from glob import glob
import os

img_path = glob('img/*.jpg')

n = 37

for i in img_path:
    a = i.split('\\')
    os.rename(i, a[0]+'/1-{}.jpg'.format(str(n)))
    n = n + 1

I have python script that compares existing file names in a folder to a reference table and then determines if it needs to be renamed or not.

As it loops through each filename:

'oldname' = the current file name

'newname' = what it needs to be renamed to

I want rename the file and move it to a new folder "..\renamedfiles"

Can I do the rename and the move at the same time as it iterates through the loop?

Update:

Apologies, I'm fairly green with scrpting in general but this appears to be pretty basic. shutil.move is exactly what I needed THANKS- I just didn't know to look for it. Successful test below. Now to work it into the script.

import shutil

os.chdir('C:\Users\me\Desktop\New folder')

renFolder= 'Renamed'

oldname = 'Test.txt'

newname= 'renTest.txt'

shutil.move(oldname, renFolder+'/'+newname)

解决方案

os.rename (and os.replace) won't work if the source and target locations are on different partitions/drives/devices. If that's the case, you need to use shutil.move, which will use atomic renaming if possible, and fallback to copy-then-delete if the destination is not on the same file system. It's perfectly happy to both move and rename in the same operation; the operation is the same regardless.

因为需要给一些文件重命名一下，而且文件比较多，所以命名的时候想到了用py，我需要解决的问题是这样子的

• 文件基本上一至
• 文件名是给定的
• 文件和文件名没有映射关系

要求在给定路径下的文件命名

代码如下：
code：

import os
name1 = []

name2 = []


i=0
path = ( r'C:\Users\Administrator\Desktop\第三季第一期\a')  # 一定要加r转义 单引号
filelist = os.listdir(path)  # 该文件夹下所有的文件（包括文件夹）
for files in filelist:  # 遍历所有文件
    i = i+1
    # print(files)
    Olddir=os.path.join(path,files) #  原来的文件路径
    filename=os.path.splitext(files)[0]  #  文件名
    #  filetype = os.path.splitext(files)[1];  # 文件扩展名
    filetype='.jpg'
    Newdir=os.path.join(path,(str(name1[i])+'--计算机学院a')+filetype) #  新的文件路径
    os.rename(Olddir,Newdir) #  重命名