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  • <div><p>...<p>Probably the smallest change I've ever made, and I've made a lot of small changes.</p><p>该提问来源于开源项目:metabrainz/musicbrainz-server</p></div>
  • Add score detail page

    2020-12-26 01:45:04
    s no direct relation between accuracy and grade</li><li>still uses current (older design) user card</li><li>only for high scores at the moment (<code>osu_scores_*high)</li><li>the url scheme will need...
  • <div><p>The <code>MSGFPlusAdapter</code> now uses internally a direct conversion from the MS-GF+ output format <code>mzid</code> to <code>idXML</code>. The scores are incorrectly imported. That ...
  • Incorrect GQ Score = 0

    2020-11-24 18:41:24
    but with GQ in the 140-160 range for most samples and are in line with the results with the HaplotypeCaller VCF direct results (see below). <h4>Actual behavior <p>Pipeline 2 is incorrectly setting GQ...
  • <p>Random guess, maybe it was a direct challenge? Is the "auto score this" based on a player being flagged as a bot account, or the game made under Create Game -> Vs Computer? <p>That's...
  • Direct Mail Bypass <p>This is an emerging attack vector which I've been submitting numerous vulnerability reports for and it has to do with the unique nature of how mail routing works for cloud-...
  • <div><p>Testing leaderboards with minimal prototype (buttons to set score, submit score, call leaderboard, and similar simple direct functions). Oddly enough this prototype worked fine until today. ...
  • trying to polish a draft genome with direct RNA data. <p>using: <code>nanopolish variants --consensus polished_longest.fa --fix-homopolymers -t 8 --max-rounds=5 --reads /path/to/reads.dna.fq --bam...
  • table_score that should be d_table_score_scrub~~</li><li>~~Use mean of ranks instead of sum for decision table scores, which lets us drop the n_decision_metrics variable~~ (#262)</li><li>~~Add kappa ...
  • t initially notice that all the examples in the wiki and the example project for <code>/react</code> use non-text nodes as direct children of <code><Localized>, so I was implementing most of my ...
  • <div><p>POSTing a search query via a REST client yield different results, it ... hits: { total: 0, max_score: null, hits: [] } }</code></pre>该提问来源于开源项目:elastic/elasticsearch-js</p></div>
  • This is an Ewings-sarcoma cell line so we are hoping to see the EWS-FLI1 fusion from our ONT direct RNA output. <p>minimap2 call: <pre><code> minimap2 --MD -t 16 -ax splice -uf -k14 GRCh38_full_...
  • The above exception was the direct cause of the following exception: Traceback (most recent call last): File "/data/code_ytw/photo-composition-master/vfn_eval.py", line 163, in <module.

    TypeError: only size-1 arrays can be converted to Python scalars

    The above exception was the direct cause of the following exception:

    Traceback (most recent call last):
      File "/data/code_ytw/photo-composition-master/vfn_eval.py", line 163, in <module>
        score=evaluate_aesthetics_score(200)
      File "/data/code_ytw/photo-composition-master/vfn_eval.py", line 105, in evaluate_aesthetics_score
        scores[i] = sess.run([score_func], feed_dict={image_placeholder: img_resize})[0]
    ValueError: setting an array element with a sequence.

     

    本人不熟悉tensorflow,看不懂为啥错

     

     

    出现这个问题前,说我的数据类型不匹配(200,227,227,3),然后我随机生成一个(200,227,227,3)的np数组,报错如此,不知何故。有问题代码如此

     

    修改后,可以用了

     

    希望大佬指导

    展开全文
  • 0 are on the bottom line, their direct acenstors are placed above (higher as) them with score = 1 and so on.</p><p>该提问来源于开源项目:magjac/graphviz-visual-editor</p></div>
  • Graduate(char *Name, char Sex, int Age, char *Id, char *Date, float Score, char *Direct, char *Teacher) :Person(Name, Sex, Age),Student(Name, Sex, Age, Id, Date, Score) { //在构造函数的函数体中...
  • <div><p>Ram use can be quickly saturated when loading "...Adding an option to stream direct from disc would add a lot of flexibility. </p><p>该提问来源于开源项目:ossia/score</p></div>
  • Matlab 7 GA

