# [情人节专属]纯JS脚本1k大小的3D玫瑰

#### 发表于2012-02-09 13:04| 次阅读| 来源romancortes.com| 0 条评论| 作者赵红编译

3D玫瑰花的实现代码如下：

 with(m=Math)C=cos,S=sin,P=pow,R=random;c.width=c.height=f=500;h=-250;function p(a,b,c){if(c>60)return[S(a*7)*(13+5/(.2+P(b*4,4)))-S(b)*50,b*f+50,625+C(a*7)*(13+5/(.2+P(b*4,4)))+b*400,a*1-b/2,a];A=a*2-1;B=b*2-1;if(A*A+B*B<1){if(c>37){n=(j=c&1)?6:4;o=.5/(a+.01)+C(b*125)*3-a*300;w=b*h;return[o*C(n)+w*S(n)+j*610-390,o*S(n)-w*C(n)+550-j*350,1180+C(B+A)*99-j*300,.4-a*.1+P(1-B*B,-h*6)*.15-a*b*.4+C(a+b)/5+P(C((o*(a+1)+(B>0?w:-w))/25),30)*.1*(1-B*B),o/1e3+.7-o*w*3e-6]}if(c>32){c=c*1.16-.15;o=a*45-20;w=b*b*h;z=o*S(c)+w*C(c)+620;return[o*C(c)-w*S(c),28+C(B*.5)*99-b*b*b*60-z/2-h,z,(b*b*.3+P((1-(A*A)),7)*.15+.3)*b,b*.7]}o=A*(2-b)*(80-c*2);w=99-C(A)*120-C(b)*(-h-c*4.9)+C(P(1-b,7))*50+c*2;z=o*S(c)+w*C(c)+700;return[o*C(c)-w*S(c),B*99-C(P(b, 7))*50-c/3-z/1.35+450,z,(1-b/1.2)*.9+a*.1, P((1-b),20)/4+.05]}}setInterval('for(i=0;i<1e4;i++)if(s=p(R(),R(),i%46/.74)){z=s[2];x=~~(s[0]*f/z-h);y=~~(s[1]*f/z-h);if(!m[q=y*f+x]|m[q]>z)m[q]=z,a.fillStyle="rgb("+~(s[3]*h)+","+~(s[4]*h)+","+~(s[3]*s[3]*-80)+")",a.fillRect(x,y,1,1)}',0)

 function surface(a, b) { // I'm using a and b as parameters ranging from 0 to 1. return { x: a*50, y: b*50 }; // this surface will be a square of 50x50 units of size }

 var canvas = document.body.appendChild(document.createElement("canvas")), context = canvas.getContext("2d"), a, b, position; // Now I'm going to sample the surface at .1 intervals for a and b parameters: for (a = 0; a < 1; a += .1) { for (b = 0; b < 1; b += .1) { position = surface(a, b); context.fillRect(position.x, position.y, 1, 1); } }

 function surface(a, b) { var x = a * 100, y = b * 100, radius = 50, x0 = 50, y0 = 50; if ((x - x0) * (x - x0) + (y - y0) * (y - y0) < radius * radius) { // inside the circle return { x: x, y: y }; } else { // outside the circle return null; } }

 if (position = surface(a, b)) { context.fillRect(position.x, position.y, 1, 1); }

 function surface(a, b) { // Circle using polar coordinates var angle = a * Math.PI * 2, radius = 50, x0 = 50, y0 = 50; return { x: Math.cos(angle) * radius * b + x0, y: Math.sin(angle) * radius * b + y0 }; }

