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  • radix_point_left_str = split_result[0] # 小数点右边 radix_point_right_str = "" if 1 (split_result): radix_point_right_str = save_decimal_place_str.split('.')[1] # 千分位的分隔符以逗号作为基准 ...

    """

    from decimal import Decimal

    def test():

    result = ""

    try:

    # 计算公式:symbol_left + 格式化美元价 * value + symbol_right

    # 公式参数说明:

    # 格式化美元价: usaPrice的amount

    # decimal_place: 是保留多少小数位

    # dec_point: 是小数点符号

    # thousands_sep:是千位分割符号

    # 获取格式化美元价

    usa_price_amount = Decimal('59.24')

    value = Decimal('160.234')

    symbol_left = '₹'

    symbol_right = ""

    decimal_place = '2'

    dec_point = '.'

    thousands_sep = ','

    calculate_decimal = usa_price_amount * value

    # 保留几位小数

    save_decimal_place_str = "%.{0}f".format(int(decimal_place)) % (

    calculate_decimal)

    # 逗号

    comma_str = ","

    # 点号

    dot_str = "."

    if thousands_sep == comma_str and dec_point == dot_str:

    thousands_sep_comma_str = "{:,}".format(Decimal(save_decimal_place_str))

    result = symbol_left + thousands_sep_comma_str + symbol_right

    else:

    # 按照文档:由于小数点符号和千位分割符号,

    # 会出现小数点符号是逗号,千位分割符号为点号

    # 所以对save_decimal_place_str进行拆分

    # 小数点左边

    split_result = save_decimal_place_str.split('.')

    radix_point_left_str = split_result[0]

    # 小数点右边

    radix_point_right_str = ""

    if 1 < len(split_result):

    radix_point_right_str = save_decimal_place_str.split('.')[1]

    # 千分位的分隔符以逗号作为基准

    thousands_sep_comma_str = "{:,}".format(

    Decimal(radix_point_left_str))

    # 如果千分位的分隔符不是逗号

    if thousands_sep != comma_str:

    radix_point_left_str = thousands_sep_comma_str.replace(',',

    thousands_sep)

    else:

    radix_point_left_str = thousands_sep_comma_str

    new_res = radix_point_left_str + dec_point + radix_point_right_str

    result = symbol_left + new_res + symbol_right

    except Exception as e:

    pass

    return result

    print(test())

    """

    展开全文
  • I have a large dataframe which has a column called Lead Rev. This column is a field of numbers such as (100000 or 5000 etc.) I want to know how to format these numbers to show commas as thousand separ...

    I have a large dataframe which has a column called Lead Rev. This column is a field of numbers such as (100000 or 5000 etc.) I want to know how to format these numbers to show commas as thousand separators. The dataset has over 200,000 rows.

    Is it something like: '{:,}'.format('Lead Rev')

    which gives this error:

    ---------------------------------------------------------------------------

    ValueError Traceback (most recent call last)

    in ()

    ----> 1 '{:,}'.format('Lead Rev')

    ValueError: Cannot specify ',' or '_' with 's'.

    解决方案

    To make all your floats show comma separators by default in pandas versions 0.23 through 0.25 set the following:

    pd.options.display.float_format = '{:,}'.format

    In pandas version 1.0 this leads to some strange formatting in some cases.

    展开全文
  • I have a dataframe which has a column called "Lead Rev" This column is a field of numbers such as (100000 or 5000 etc..). I want to know how to format these numbers to show commas as thousand separato...

    I have a dataframe which has a column called "Lead Rev" This column is a field of numbers such as (100000 or 5000 etc..). I want to know how to format these numbers to show commas as thousand separators.

    Is it something like: '{:,}'.format('Lead Rev')

    'Lead Rev' is my column name. I have over 200,000 rows in my dataset.

    This is my error:

    ValueError Traceback (most recent call last)

    in ()

    ----> 1 '{:,}'.format('Lead Rev')

    ValueError: Cannot specify ',' or '_' with 's'.

    解决方案

    You can use apply() to get the desired result. This works with floating too

    import pandas as pd

    series1 = pd.Series({'Value': 353254})

    series2 = pd.Series({'Value': 54464.43})

    series3 = pd.Series({'Value': 6381763761})

    df = pd.DataFrame([series1, series2, series3])

    print(df.head())

    Value

    0 3.532540e+05

    1 5.446443e+04

    2 6.381764e+09

    df['Value'] = df.apply(lambda x: "{:,}".format(x['Value']), axis=1)

    print(df.head())

    Value

    0 353,254.0

    1 54,464.43

    2 6,381,763,761.0

    展开全文
  • python 千位分隔符

    千次阅读 2019-01-07 13:06:00
    >>>'{:,}'.format(1234567890) >>>'1,234,567,890' 转载于:https://www.cnblogs.com/sea-stream/p/10232674.html

     

    >>>'{:,}'.format(1234567890)
    >>>'1,234,567,890'

     

