• ## 1062

2019-08-11 14:50:07
给出平面上两个点的坐标(x1,y1),(x2,y2)，求两点之间的曼哈顿距离。曼哈顿距离=|x1-x2|+|y1-y2|。 给出平面上两个点的坐标(x1,y1),(x2,y2)，求两点之间的曼哈顿距离。曼哈顿距离=|x1-x2|+|y1-y2|。...
给出平面上两个点的坐标(x1,y1),(x2,y2)，求两点之间的曼哈顿距离。曼哈顿距离=|x1-x2|+|y1-y2|。
给出平面上两个点的坐标(x1,y1),(x2,y2)，求两点之间的曼哈顿距离。曼哈顿距离=|x1-x2|+|y1-y2|。
解题思路：
能用double 就用double吧,没必要节省这点空间，用float极大可能存在精度丢失问题，也从未遇到过用double到账超时的例子
双精度用   %lf
#include<stdio.h>
#include<math.h>
int main()
{
double x1,x2,y1,y2;
double x,y,sum;
while(scanf("%lf %lf %lf %lf",&x1,&y1,&x2,&y2)!=EOF)
{
x=fabs(x1-x2);
y=fabs(y1-y2);
sum=x+y;
printf("%.3lf",sum);
}
return 0;
}



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• tea1062技术资料，tea1062技术资料，tea1062技术资料，
• mysql主从库同步错误：1062 Error 'Duplicate entry '1438019' for key 'PRIMARY'' on querymysql主从库在同步时会发生1062 Last_SQL_Error: Error ‘Duplicate entry ‘的问题：显然这个问题是因为插入重复主键导致...
mysql主从库同步错误：1062 Error 'Duplicate entry '1438019' for key 'PRIMARY'' on querymysql主从库在同步时会发生1062 Last_SQL_Error: Error ‘Duplicate entry ‘的问题：显然这个问题是因为插入重复主键导致从库不工作了，错误消息如下mysql> show slave status\G;*************************** 1. row ***************************Slave_IO_State: Waiting for master to send eventMaster_Host: 192.168.10.100Master_User: slave_userMaster_Port: 3306Connect_Retry: 60Master_Log_File: mysql-bin.000773Read_Master_Log_Pos: 63325Relay_Log_File: server122-relay-bin.000002Relay_Log_Pos: 165661Relay_Master_Log_File: mysql-bin.000771Slave_IO_Running: YesSlave_SQL_Running: NoReplicate_Do_DB:Replicate_Ignore_DB:Replicate_Do_Table:Replicate_Ignore_Table:Replicate_Wild_Do_Table:Replicate_Wild_Ignore_Table:Last_Errno: 1062Last_Error: Error 'Duplicate entry '1438019' for key 'PRIMARY'' on query. Default database: 'otrs'. Query: 'INSERT INTO ticket (tn, title, create_time_unix, queue_id, ticket_lock_id, user_id, group_id, ticket_priority_id, ticket_state_id, ticket_answered, escalation_start_time, timeout, valid_id, create_time, create_by, change_time, change_by) VALUES ('2012061310001851', 'Your order ORD201205A000016 was bounced back', 1339585744, 44, 1, 43, 1, 3, 4, 0, 1339585744, 0, 1, current_timestamp, 43, current_timestamp, 43)'Skip_Counter: 0Exec_Master_Log_Pos: 41969067Relay_Log_Space: 625695Until_Condition: NoneUntil_Log_File:Until_Log_Pos: 0Master_SSL_Allowed: NoMaster_SSL_CA_File:Master_SSL_CA_Path:Master_SSL_Cert:Master_SSL_Cipher:Master_SSL_Key:Seconds_Behind_Master: NULLMaster_SSL_Verify_Server_Cert: NoLast_IO_Errno: 0Last_IO_Error:Last_SQL_Errno: 1062Last_SQL_Error: Error 'Duplicate entry '1438019' for key 'PRIMARY'' on query. Default database: 'otrs'. Query: 'INSERT INTO ticket (tn, title, create_time_unix, queue_id, ticket_lock_id, user_id, group_id, ticket_priority_id, ticket_state_id, ticket_answered, escalation_start_time, timeout, valid_id, create_time, create_by, change_time, change_by) VALUES ('2012061310001851', 'Your order ORD201205A000016 was bounced back', 1339585744, 44, 1, 43, 1, 3, 4, 0, 1339585744, 0, 1, current_timestamp, 43, current_timestamp, 43)'1 row in set (0.00 sec)ERROR:No query specified解决的办法是在从库上执行:mysql> slave stop;mysql> set GLOBAL SQL_SLAVE_SKIP_COUNTER=1;mysql> slave start;上面的方法可以解决问题，还有一种解决问题的办法是通过修改mysql的配置文件，让从库的同步线程忽略这个错误，方法：修改mysql配置文件 /etc/my.cnf 在 [mysqld]下加一行 slave_skip_errors = 1062 ,保存.重启mysql. mysql slave可以正常同步了.
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• HDU1062 Text Reverse Problem Description Ignatius likes to write words in reverse way. Given a single line of text which is written by Ignatius, you should reverse all the words and then output them. ...
HDU1062
Text Reverse
Problem Description
Ignatius likes to write words in reverse way. Given a single line of text which is written by Ignatius, you should reverse all the words and then output them.
Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single line with several words. There will be at most 1000 characters in a line.
Output
For each test case, you should output the text which is processed.
Sample Input
3
olleh !dlrow
m’I morf .udh
I ekil .mca
Sample Output
hello world!
I’m from hdu.
I like acm.
Hint
Remember to use getchar() to read ‘\n’ after the interger T, then you may use gets() to read a line and process it.
#include<stdio.h>
int main()
{
int T;
char c,a[1010];
int i;
while(scanf("%d",&T)!=EOF)
{
getchar();
while(T--)
{
i=0;
while((c=getchar())!='\n')
{
if(c==' ')
{
while(i--)
putchar(a[i]);
i=0;
printf(" ");
}
else
a[i++]=c;
}
while(i--)
putchar(a[i]);
printf("\n");
}
}
return 0;
}



