精华内容
下载资源
问答
  • Divide

    2011-10-13 17:12:36
    Divide   [题目描述]  GG有n份工作要完成,每一份工作有一个类型系数Ak。由于工作数目太多了,GG光靠自己的能力是无法完成的,所以他打算雇佣很多工人来帮他。工人是非常精明的,他们要求按照工作数目收费,...

    Divide

     

    [题目描述]

          GG有n份工作要完成,每一份工作有一个类型系数Ak。由于工作数目太多了,GG光靠自己的能力是无法完成的,所以他打算雇佣很多工人来帮他。工人是非常精明的,他们要求按照工作数目收费,如果分派给他的工作数目小于k,他们将不愿意接受。工人完成一份工作的收费是C。但是,GG也是很精明的老板,考虑到有些工作之间很类似,完成了一份工作之后可以很轻松的完成下一份工作,所以他提出了这样的要求,假设工人接受的工作的类型系数是{B1, B2, B3 … Bp},他能够得到的报酬将是C + (maxB – minB)2

          作为GG的助理,现在你有责任告诉他,为了完成这些工作,他至少要支付多少钱给工人(不算你的工资)?

     

    [输入文件]

          第一行三个正整数n、k、C(1 <= k <= n <= 106,0 < C <= 109),意义如题所述;

          第二行n个正整数描述n份工作的类型系数(0 < A <= 109)。

     

    [输出文件]

          一个整数表示GG最少需要支付的工资(保证答案不大于1017)。

     

    [样例输入]

    2 1 1

    2 4

     

    [样例输出]

    2

     

    [样例说明]

    如果分给一个工人做,收费为1 + (4 – 2)2 = 5;

    如果分给两个工人作,收费为1 + 1 = 2;

    所以最小收费为2。

     

    [数据约定]

    对于50分的测试数据中保证有N <= 1000

    对于80分的测试数据中保证有N <= 100000

    ======================================

    60分算法..

    ===================

    var
      n,k,c:longint;
      a:array[1..1000000]of int64;
      f:array[0..1000000]of int64;
      
    procedure init;
    begin
      assign(input,'divide.in');
      assign(output,'divide.out');
      reset(input); rewrite(output);
    end;
    
    procedure terminate;
    begin
      close(input); close(output);
      halt;
    end;
    
    function min(a,b:int64):int64;
    begin
      if a<b then exit(a);
      exit(b);
    end;
    
    procedure qsort(s,t:longint);
    var
      i,j:longint;
      x:longint;
      tem:longint;
    begin
      x:=a[(s+t) shr 1];
      i:=s; j:=t;
      repeat
        while x<a[j] do dec(j);
        while a[i]<x do inc(i);
        if i<=j then
          begin
            tem:=a[i];
            a[i]:=a[j];
            a[j]:=tem;
            inc(i); dec(j);
          end;
      until i>j;
      if i<t then qsort(i,t);
      if s<j then qsort(s,j);
    end;
    
    procedure main;
    var
      i,j:longint;
    begin
      readln(n,k,c);
      fillchar(f,sizeof(f),$7f);
      for i:=1 to n do read(a[i]);
      qsort(1,n);
      {for i:=1 to n do
        write(a[i],' '); }
      f[0]:=0;
      for i:=k to n do
        for j:=i-k downto 0 do
          begin
            f[i]:=min(f[i],f[j]+sqr(a[i]-a[j+1])+c);
          end;
      writeln(f[n]);
    end;
    
    begin
      init;
      main;
      terminate;
    end.
    

    展开全文
  • Sample Input 15 2 4 1 3 8 9 2 12 2 Sample Output 0 Sample Input 12 5 2 5 7 2 5 7 3 12 2 4 1 9 2 4 5 Sample Output 16
  • BigDecimal中divide方法详解

    万次阅读 多人点赞 2020-02-24 12:05:35
    首先说一下用法,BigDecimal中的divide主要就是用来做除法的运算。其中有这么一个方法. public BigDecimal divide(BigDecimal divisor,int scale, int roundingMode) 第一个参数是除数,第二个参数代表保留几位...

