)
    {
     cin>>a;
     sum+=a;
     if(sum<0)
     {
      k++;
      sum=0;
     }
    }
    cout<<k<<'\n';
    return 0;
    }
    
    展开全文
  • Police VS Bandwidth

    2017-11-16 22:53:00
    刚写了Priority与Bandwidth的区别,趁热打铁,把police vs bandwidth也拿来来晒晒。 乍一看这两者后面带的都是带宽,其实区别还是很明显的,先把QOS的列出: classification and marking match and set congestion...
  • Police use baidu map and find parking place 使用百度地图,爬去附近的停车位
  • :police_car_light: :warning: 警告:已弃用/不再维护! :warning: :police_car_light: 从2020年4月26日起,不再对miniProxy进行维护,并且不会对其进行任何更改(包括与安全性相关的更改)。 于2005年作为首次...
  • 警察::police_officer:Haskell PVP顾问
  • 警察犯罪 从data.police.uk中提取用于将Bath和North East Somerset的街道犯罪数据导入Socrata的脚本 存取资料 在index.php文件顶部添加以下凭据: root_url-您的Socrata数据存储根URL app_token-您可以通过在...
  • Codeforces - Police Stations

    2020-02-11 15:55:49
    题目链接:Codeforces - Police Stations 我们首先找到必须边,然后问题就解决了。 所以怎么找必须边呢? 每个点肯定是到最近的警察局,又因为两点之间距离都是1,所以我们从警局开始bfs,找到必须边即可。 AC代码...
  • codeforces Police Recruits

    2015-12-18 21:44:28
    The police department of your city has just started its journey. Initially, they don’t have any manpower. So, they started hiring new recruits in groups.Meanwhile, crimes keeps occurring w
  • Police Recruits
  • 警察 一个易于使用和扩展的身份验证库。 它与节点> = 0.11.16与兼容--harmony标志,并且任何版本 。 安装 只需运行 $ npm install --save koa-police 入门 koa-police使用策略选择应保护的路径,并用作普通的Koa...
  • Wi-Fi Privacy Police prevents your smartphone or tablet from leaking privacy sensitive information via Wi-Fi networks. It does this in two ways: It prevents your smartphone from sending out the names...
  • Input police filter driver for Linux.
  • 受和启发的简单而灵活的身份验证工作流程。 注意:这需要 Sails v0.11.0+。 如果 v0.11.0+ 还没有发布到 NPM,你需要通过 Github 安装它。 指导 政策设置 ...var police = require ( 'sails-police' )

空空如也

空空如也

1 2 3 4 5 ... 20
收藏数 16,126
精华内容 6,450
关键字:

police