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• PAT甲级1062，的工程文件，。。。。。。。。。。。。。。。
• <div><p>How can I avoid CA1062 warnings when using for example Guard.Argument(message, nameof(message)).NotNull(); <p>I tried the following in .editorconfig in visual studio 2019 solution root: dotnet...
• program candy bzoj1062; const maxc=1000100; maxm=4010; maxn=2010; var n,len,m,i,p,t,l,r,c,d,q:longint; s:array[0..1,0..maxn,0..maxm] of longint; x,y:array[0..maxc] of ...


program candy bzoj1062;
const maxc=1000100;
maxm=4010;
maxn=2010;
var n,len,m,i,p,t,l,r,c,d,q:longint;
s:array[0..1,0..maxn,0..maxm] of longint;
x,y:array[0..maxc] of longint;

var i:longint;
begin
inc(x); inc(y);
while x<maxn do
begin
i:=y;
while i<maxm do
begin
inc(s[p,x,i],v);
inc(i,i and -i);
end;
inc(x,x and -x);
end;
end;

function sum(p,x,y:longint):longint;
var i:longint;
begin
if (x<0)or(y<0) then exit(0);
inc(x); inc(y); sum:=0;
if x>n then x:=n+1;
if y>m then y:=m+1;
while x>0 do
begin
i:=y;
while i>0 do
begin
inc(sum,s[p,x,i]);
dec(i,i and -i);
end;
dec(x,x and -x);
end;
end;

procedure update(t,c,l,r,d:longint);            inline;
begin
x[c]:=(t-d*l+n) mod n; y[c]:=r-l;
end;

procedure change(c:longint);                    inline;
begin
end;

function area(p,x1,y1,x2,y2:longint):longint;   inline;
begin
area:=sum(p,x2,y2)+sum(p,x1-1,y1-1)-sum(p,x1-1,y2)-sum(p,x2,y1-1);
end;

var d:longint;
begin
d:=longint(r=len);
end;

begin
for i:=1 to q do
begin
case p of
end;
end;
end.

转载于:https://www.cnblogs.com/logichandsome/p/4054656.html
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