    1、首先说一下用法,BigDecimal中的divide主要就是用来做除法的运算。其中有这么一个方法.

        public BigDecimal divide(BigDecimal divisor,int scale, int roundingMode)
    
    第一个参数是除数,第二个参数代表保留几位小数,第三个代表的是使用的模式。
    BigDecimal.ROUND_DOWN:直接省略多余的小数,比如1.28如果保留1位小数,得到的就是1.2
    
    BigDecimal.ROUND_UP:直接进位,比如1.21如果保留1位小数,得到的就是1.3
    
    BigDecimal.ROUND_HALF_UP:四舍五入,2.35保留1位,变成2.4
    
    BigDecimal.ROUND_HALF_DOWN:四舍五入,2.35保留1位,变成2.3
    
    后边两种的区别就是如果保留的位数的后一位如果正好是5的时候,一个舍弃掉,一个进位。
    

    2、BigDecimal.setScale()方法用于格式化小数点

    setScale(1)表示保留一位小数,默认用四舍五入方式 
    setScale(1,BigDecimal.ROUND_DOWN)直接删除多余的小数位,如2.35会变成2.3 
    setScale(1,BigDecimal.ROUND_UP)进位处理,2.35变成2.4 
    setScale(1,BigDecimal.ROUND_HALF_UP)四舍五入,2.35变成2.4
    setScaler(1,BigDecimal.ROUND_HALF_DOWN)四舍五入,2.35变成2.3,如果是5则向下舍
    
    展开全文
  • Tree and Divide Conquer

    2020-12-21 22:15:28
    title: Tree and Divide Conquer date: 2020-03-24 20:11:09 tags: Algorithm Tree and Divide Conquer 最近做二叉树相关的题,被递归搞的晕头转向。 文章目录Tree and Divide Conquer一、树的性质Divide and ...
  • Tailwind Divide

    2020-06-04 23:06:25
    Tailwind提供了以.devide-为前缀的工具类用于控制父级容器中子...分割线宽度(divide width) 分割线宽度以像素为单位,并辅以顶边和左边两个方位。 工具类 属性 divide-x border-left-width:1px; divide-...

    Tailwind提供了以.devide-为前缀的工具类用于控制父级容器中子类之间的分割线,分割线工具类分为三类分别是宽度、颜色、透明度。分割线工具类需添加在父级容器中,才能显示出子类之间的分割线。

    分割线宽度(divide width)

    分割线宽度以像素为单位,并辅以顶边和左边两个方位。

    工具类 属性
    divide-x border-left-width:1px;
    divide-y border-top-width:1px;
    divide-x-reverse --divide-x-reverse:1;
    divide-y-reverse --divide-y-reverse:1;
    divide-x-0 border-left-width:0;
    divide-x-2 border-left-width:2px;
    divide-x-4 border-left-width:4px;
    divide-x-8 border-left-width:8px;
    divide-y-0 border-top-width:0;
    divide-y-2 border-top-width:2px;
    divide-y-4 border-top-width:4px;
    divide-y-8 border-top-width:8px;

    例如:为子类添加分割线

    divide
    <link href="https://unpkg.com/tailwindcss@^1.0/dist/tailwind.min.css" rel="stylesheet">
    <link href="https://cdn.bootcdn.net/ajax/libs/font-awesome/5.13.0/css/all.min.css" rel="stylesheet">
    
    <div class="container mx-auto my-4 p-4">
      <div class="grid grid-cols-3 divide-x divide-gray-400 text-center border mb-4">
        <div>1</div>
        <div>2</div>
        <div>3</div>
      </div>
      <div class="divide-y divide-gray-400 text-center border">
        <div>1</div>
        <div>2</div>
        <div>3</div>
      </div>
    </div>
    

    分割线颜色(divide color)

    工具类 属性
    divide-transparent border-color:transparent;
    divide-current border-color:currentColor;
    divide-black border-color:#000;
    divide-white border-color:#fff;

    分割线透明度(divide opacity)