    千次阅读 2004-07-03 12:34:00
    在 Matlab 7.0 中提供了 Genetic Algorithm and Direct Search 工具箱,现在简单介绍下。转载时请保持作者信息完整。1、首先编写fitness函数,函数内容见后面的引用。function score = my_func1(pop)%f(x1,x2)=21.5+...
    在 Matlab 7.0 中提供了 Genetic Algorithm and Direct Search 工具箱,
    现在简单介绍下。转载时请保持作者信息完整。

    1、首先编写fitness函数,函数内容见后面的引用。

    function score = my_func1(pop)
    %f(x1,x2)=21.5+x1*sin(4*pi*x1)+x2*sin(20*pi*x2)
    %-3.0<=x1<=12.1; 4.1<=x2<=5.8
    score = -21.5 - pop(1)*sin(4*pi*pop(1)) - pop(2)*sin(20*pi*pop(2));

    从ga函数说明可知
    % X = GA(FITNESSFCN,NVARS) finds the minimum of FITNESSFCN using
    % GA. NVARS is the dimension (number of design variables) of the
    % FITNESSFCN. FITNESSFCN accepts a vector X of size 1-by-NAVRS,
    % and returns a scalar evaluated at X.
    %     
    % X = GA(FITNESSFCN,NAVRS,OPTIONS) finds the minimum for
    % FITNESSFCN with the default optimization parameters replaced by values
    % in the structure OPTIONS. OPTIONS can be created with the GAOPTIMSET
    % function.
    ga 是寻找最小值的,所以将原函数取负。


    从本站翻出来一个老贴。
    [parse]lihuanc[/parse]
    关于优化方面的:
    f(x1,x2)=21.5+x1*sin(4*pi*x1)+x2*sin(20*pi*x2)
    -3.0<=x1<=12.1 4.1<=x2<=5.8

    [parse]zonly[/parse]
    用遗传算法算了下,得到一个最优值为38.8503
    x1*=11.6255 x2*=5.7250
    但似乎仍不是全局最优解

    [parse]easyworm[/parse]
    呵呵,这个问题的局部极小较多,我用NLPSolver1.0(到偶的网站www.easyworm.com下载)算了一下:
    初始值取X1=11.600000, X2=4.500000
    最优目标值为37.650301
    最优点处X1*=11.625545, X2*=4.525056
    lingo 8.0的计算结果为37.45030
    最优点处X1*=11.62554, X2*=4.325057


    2、gatool 的用法
    在matlab7命令行输入 gatool,见附图。

    在 PopulationSize=10000; 请注意Mutation函数的选择。

    f(x1*,x2*)=-my_func1(x1*,x2*)=38.84741978236206,
    where x1*=11.62378; x2*=5.72501

    3、ga 函数的使用
    因为要使用非原始设定,所以要采用 ga 的第2种调用方式,并且Mutation要采用mutationuniform函数。

    opt1 = gaoptimset;
    opt1.PopInitRange = [[-3.0 4.1];[12.1 5.8]];
    opt1.PopulationSize = 1000;
    opt1.MutationFcn=@mutationuniform;
    [x, fval] = ga(@my_func1,2,opt1)

    结果如下:
    >> opt1

    opt1 =

    PopulationType: 'doubleVector'
    PopInitRange: [2x2 double]
    PopulationSize: 1000
    EliteCount: 2
    CrossoverFraction: 0.80000000000000
    MigrationDirection: 'forward'
    MigrationInterval: 20
    MigrationFraction: 0.20000000000000
    Generations: 100
    TimeLimit: Inf
    FitnessLimit: -Inf
    StallGenLimit: 50
    StallTimeLimit: 20
    InitialPopulation: []
    InitialScores: []
    PlotInterval: 1
    CreationFcn: @gacreationuniform
    FitnessScalingFcn: @fitscalingrank
    SelectionFcn: @selectionstochunif
    CrossoverFcn: @crossoverscattered
    MutationFcn: @mutationuniform
    HybridFcn: []
    Display: 'final'
    PlotFcns: []
    OutputFcns: []
    Vectorized: 'off'

    >> [x, fval] = ga(@my_func1,2,opt1)
    Optimization terminated: stall generations limit exceeded.

    x =

    11.60992040806107 5.72602745388080

    fval =

    -38.61619496300001

    >>
    58619379.snap.jpg
    (缩略图,点击图片链接看原图)
    function y = my_func2(x)
    %fmax
    r=sqrt((x(1)-50)^2+(x(2)-50)^2)+exp(1);
    y=-(sin(r)/r+1);

    function y = my_func2a(x)
    %fmin
    r=sqrt((x(1)-50)^2+(x(2)-50)^2)+exp(1);
    y=(sin(r)/r+1);

