假设有一个对象数组，我们想要根据某个对象属性对数组进行排序，而传递给数组sort()方法的比较函数要接受2个参数，即要比较的值

可是，我们需要一种方式指明按照哪个属性来排序。
要解决这个问题，可以定义一个函数，它接收一个属性名，然后根据这个属性名来创建一个比较函数

function createComprisonFunction (propName) {
	return function (object1, object2) {
		var value1 = object1[propName];
		var value2 = object2[propName];
		if (value1 < value2) {
			return -1;
		} else {value1 > value2} {
			return 1;
		} else {
			return 0;
		}
	}
}

// 调用
var data = [
	{name: 'heqiuyu', age: 20},
	{name: 'baixiaoyun', age: 20}
];
data.sort(createComprisonFunction('name'));
console.log(data[0].name);
data.sort(createComprisonFunction('name'));
console.log(data[0].name);

对数组里面的对象排序并取出值最大的五条

原数据（数据太多只展示前五条）

response.data
0: {confirm: 1646192, nation: "西班牙", rate: 35232, population: 46723749}
1: {confirm: 1621305, nation: "英国", rate: 24385, population: 66488991}
2: {confirm: 1585178, nation: "意大利", rate: 26231, population: 60431283}
3: {confirm: 1418807, nation: "阿根廷", rate: 31887, population: 44494502}
4: {confirm: 1308376, nation: "哥伦比亚", rate: 26353, population: 49648685}

方法

let data = response.data
var compare = function (obj1, obj2) {
            var val1 = obj1.confirm;
            var val2 = obj2.confirm;
            if (val1 < val2) {
              return -1;
            } else if (val1 > val2) {
              return 1;
            } else {
              return 0;
            }
          }
          let data11 = data.sort(compare).reverse().splice(0,5)

处理后的数据

0: {confirm: 13750404, nation: "美国", rate: 42029, population: 327167434}
1: {confirm: 9431691, nation: "印度", rate: 6973, population: 1352617328}
2: {confirm: 6314740, nation: "巴西", rate: 30146, population: 209469333}
3: {confirm: 2270573, nation: "法国", rate: 33896, population: 66987244}
4: {confirm: 2249890, nation: "俄罗斯", rate: 15573, population: 144478050}

data(){
return{
subjects:[
{sort:1,name:“aaa”},
{sort:3,name:“ccc”},
{sort:2,name:“bbb”}
]
}
}

this.subjects = this.sortBykey(this.subjects, “sort”);

//对象数组排序方法
sortBykey(array, key) {
return array.sort(function (a, b) {
var x = a[key]; //如果要从大到小,把x,y互换就好
var y = b[key];
return x < y ? -1 : x > y ? 1 : 0;
});
},