    工具类 属性
    divide-opacity-0 --divide-opacity:0;
    divide-opacity-25 --divide-opacity:0.25;
    divide-opacity-50 --divide-opacity:0.5;
    divide-opacity-75 --divide-opacity:0.75;
    divide-opacity-100 --divide-opacity:1
    展开全文
  • <div><p>At the start of training the my FasterRCNN model I always get <code>divide by zero encountered in divide</code> errors although I am checking all my bbox's for validity in the dataset: ...
  • divide_conquer-源码

    2021-03-08 06:32:14
    divide_conquer
  • Divide Chocolate

    2017-11-25 08:15:55
    Obviously clever claire can easily accomplish the division, but she is curious about how many ways there are to divide the chocolate. To simplify this problem, the chocolate can be seen as a ...
  • Divide Groups

    2017-11-16 06:32:09
    To improve the activities effects, Tom200 has to divide all those who signed up into groups to take part in the activity at different time. As we know, one's energy is limited, and Tom200 can hold ...
  • BigDecimal divide

    2019-04-18 18:49:22
    big public Double divSum(Double a, Double b) { if (a != null && b != null && a > 0 && b > 0) { ... return BigDecimal.valueOf(a).divide(BigDecimal.value...

    big

    public Double divSum(Double a, Double b) {
            if (a != null && b != null && a > 0 && b > 0) {
    
                return BigDecimal.valueOf(a).divide(BigDecimal.valueOf(b))
                        .setScale(2, BigDecimal.ROUND_HALF_UP).doubleValue();
            }
            return 0.0;
        }
    
        public Double rateNum(Double a, Double b) {
            if (a != null && b != null && a > 0 && b > 0) {
    
                Double c = divSum(a, 100.0);
                return mulSum(c, b);
            }
            return 0.0;
        }
    
        public Double mulSum(Double a, Double b) {
            if (a != null && b != null && a > 0 && b > 0) {
    
                return BigDecimal.valueOf(a).multiply(BigDecimal.valueOf(b))
                        .setScale(2, BigDecimal.ROUND_HALF_UP).doubleValue();
            }
            return 0.0;
        }

    最新:

    public Double deductSum(Double[] deducts) {
            if (deducts != null && deducts.length > 0) {
                BigDecimal sum = BigDecimal.valueOf(0.0);
                if (deducts.length == 1) {
                    if (deducts[0] != null) {
                        sum.add(BigDecimal.valueOf(deducts[0]));
                    } else {
                        return 0.0;
                    }
                } else {
                    for (Double deduct : deducts) {
                        if (deduct != null) {
                            sum.add(BigDecimal.valueOf(deduct));
                        }
                    }
                }
                return sum.doubleValue();
            }
            return 0.0;
        }
    
        //    a > 0 &&
        public Double realSum(Double a, Double[] deducts) {
            if (a != null && deducts != null && deducts.length > 0) {
                BigDecimal sum = BigDecimal.valueOf(a);
                if (deducts.length == 1) {
                    if (deducts[0] != null) {
                        sum.subtract(BigDecimal.valueOf(deducts[0]));
                    } else {
                        return a;
                    }
                } else {
                    for (Double deduct : deducts) {
                        if (deduct != null) {
                            sum.subtract(BigDecimal.valueOf(deduct));
                        }
                    }
                }
                return sum.doubleValue();
            }
            return 0.0;
        }

     

    第二旧例子:

    public Double deductSum(Double[] deducts) {
            if (deducts != null && deducts.length > 0) {
                BigDecimal sum = BigDecimal.valueOf(0.0);
                if (deducts.length == 1) {
                    if (deducts[0] != null && deducts[0] > 0) {
                        sum.add(BigDecimal.valueOf(deducts[0]));
                    } else {
                        return 0.0;
                    }
                } else {
                    for (Double deduct : deducts) {
                        if (deduct != null && deduct > 0) {
                            sum.add(BigDecimal.valueOf(deduct));
                        }
                    }
                }
                return sum.doubleValue();
            }
            return 0.0;
        }
    
     