    原贴见
    http://bbs.matwav.com/post/view?bid=7&id=45307&sty=0&tpg=2&ppg=1&age=0#45307

    请注意 Mutation 选择 Gaussian 函数时, Scale 要设成 0;
    结果:
    minimize f(x) = 0.7827663723309104;
    maximize f(x) = 1.1283745483594003
    96993515.snap.jpg
    (缩略图,点击图片链接看原图)


    展开全文
  • 学生排序

    2018-03-11 20:57:38
    #include <stdio.h> #include <algorithm> using namespace std; struct E{ char name[100]; int num;//用于标注录入顺序 int score; }buf[1000]; int direct; bool cmp1(struct E a, E b) { ...
    #include <stdio.h>
    #include <algorithm>
    using namespace std;
    struct E{
        char name[100];
        int num;//用于标注录入顺序
        int score;
    }buf[1000];
    int direct;
    bool cmp1(struct E a, E b)
        {
            if(a.score!=b.score) return a.score<b.score;
            else return a.num<b.num;//录入顺序
        }
    bool cmp2(E a,E b)
        {
            if(a.score!=b.score) return a.score>b.score;
            else return a.num<b.num;//录入顺序
        }
    int main()
    {
        int n;
        while(scanf("%d",&n)!=EOF)
        {
            scanf("%d",&direct);
            for(int i=0;i<n;++i){
                scanf("%s %d",buf[i].name,&buf[i].score);
                buf[i].num=i;
            }
            if(direct==0)
                sort(buf,buf+n,cmp2);
            else if(direct==1)
                sort(buf,buf+n,cmp1);
            for(i=0;i<n;++i)
            {
                printf("%s %d\n",buf[i].name,buf[i].score);
            }
        }
            return 0;
    }
    

     

    展开全文
  • 消消乐

    2018-12-19 15:31:05
    typedef enum{UP, DOWN, LEFT, RIGHT, INIT} DIRECT; typedef enum{FALSE, TRUE} BOOL; char bubble[10][10] = {0}; int count = 0; int score = 0; void initialization() { //初始化 s...
    #include <stdio.h>
    
    typedef enum{UP, DOWN, LEFT, RIGHT, INIT} DIRECT;
    typedef enum{FALSE, TRUE} BOOL;
    
    char bubble[10][10] = {0};
    int count = 0;
    int score = 0;
    
    void initialization()
    {
    	//初始化
    	srand(time(NULL));
    	
    	int i,j;
    	
    	for(i = 0; i < 10; i++)
    	{
    		for(j = 0; j < 10; j++)
    		{
    			if(i == 0)
    			{
    				bubble[i][j] = j+'0';			//第一行表示列号
    			}
    			else if(j == 0)
    			{
    				bubble[i][j] = i+'0';			//第一列表示行号
    			}
    			else
    			{
    				bubble[i][j] = rand()%5 + 'A';	//将'A'-'E'的随机数赋值给二维数组bubble
    			}
    		}
    	}
    	
    }
    
    void print_bubble()
    {
    	//打印所有泡泡
    	int i,j;
    	
    	for(i = 0; i < 10; i++)
    	{
    		for(j = 0; j < 10; j++)
    		{
    			if(1 == j)
    			{
    				printf(" ");
    			}
    			printf("%c",bubble[i][j]);
    		}
    		printf("\n");
    	}
    }
    
    void translate_o(int x, int y)
    {
    	char same = bubble[x][y];
    	bubble[x][y] = 'O';
    	
    	if((x>1) && (bubble[x-1][y] == same))
    		translate_o(x-1, y);
    	
    	if((x<=8) && (bubble[x+1][y] == same))
    		translate_o(x+1, y);
    	
    	if((y>1) && (bubble[x][y-1] == same))
    		translate_o(x, y-1);
    	
    	if((y<=8) && (bubble[x][y+1] == same))
    		translate_o(x, y+1);
    }
    
    
    void input_xy(int *x, int *y)
    {
    	BOOL tmp = FALSE;
    	
    	while(tmp == FALSE)
    	{
    		printf("请输入要消除的坐标: ");
    		scanf("%d,%d", x, y);
    		