（此方法相比前一个方法需要密集采样以进行填充。）

 function surface(a, b) { var x = a * 100, y = b * 100, radius = 50, x0 = 50, y0 = 50; if ((x - x0) * (x - x0) + (y - y0) * (y - y0) < radius * radius) { return { x: x, y: y * (1 + b) / 2 // deformation }; } else { return null; } }

 function surface(a, b) { var x = a * 100, y = b * 100, radius = 50, x0 = 50, y0 = 50; if ((x - x0) * (x - x0) + (y - y0) * (y - y0) < radius * radius) { return { x: x, y: y * (1 + b) / 2, r: 100 + Math.floor((1 - b) * 155), // this will add a gradient g: 50, b: 50 }; } else { return null; } } for (a = 0; a < 1; a += .01) { for (b = 0; b < 1; b += .001) { if (point = surface(a, b)) { context.fillStyle = "rgb(" + point.r + "," + point.g + "," + point.b + ")"; context.fillRect(point.x, point.y, 1, 1); } } }

3D曲面和透视投影

 function surface(a, b) { var angle = a * Math.PI * 2, radius = 100, length = 400; return { x: Math.cos(angle) * radius, y: Math.sin(angle) * radius, z: b * length - length / 2, // by subtracting length/2 I have centered the tube at (0, 0, 0) r: 0, g: Math.floor(b * 255), b: 0 }; }

 var pX, pY, // projected on canvas x and y coordinates perspective = 350, halfHeight = canvas.height / 2, halfWidth = canvas.width / 2, cameraZ = -700; for (a = 0; a < 1; a += .001) { for (b = 0; b < 1; b += .01) { if (point = surface(a, b)) { pX = (point.x * perspective) / (point.z - cameraZ) + halfWidth; pY = (point.y * perspective) / (point.z - cameraZ) + halfHeight; context.fillStyle = "rgb(" + point.r + "," + point.g + "," + point.b + ")"; context.fillRect(pX, pY, 1, 1); } } }

z-buffer

z-buffer在计算机图形学中是一个相当普遍的技术，在为物件进行着色时，执行“隐藏面消除”工作，使隐藏物件背后的部分就不会被显示出来。

 var zBuffer = [], zBufferIndex; for (a = 0; a < 1; a += .001) { for (b = 0; b < 1; b += .01) { if (point = surface(a, b)) { pX = Math.floor((point.x * perspective) / (point.z - cameraZ) + halfWidth); pY = Math.floor((point.y * perspective) / (point.z - cameraZ) + halfHeight); zBufferIndex = pY * canvas.width + pX; if ((typeof zBuffer[zBufferIndex] === "undefined") || (point.z < zBuffer[zBufferIndex])) { zBuffer[zBufferIndex] = point.z; context.fillStyle = "rgb(" + point.r + "," + point.g + "," + point.b + ")"; context.fillRect(pX, pY, 1, 1); } } } }

 function surface(a, b) { var angle = a * Math.PI * 2, radius = 100, length = 400, x = Math.cos(angle) * radius, y = Math.sin(angle) * radius, z = b * length - length / 2, yAxisRotationAngle = -.4, // in radians! rotatedX = x * Math.cos(yAxisRotationAngle) + z * Math.sin(yAxisRotationAngle), rotatedZ = x * -Math.sin(yAxisRotationAngle) + z * Math.cos(yAxisRotationAngle); return { x: rotatedX, y: y, z: rotatedZ, r: 0, g: Math.floor(b * 255), b: 0 }; }

 var i; window.setInterval(function () { for (i = 0; i < 10000; i++) { if (point = surface(Math.random(), Math.random())) { pX = Math.floor((point.x * perspective) / (point.z - cameraZ) + halfWidth); pY = Math.floor((point.y * perspective) / (point.z - cameraZ) + halfHeight); zBufferIndex = pY * canvas.width + pX; if ((typeof zBuffer[zBufferIndex] === "undefined") || (point.z < zBuffer[zBufferIndex])) { zBuffer[zBufferIndex] = point.z; context.fillStyle = "rgb(" + point.r + "," + point.g + "," + point.b + ")"; context.fillRect(pX, pY, 1, 1); } } } }, 0);

[情人节专属]纯JS脚本1k大小的3D玫瑰
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