     

       public Double realSum(Double a, Double[] deducts) {
            if (a != null && a > 0 && deducts != null && deducts.length > 0) {
                BigDecimal sum = BigDecimal.valueOf(a);
                if (deducts.length == 1) {
                    if (deducts[0] != null && deducts[0] > 0) {
                        sum.subtract(BigDecimal.valueOf(deducts[0]));
                    } else {
                        return a;
                    }
                } else {
                    for (Double deduct : deducts) {
                        if (deduct != null && deduct > 0) {
                            sum.subtract(BigDecimal.valueOf(deduct));
                        }
                    }
                }
                return sum.doubleValue();
            }
            return 0.0;
        }

    旧例子:

    public Double realSum(Double a, Double[] deducts) {
            if (a != null && a > 0 && deducts != null && deducts.length > 0) {
                BigDecimal sum = BigDecimal.valueOf(a);
                if (deducts.length == 1 && deducts[0] != null && deducts[0] > 0) {
                    sum.divide(BigDecimal.valueOf(deducts[0]));
                } else {
                    for (Double deduct : deducts) {
                        if (deduct != null && deduct > 0) {
                            sum.subtract(BigDecimal.valueOf(deduct));
                        }
                    }
                }
                return sum.doubleValue();
            }
            return 0.0;
        }

     

     

     

     

     

    import java.math.BigDecimal;
    
    BigDecimal allocation = BigDecimal.valueOf(allVo.getStudentAllocation());
                    BigDecimal signUp = BigDecimal.valueOf(allocationVo.getStudentSignUp());
                    BigDecimal divide = allocation.divide(signUp, 2, BigDecimal.ROUND_HALF_UP);
                    allocationVo.setStudentRate(divide.doubleValue()+"%");

     

    public String divide(Integer all, Integer sign) {
            if (all > 0 || sign > 0) {
                BigDecimal allocation = BigDecimal.valueOf(all);
                BigDecimal signUp = BigDecimal.valueOf(sign);
                BigDecimal divide = signUp.divide(allocation, 2, BigDecimal.ROUND_HALF_UP);
                return divide.doubleValue() + "%";
            }
            return "0%";
        }

     

    package cn.itcast_02;
     
    import java.math.BigDecimal;
     
    /*
     * 构造方法:
     * 		public BigDecimal(String val):
     * 
     * 金融相关的东西(例:银行钱的小数,商品价格小数,实验小数)
     * 
     * 成员方法:
     * 		public BigDecimal add(BigDecimal augend):加
     * 		public BigDecimal subtract(BigDecimal subtrahend):减
     * 		public BigDecimal multiply(BigDecimal multiplicand):乘
     * 		public BigDecimal divide(BigDecimal divisor):除
     * 		public BigDecimal divide(BigDecimal divisor,int scale,int roundingMode):商,几位小数,如何舍取。
     * 		
     */
    public class BigDecimalDemo {
    	public static void main(String[] args) {
    		System.out.println(0.09 + 0.01);
    		System.out.println(1.0 - 0.32);
    		System.out.println(1.015 * 100);
    		System.out.println(1.301 / 100);
     
    		// public BigDecimal add(BigDecimal augend):加
    		BigDecimal bd1 = new BigDecimal("0.09");
    		BigDecimal bd2 = new BigDecimal("0.01");
    		System.out.println("add:" + bd1.add(bd2));
    		System.out.println("----------------------");
    		// public BigDecimal subtract(BigDecimal subtrahend):减
    		BigDecimal bd3 = new BigDecimal("1.0");
    		BigDecimal bd4 = new BigDecimal("0.32");
    		System.out.println("subtract:" + bd3.subtract(bd4));
    		System.out.println("----------------------");
    		// public BigDecimal multiply(BigDecimal multiplicand):乘
    		BigDecimal bd5 = new BigDecimal("1.015");
    		BigDecimal bd6 = new BigDecimal("100");
    		System.out.println("multiply:" + bd5.multiply(bd6));
    		System.out.println("----------------------");
    		// public BigDecimal divide(BigDecimal divisor):除
    		BigDecimal bd7 = new BigDecimal("1.301");
    		BigDecimal bd8 = new BigDecimal("100");
    		System.out.println("divide:" + bd7.divide(bd8));
    		System.out.println("divide:" + bd7.divide(bd8,3,BigDecimal.ROUND_HALF_UP));
    		System.out.println("divide:" + bd7.divide(bd8,9,BigDecimal.ROUND_HALF_UP));
    	}
    }
    