    		if(bubble[*x][*y]>='A' && bubble[*x][*y]<='E' && *x>0 && *x<10 && *y>0 && *y<10)
    		{
    			tmp = TRUE;
    		}
    		else
    		{
    			printf("坐标有误,请重新输入\n");
    		}
    	}
    }
    
    int getscore(int count)
    {
    	if(count == 1)
    		return 2;
    	
    	return (getscore(count-1)+2*(count-2));
    }
    
    BOOL delete_o()
    {
    	int i,j,k;
    	int gap = 0;
    	for(j = 1; j < 10; j++)
    	{
    		for(i = 1; i < 10 ;i++)
    		{
    			if(bubble[i][j] == 'O')
    			{
    				k = i-1;
    				while(k > 0)
    				{
    					bubble[k+1][j] = bubble[k][j];
    					k--;
    				}
    				
    				bubble[1][j] = ' ';
    				gap++;
    			}
    		}
    	}
    	
    	if(gap < 2)
    	{
    		return FALSE;
    	}
    	else
    	{
    		count += gap;
    		score = getscore(count);
    		return TRUE;
    	}
    }
    
    
    int main()
    {
    	int x,y;
    	BOOL alive = TRUE;
    	
    	initialization();
    	print_bubble();
    		
    	while(1)
    	{
    		input_xy(&x,&y);
    		
    		translate_o(x, y);	
    		
    		alive = delete_o();
    		print_bubble();
    		if(alive == TRUE)
    		{
    			printf("当前分数=%d\n", score);
    		}
    		else
    		{
    			printf("游戏结束,最终得分=%d\n\n", score);
    			break;
    		}
    	}
    	
    	return 0;
    }
    
    展开全文
  • 电影评论系统

    千次阅读 2019-04-11 16:21:24
    #include<stdio.h> #include<stdlib.h> #include<string.h> #define ELE_MAX 20 typedef struct _Film { int year;//年份 int no;//编号 float score;... char direct[20...
  • lucene6中自定义评分的方法

    千次阅读 2018-07-24 10:20:01
    仍然在上篇博客案例的基础上...与上面案例不同的一点是,在这里,添加了一个score字段,用来表示我们的评分域。 创建索引FileIndexUtils01类 public class FileIndexUtils01 { private static Directory direct...
  • So i decided to say, My program will allow it to function the same but give it no more priority then star has when it comes to the overall score so i do this. <p># full pattern match scores: $user_...
  • Add vanilla loss to NPO

    2020-11-24 11:36:38
    uses the vanilla loss, as VPG uses direct gradient estimator from policy score function, NPO calculates the derivation using importance sampling. Thus, we need to add the 'real' vanilla loss ...
  • 专业统计软件stata11.0

    2012-10-11 11:31:48
    Direct and indirect effects ■Score tests and Wald tests ■Factors scores and other predictions ■Goodness of fit ■Estimation with groups and tests of invariance ■Survey data and clustered data ■...
  • <p>A third option would be that the user enrichs the embeddings of the decoder such as done in RGCN, but a direct approach might be more convenient. <p>As always, any alternative solution is welcome....
  • direct-a.zone-a. 300 IN CNAME direct.zone-a. direct.zone-a. 300 IN A 2.2.2.2 ... </code></pre> <pre><code> root:/# dig @::1 A direct-b.zone-b ... ;; ANSWER SECTION: direct-b.zone-b. 300 IN CNAME ...
  • 一、笑脸数据集(genki4k)正负样本的划分、模型训练和测试的过程(至少包括SVM、CNN),输出模型训练精度和测试精度(F1-score和ROC) 1.数据集下载 笑脸数据集下载链接:...
  • <a href="/questions/1756591/prevent-direct-access-to-file-called-by-ajax-function" dir="ltr">Prevent Direct Access To File Called By ajax Function 12 answers <h1>Context <p>I have ...
  • f("direct", 300000) go f("foo", 200000) go f("bar", 20000) go f("baz", 2000) go func(msg string) { fmt.Println(msg) }("going without loop") var input string fmt.Scanln(&input) fmt.Println...
  • JSON Api Data Array

    2020-12-02 06:45:44
    current bot, no topic to match, no thatpattern to match, direct pattern match, direct word match: test"}} <p>Part of that response array is "filename" - I've tried to use this but "...

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