    转载于:https://www.cnblogs.com/sea-stream/p/10232674.html

    展开全文
  • I know that theoretically digits in large integers can be grouped by thousands for better readability:Python 3.5.2 (default, Nov 17 2016, 17:05:23)[GCC 5.4.0 20160609] on linuxType "help", "copyright...
  • 将 “12,345.678” (str) 转化为 12345.678 (float) fromlocaleimport* setlocale(LC_NUMERIC,'English_US') atof('123,456')# 123456.0 转自...
  • python中怎么把千位分隔符以及货币符号去掉转成数值形式? 比如下面的这种 $10,000 ¥1,000,000.00 怎么转换成数值? 用正则表达就可以了 from re import sub money = '¥1,000,000' val = float(sub(r'[^...
  • * 字符串 千位符 千位分隔符,并且小数点后保留2位 * @param num * @return */ public static String num2thousand(String num) { String numStr = ""; if (!TextUtils.isEmpty(num)) { return numStr; } ...
  • 5.2.5 字段宽度、精度和千位分隔符 使用类型符f格式化浮点数时,默认在小数点后会保留6位数。其实,使用format方法也可以让该格式化数值的整数部分占用一个固定的位数,也可以看作控制字段的宽度。例如,使用{num:10...
  • 1. Basic soluation Match: [0-9](?=(?:[0-9]{3})+(?![0-9])) Replace: \g, 2. Match separator positions only, using lookbehind Match:(?[0-9])(?=(?:[0-9]{3})+(?![0-9])) Replace: ,
  • 第六课 字段宽度、精度和千位分隔符(format方法)# 字段宽度、精度和千位分隔符# 100,000,000,000# 让一个数值在宽度为2的范围内输出,如果数值没到12位,左侧填充空格 4位呢print("a:{num:2}".format(num = 32)) # a...
  • 1. Mandatory integer and fraction ^[0-9]{1,3}(,[0-9]{3})*\.[0-9]+$ 2. Mandatory integer and optional fraction. Decimal dot must be omitted if the fraction is omitted ^[0-9]{1,3}(,[0-9]{3})*(\.[0-9]+)
  • Mysql千位分隔符的varchar转数字

    千次阅读 2019-10-31 16:05:06
    sql写入数据时没有对千分位分隔符的逗号进行处理,查询到excel或者用PQ,PB连接也没问题,但是sql语句里面做计算的话就只会取第一个逗号之前的部分进行计算 说明:数据类型为varchar
  • Ans 1 (Python) O(logN)O(logN)O(logN) O(logN)O(logN)O(logN) 32ms (95.60%) Ans 2 (Python) Ans 3 (Python) 解法一: class Solution: def thousandSeparator(self, n: int) -> str: ans = []
  • js实现千位分隔符

    2018-10-18 10:01:00
    2019独角兽企业重金招聘Python工程师标准>>> ...
  •  设置千位分隔符:自定义函数+格式化处理 df['data'].map(lambda x : format(x, ',')) # 处理后依然是对象格式。设置千位分割符请小心操作,因为对电脑来说,这些已经不再是数字了,而是数字和逗号组成的字符串,要...
  • 如何将下图中的浏览量(PV)、访客数(UV)、IP数这几列中的带有千位分隔符","的字符串类型转换成浮点数类型 示例代码如下: importpandasaspd test=pd.DataFrame({'A':['1,232.1','22,332.3','3,232','1,111,...
  • 玩转千位分隔符输出

    2015-06-29 01:30:00
    2019独角兽企业重金招聘Python工程师标准>>> ...
  • js金额千位分隔符(转)

    2017-08-17 15:57:00
    2019独角兽企业重金招聘Python工程师标准>>> ...
  • * 功能:金额按千位逗号分割 * 参数:s,需要格式化的金额数值. * 参数:type,判断格式化后的金额是否需要小数位.传0无小数位,不传或传其他 * 值保留两位小数 * 返回:返回格式化后的数值字符串. */ ...
  • 如果没有分隔符的话,python的处理方法很简单了,就是 f = float(s) 但可惜的是,float是不支持这个分隔符的 那么下面就是解决方法了,有两个 1,直接使用 replace,相当于把这...
  • 将“12,345.678” (str)转化为12345.678 (float) from locale import * setlocale(LC_NUMERIC, 'English_US') atof('123,456') # 123456.0转自:https://www.cnblogs.com/meadow/p/6279313.html...
  • 更改数字格式貌似用的比较多,直接上代码了: import numpy as np import pandas as pd data_2019=pd.read_excel('C:\\Users\\02180085\\Desktop\\会员新旧离返\\19年-731.xlsx') # data_2019['销售金额'].map...
  • 在数值中加入千位分隔符

    千次阅读 2007-04-06 14:47:00
    procedure TInfoForm.Button2Click(Sender: TObject);var m:DOUBLE;begin m:=12345678; ShowMessage(Format(%*.*n,[0,0,m]));end;[ 0 , 0 , m] 保留位数 
  • python逗号分隔符 什么是质数? (What is a prime number?) Many times, while writing the code we need to print the large number separated i.e. thousands separators with commas. 很多时候,在编写代码时,...
  • 给你一个整数n,请你每隔三位添加点(即 "." 符号)作为千位分隔符,并将结果以字符串格式返回。 示例 1: 输入:n = 987 输出:"987" 示例 2: 输入:n = 1234 输出:"1.234" 示例 3: 输入:n = 123456789 ...
  • 给你一个整数 n,请你每隔三位添加点(即 “.” 符号)作为千位分隔符,并将结果以字符串格式返回。 【示例 1】 输入:n = 987 输出:“987” 【示例 2】 输入:n = 1234 输出:“1.234” 【示例 3】 输入:n = ...
  • 给你一个整数 n,请你每隔三位添加点(即 “.” 符号)作为千位分隔符,并将结果以字符串格式返回。 解题思路: 将整数转化为字符串; 计算其长度与3的关系; 添加“.”,并加入到新的字符串中; 返回分隔后的字符...

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