     

    展开全文
  • FloatingPointError: divide by zero encountered in true_divide" in the pairwise feature portion of the code. Apparently there was a divide by zero issue in the cov part of the underlying code. <p>...
  • divide方法

    千次阅读 2017-08-04 09:25:00
    java.math.BigDecimal.divide(BigDecimal divisor, RoundingMode roundingMode)返回一个BigDecimal,其值为(this/除数),其标度是this.scale()。如果必须执行舍入,以产生一个结果与给定的比例,将指定的舍入模式...
  • Divide by zero

    2020-11-21 16:31:49
    divide by zero" exception. Although, it is being caught by IOException, I guess better way is to prevent divide operation is done. Please have a look at "FuelEconomyObdCommand.java" line ...
  • Implement floor divide

    2021-01-07 11:49:54
    <p>Implement <code>//</code> which is pythonic syntax for divide and floor <h3>- How I did it <p>Added support for <code>//</code> in <code>expr.py :: def arithmetic</code></p> <h3>- How to verify it ...
  • <p>In situations where, for example, sample-data is zero - this causes a runtime warning about divide (and returns a undefined instead of zero) when we need to convert from absolute uncertainties back...
  • Divide-and-conquer-源码

    2021-03-15 03:13:37
    Divide-and-conquer
  • Bigdecimal divide

    2016-12-19 11:07:37
    divisor 为一个BigDecimal类型的除数 scale为保留多少个小数位 roundingMode是小数的保留模式。它们都是BigDecimal中的常量字段,你可以看一下...pubilc BigDecimal divide(BigDecimal divisor, int scal
  • Divide by zero protection

    2020-12-01 12:31:20
    ve taken your divide by zero protection patches and gotten them ready for merging into ChaiScript. <p>I made the following changes: 1. Remove macros in favor of function template 2. Make divide by ...
  • Divide by 0 error

    2020-12-26 07:05:14
    <div><p>In an Operation due to the non-existent <code>NULLIF</code> clause if there is a division then the query throws a divide by 0 error. For Example: <code>PersonFinder.age().dividedBy...
  • Divide Game 程序实现

    2019-12-31 18:53:47
    Now iSea have a clever challenger, who always choose the optimum strategy, if they two play the divide game, and iSea have the chance to divide the string in the first game, can he win the final game?...
  • Divide Two Integers

    2019-10-06 18:13:32
    Divide Two Integers 特殊值可先判断并返回 很重要 本题是通过左移代替乘法产生不同的除数, 然后做减法得到解。 1 public class Solution { 2 public int divide(int dividen...
  • Divide and Conquer

    2019-01-10 21:23:41
    Divide and Conquer: Overview Divide and conquer Break up problem into several parts Solve each part recursively Combine solutions to sub-problems into overall solution Most common usage Break up pr...
  • divide by zero error

    2020-12-09 01:53:26
    divide by zero" error. <pre><code> /Users/tema/pyloudnorm-master/pyloudnorm/loudness.py:173: RuntimeWarning: divide by zero encountered in log10 l = [-0.691 + 10.0 * np.log10(np.sum([G[i] ...
  • var divide = require ( 'compute-divide' ) ; 除法(arr,x [,opts]) 计算按元素划分。 x可以是长度相等的array ,也可以是numeric 。 var arr = [ 2 , 1 , 4 , 2 ] , out ; out = divide ( arr , 2 ) ; // ...
  • 035 Divide SubString

    2020-12-23 10:23:14
    given a number n and a length k now we need to know that from all the substring of number n with length of k, how many of these can be divisible by n. return the number of substrings ...public int divide

空空如也

空空如也

1 2 3 4 5 ... 20
收藏数 16,659
精华内容 6,663
关键字:

divide